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Category: Geometry

Question-203269

Question Number 203269 by ahmetgg last updated on 13/Jan/24 Answered by esmaeil last updated on 13/Jan/24 $${tan}\mathrm{10}=\frac{{AH}}{{BH}} \\ $$$${tan}\mathrm{20}=\frac{{HC}}{{BH}}\rightarrow\frac{{HC}}{{AH}}\approx\mathrm{2}.\mathrm{0642} \\ $$$${tan}\mathrm{50}=\frac{{OH}}{{AH}} \\ $$$${tanx}=\frac{{OH}}{{CH}}\rightarrow\frac{{tan}\mathrm{50}}{{tanx}}\approx\mathrm{2}.\mathrm{0642}\rightarrow \\ $$$${x}={tan}^{−\mathrm{1}}…

Question-203187

Question Number 203187 by Amidip last updated on 12/Jan/24 Answered by mr W last updated on 12/Jan/24 $${supposed}:\:{AB}\bot{AC},\:{AD}\bot{BC} \\ $$$$\frac{\mathrm{45}}{{x}}=\frac{{x}+\mathrm{48}}{\mathrm{45}}\: \\ $$$$\Rightarrow{x}^{\mathrm{2}} +\mathrm{48}{x}−\mathrm{45}^{\mathrm{2}} =\mathrm{0} \\…

Question-203211

Question Number 203211 by ajfour last updated on 12/Jan/24 Answered by MM42 last updated on 12/Jan/24 $${p}^{\mathrm{2}} =\mathrm{2}−\mathrm{2}{cosa} \\ $$$${q}^{\mathrm{2}} =\mathrm{2}−\mathrm{2}{sina} \\ $$$$\Rightarrow\left({p}^{\mathrm{2}} −\mathrm{2}\right)^{\mathrm{2}} +\left({q}^{\mathrm{2}}…