Question Number 207230 by mr W last updated on 10/May/24 Answered by mr W last updated on 10/May/24 Commented by mr W last updated on…
Question Number 207184 by cherokeesay last updated on 08/May/24 Answered by Ismoiljon_008 last updated on 08/May/24 $$\:\:\:\frac{\mathrm{5}}{\mathrm{24}} \\ $$ Answered by mr W last updated…
Question Number 207035 by mr W last updated on 04/May/24 Answered by A5T last updated on 04/May/24 $${BE}=\sqrt{\mathrm{6}^{\mathrm{2}} +\mathrm{2}^{\mathrm{2}} }=\mathrm{2}\sqrt{\mathrm{10}}\Rightarrow{EF}={FB}=\sqrt{\mathrm{10}} \\ $$$${Let}\:{the}\:{line}\:{through}\:{F}\:{parallel}\:{to}\:{BC}\:{meet}\:{AB},{DC} \\ $$$${at}\:{H},{I}\:{resp}.,{then}\:{BH}=\mathrm{3}={DI};\:{FH}=\mathrm{1} \\…
Question Number 207018 by cherokeesay last updated on 03/May/24 Answered by mr W last updated on 03/May/24 Commented by cherokeesay last updated on 03/May/24 $${R}=?…
Question Number 207008 by mr W last updated on 03/May/24 Answered by A5T last updated on 03/May/24 Commented by A5T last updated on 03/May/24 $$\frac{\mathrm{5}}{{BO}}=\frac{\mathrm{6}}{{CO}}\Rightarrow\frac{{BO}}{{CO}}=\frac{\mathrm{5}}{\mathrm{6}};\:{BO}=\mathrm{5}{x};{CO}=\mathrm{6}{x}…
Question Number 206956 by mr W last updated on 01/May/24 Commented by mr W last updated on 01/May/24 $${find}\:{the}\:{radius}\:{of}\:{circle}. \\ $$ Answered by Frix last…
Question Number 206937 by efronzo1 last updated on 01/May/24 Answered by A5T last updated on 01/May/24 Commented by A5T last updated on 01/May/24 $$\mathrm{8}×\mathrm{14}={x}\left({x}+\mathrm{2}{r}\right)={x}^{\mathrm{2}} +\mathrm{2}{rx}=\mathrm{112}…
Question Number 206923 by Amidip last updated on 01/May/24 $$ \\ $$$$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 206885 by efronzo1 last updated on 29/Apr/24 Answered by BaliramKumar last updated on 29/Apr/24 $${x}\:=\:\mathrm{tan}^{−\mathrm{1}} \left(\frac{\mathrm{5}}{\mathrm{8}}\right)\:\approx\:\mathrm{32}° \\ $$ Answered by Rasheed.Sindhi last updated…
Question Number 206806 by Frix last updated on 26/Apr/24 $$\mathrm{Given}\:\mathrm{is}\:\mathrm{a}\:\mathrm{square}\:\mathrm{with}\:\mathrm{side}\:\mathrm{length}\:\mathrm{15}. \\ $$$$\mathrm{We}\:\mathrm{need}\:\mathrm{to}\:\mathrm{find}\:\mathrm{exactly}\:\mathrm{17}\:\mathrm{smaller}\:\mathrm{squares} \\ $$$$\mathrm{to}\:\mathrm{fill}\:\mathrm{the}\:\mathrm{big}\:\mathrm{one}.\:\mathrm{How}\:\mathrm{many}\:\mathrm{solutions}\:\mathrm{are} \\ $$$$\mathrm{possible}? \\ $$$$\left(\mathrm{Note}:\:\mathrm{it}'\mathrm{s}\:\mathrm{not}\:\mathrm{enough}\:\mathrm{to}\:\mathrm{find}\:\mathrm{squares}\:\mathrm{with}\right. \\ $$$$\mathrm{the}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{their}\:\mathrm{areas}\:\mathrm{being}\:\mathrm{225},\:\mathrm{they}\:\mathrm{must} \\ $$$$\mathrm{fit}\:\mathrm{into}\:\mathrm{the}\:\mathrm{15}×\mathrm{15}\:\mathrm{square}.\:\mathrm{Example}\:\mathrm{with} \\ $$$$\mathrm{3}\:\mathrm{squares}:\:\mathrm{2}×\mathrm{2}+\mathrm{5}×\mathrm{5}+\mathrm{14}×\mathrm{14}=\mathrm{225}\:\mathrm{but} \\…