Question Number 224249 by mnjuly1970 last updated on 29/Aug/25 Commented by mnjuly1970 last updated on 29/Aug/25 $${please}\:{prove}\:\:\underline{\underbrace{\lesseqgtr}} \\ $$ Commented by mr W last updated…
Question Number 224246 by mr W last updated on 28/Aug/25 Commented by mr W last updated on 28/Aug/25 $${find}\:{the}\:{area}\:{of}\:{hexagon}. \\ $$ Answered by A5T last…
Question Number 224168 by mr W last updated on 23/Aug/25 Commented by mr W last updated on 23/Aug/25 $${find}\:{the}\:{shaded}\:{area}. \\ $$ Answered by fantastic last…
Question Number 224108 by MirHasibulHossain last updated on 21/Aug/25 Answered by mr W last updated on 21/Aug/25 $${i}\:{think}\:{if}\:{the}\:{three}\:{big}\:{blue}\:{circles}\: \\ $$$${have}\:{different}\:{radii}\:{a}_{\mathrm{1}} ,\:{a}_{\mathrm{2}} ,\:{a}_{\mathrm{3}} ,\: \\ $$$${generally}\:{we}\:{have}…
Question Number 224013 by efronzo1 last updated on 14/Aug/25 Commented by efronzo1 last updated on 14/Aug/25 $$\mathrm{Given}\:\mathrm{AB}\:\mathrm{is}\:\mathrm{diameter}\:,\:\angle\mathrm{AOD}=\mathrm{22}° \\ $$$$\:\mathrm{and}\:\angle\mathrm{BCD}=\:\mathrm{p}°. \\ $$$$\:\mathrm{Find}\:\mathrm{p}. \\ $$ Answered by…
Question Number 224003 by mr W last updated on 13/Aug/25 Commented by mr W last updated on 13/Aug/25 $${the}\:{areas}\:{of}\:{two}\:{equilaterals}\:{are} \\ $$$${known}.\:{find}\:{the}\:{area}\:{of}\:{the}\:{third} \\ $$$${triangle}. \\ $$…
Question Number 223962 by behi834171 last updated on 11/Aug/25 Commented by behi834171 last updated on 11/Aug/25 $$\boldsymbol{{Area}}\:\boldsymbol{{of}}\:\boldsymbol{{circles}}: \\ $$$$\begin{cases}{\boldsymbol{{yellow}}=\mathrm{1}}\\{\boldsymbol{{blue}}=\sqrt{\mathrm{2}}}\\{\boldsymbol{{green}}=\sqrt{\mathrm{3}}}\end{cases}\:\:\:\:\:\:\left(\boldsymbol{{any}}\:\boldsymbol{{unit}}\right)^{\mathrm{2}} \\ $$$$\boldsymbol{{Area}}\:\boldsymbol{{of}}\:\boldsymbol{{gray}}\left(\boldsymbol{{big}}\right)\:\:\boldsymbol{{circle}}=? \\ $$$$ \\ $$$$\boldsymbol{{circles}}\:\boldsymbol{{and}}\:\boldsymbol{{lines}}\:\boldsymbol{{are}}\:\boldsymbol{{tangent}}\:\boldsymbol{{to}}…
Question Number 223908 by yerlow3 last updated on 09/Aug/25 Answered by dionigi last updated on 10/Aug/25 $$ \\ $$$${ABCD}\:{should}\:{be}\:{a}\:{regular}\:{hemi}−{hexagon} \\ $$$${r}\:=\:{PA}\:=\:{PB}\:=\:{PC}\:=\:{PD} \\ $$$${r}\:=\:{DA}\:=\:{AB}\:=\:{BC} \\ $$$${and}\:{P}\:{the}\:{center}\:{of}\:{thr}\:{circle}…
Question Number 223901 by mr W last updated on 08/Aug/25 Commented by mr W last updated on 08/Aug/25 $${find}\:{the}\:{area}\:{of}\:{circle}. \\ $$ Commented by Hamada1969 last…
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