Question Number 204873 by necx122 last updated on 29/Feb/24 $${The}\:{figure}\:{below}\:{represents}\:{a}\:{design} \\ $$$${on}\:{the}\:{windows}\:{of}\:{a}\:{building}.\:{The} \\ $$$${curved}\:{part}\:{XY}\:{is}\:{an}\:{arc}\:{of}\:{a}\:{circle}. \\ $$$${The}\:{rise}\:{of}\:{the}\:{segmental}\:{arc}\:{is}\:\mathrm{10}{cm}, \\ $$$${its}\:{span}\:{is}\:\mathrm{100}{cm}\:{and}\:{XZ}={ZY}=\mathrm{120}{cm}. \\ $$$${calculate}: \\ $$$$\left({i}\right)\:{the}\:{radius}\:{of}\:{the}\:{circle} \\ $$$$\left({ii}\right)\:{the}\:{area}\:{of}\:{the}\:{segmental}\:{cap}, \\…
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Question Number 204541 by necx122 last updated on 21/Feb/24 $${In}\:{a}\:{regular}\:{pentagon}\:{PQRST}\:,\:{PR} \\ $$$${intersects}\:{QS}\:{at}\:{O}.\:{Calculate}\:{ROS}? \\ $$ Commented by som(math1967) last updated on 21/Feb/24 $$\measuredangle{ROS}=\mathrm{72}° \\ $$ Commented…
Question Number 204560 by mr W last updated on 21/Feb/24 Commented by mr W last updated on 21/Feb/24 $${AC}={BD} \\ $$$${find}\:\angle{B}=? \\ $$ Answered by…
Question Number 204521 by explorerapollo last updated on 20/Feb/24 Commented by TonyCWX08 last updated on 20/Feb/24 $${I}\:{don}'{t}\:{understand}\:{your}\:{request}\:{here}. \\ $$ Answered by mr W last updated…
Question Number 204505 by cherokeesay last updated on 19/Feb/24 Answered by mr W last updated on 19/Feb/24 $$\left[\sqrt{\left(\mathrm{2}−{r}\right)^{\mathrm{2}} −{r}^{\mathrm{2}} }−\mathrm{1}\right]^{\mathrm{2}} +\left(\mathrm{1}−{r}\right)^{\mathrm{2}} ={r}^{\mathrm{2}} \\ $$$$\left[\mathrm{2}\sqrt{\mathrm{1}−{r}}−\mathrm{1}\right]^{\mathrm{2}} =\mathrm{2}{r}−\mathrm{1}…
Question Number 204433 by emilagazade last updated on 17/Feb/24 Commented by emilagazade last updated on 17/Feb/24 $${find}\:{max}\:{value}\:{for}\:\mid{DB}\mid+\mid{BC}\mid \\ $$ Answered by deleteduser1 last updated on…
Question Number 204374 by mr W last updated on 14/Feb/24 Commented by mr W last updated on 15/Feb/24 $${The}\:{radius}\:{of}\:{the}\:{big}\:{sphere}\:\left({say}\:\right. \\ $$$$\left.{the}\:{Earth}\right)\:{is}\:{R}\:{and}\:{the}\:{radius}\:{of} \\ $$$${the}\:{small}\:{sphere}\:\left({say}\:{theMoon}\right)\:{is}\:{r}. \\ $$$${find}\:{the}\:{maximum}\:{area}\:{of}\:{the}…
Question Number 204310 by BaliramKumar last updated on 12/Feb/24 Answered by mr W last updated on 12/Feb/24 Commented by mr W last updated on 12/Feb/24…
Question Number 204197 by ajfour last updated on 08/Feb/24 Answered by mr W last updated on 08/Feb/24 $$\mathrm{sin}\:\frac{\theta}{\mathrm{2}}=\frac{{a}}{{R}−{a}} \\ $$$${OC}={OB}+{BC} \\ $$$$\frac{{R}}{\mathrm{cos}\:\theta}=\sqrt{\left({R}+\mathrm{1}\right)^{\mathrm{2}} −\mathrm{1}^{\mathrm{2}} }+\frac{\mathrm{1}}{\mathrm{tan}\:\left(\frac{\frac{\pi}{\mathrm{2}}−\theta}{\mathrm{2}}\right)} \\…