Question Number 204171 by cherokeesay last updated on 07/Feb/24 Commented by AST last updated on 07/Feb/24 $${Are}\:{those}\:{points}\:{on}\:{the}\:{circle}\:{the}\:{vertices}\:{of}\:{a} \\ $$$${regular}\:{hexagon}?\:{Is}\:{H}\:{the}\:{midpoint}\:{of}\:\Gamma\:{and}\:{A}? \\ $$ Answered by AST last…
Question Number 203969 by mr W last updated on 03/Feb/24 Answered by Rasheed.Sindhi last updated on 03/Feb/24 $$?={x} \\ $$$$\bigtriangleup\mathrm{ABC}\sim\bigtriangleup\mathrm{ADE} \\ $$$$\frac{\mathrm{3}}{{r}}=\frac{\mathrm{4}}{\mathrm{4}−{r}}=\frac{\mathrm{5}}{{x}+{r}}\Rightarrow\mathrm{4}{r}=\mathrm{12}−\mathrm{3}{r}\Rightarrow{r}=\frac{\mathrm{12}}{\mathrm{7}} \\ $$$$\frac{\mathrm{3}}{{r}}=\frac{\mathrm{5}}{{x}+{r}}\Rightarrow\frac{\mathrm{3}}{\frac{\mathrm{12}}{\mathrm{7}}}=\frac{\mathrm{5}}{{x}+\frac{\mathrm{12}}{\mathrm{7}}} \\…
Question Number 203803 by ajfour last updated on 28/Jan/24 Answered by ajfour last updated on 28/Jan/24 $$\mathrm{2}{s}^{\mathrm{2}} =\left({b}^{\mathrm{2}} +{c}^{\mathrm{2}} \right)−\left(\frac{{h}−{k}}{{h}+{k}}\right)\left({b}^{\mathrm{2}} −{c}^{\mathrm{2}} \right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:−\frac{\mathrm{2}{hk}}{\left({h}+{k}\right)^{\mathrm{2}} }\left({a}^{\mathrm{2}}…
Question Number 203778 by mr W last updated on 27/Jan/24 Answered by mr W last updated on 27/Jan/24 Commented by mr W last updated on…
Question Number 203613 by mr W last updated on 23/Jan/24 Commented by mr W last updated on 23/Jan/24 $${find}\:\frac{{R}}{{r}}=? \\ $$ Commented by esmaeil last…
Question Number 203569 by cherokeesay last updated on 22/Jan/24 Commented by a.lgnaoui last updated on 22/Jan/24 $$\mathrm{2}\left(\mathrm{a}+\mathrm{b}+\mathrm{c}+\mathrm{d}\right)=\mathrm{360} \\ $$$$\:\:\left(\mathrm{a}+\mathrm{b}+\mathrm{c}+\mathrm{d}\right)=\mathrm{180} \\ $$$$\:\:\left(\mathrm{a}+\mathrm{b}\right)=\mathrm{180}−\left(\mathrm{c}+\mathrm{d}\right) \\ $$$$ \\ $$$$\:\:\:\:\mathrm{tan}\:\left(\boldsymbol{\mathrm{a}}+\boldsymbol{\mathrm{b}}\right)=−\mathrm{tan}\:\left(\boldsymbol{\mathrm{c}}+\boldsymbol{\mathrm{d}}\right)…
Question Number 203602 by mr W last updated on 22/Jan/24 Answered by mr W last updated on 23/Jan/24 Commented by mr W last updated on…
Question Number 203557 by ajfour last updated on 21/Jan/24 Commented by ajfour last updated on 21/Jan/24 $${Find}\:{maimum}\:{blue}\:{shaded}\:{area}. \\ $$ Answered by mr W last updated…
Question Number 203480 by mr W last updated on 20/Jan/24 Commented by mr W last updated on 20/Jan/24 $${is}\:{it}\:{possible}\:{that}\:{the}\:{red}\:{lines}\:{divide} \\ $$$${the}\:{square}\:{into}\:\mathrm{4}\:{parts}\:{with}\:{given}\: \\ $$$${areas}?\:{if}\:{yes},\:{find}\:{the}\:{length}\:{of}\:{the} \\ $$$${red}\:{lines}.…
Question Number 203401 by cherokeesay last updated on 18/Jan/24 Answered by MM42 last updated on 18/Jan/24 $$<{B}=\mathrm{30}^{{o}} \\ $$$${AB}=\mathrm{2}\sqrt{\mathrm{3}}×{cos}\mathrm{30}=\mathrm{3} \\ $$$${R}=\sqrt{\mathrm{21}} \\ $$$${EC}=\mathrm{2}\sqrt{\mathrm{3}}×{cos}\mathrm{60}=\sqrt{\mathrm{3}} \\ $$$${r}=\sqrt{\mathrm{3}}×{tan}\mathrm{30}\Rightarrow{r}=\mathrm{1}…