Question Number 223865 by ajfour last updated on 07/Aug/25 Commented by ajfour last updated on 07/Aug/25 $${Contrary}\:{to}\:{diagram}\:{labelling},\:{lets} \\ $$$${have}\:{a}=\mathrm{1},\:{b}={b}.\:\angle{CAE}=\pi/\mathrm{6}. \\ $$$${If}\:{APC}\:{is}\:{a}\:{straight}\:{line},\:{P}\:{being}\:{a} \\ $$$${point}\:{of}\:{tangency},\:{then}\:{find}\:{b},\:{r},\:{R}. \\ $$…
Question Number 223836 by Tawa11 last updated on 06/Aug/25 Answered by som(math1967) last updated on 06/Aug/25 $$\bigtriangleup{ABG}\sim\bigtriangleup{HFG} \\ $$$${let}\:{AB}={x} \\ $$$$\:\:\therefore\frac{{x}}{{x}+\mathrm{105}}=\frac{{x}−\mathrm{112}}{{x}−\mathrm{105}} \\ $$$$\Rightarrow{x}^{\mathrm{2}} −\mathrm{112}{x}+\mathrm{105}{x}−\mathrm{112}×\mathrm{105} \\…
Question Number 223826 by mr W last updated on 06/Aug/25 Commented by mr W last updated on 06/Aug/25 $${find}\:{the}\:{green}\:{area}\:{in}\:{the}\:{trapezoid}. \\ $$ Answered by mehdee7396 last…
Question Number 223812 by mr W last updated on 05/Aug/25 Commented by mr W last updated on 05/Aug/25 $${find}\:{the}\:{green}\:{area}\:{in}\:{the}\:{trapezoid}. \\ $$ Answered by HeferH24 last…
Question Number 223783 by mr W last updated on 04/Aug/25 Commented by mr W last updated on 04/Aug/25 $${find}\:{shaded}\:{area}\:{in}\:{rectangle}. \\ $$ Answered by fantastic last…
Question Number 223659 by yerlow last updated on 01/Aug/25 Commented by yerlow last updated on 01/Aug/25 $$\mathrm{Solve}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\varepsilon. \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 223619 by Tawa11 last updated on 01/Aug/25 Answered by Frix last updated on 01/Aug/25 $$\mid{C}_{\mathrm{1}} {C}_{\mathrm{2}} \mid=\sqrt{\mathrm{2}} \\ $$$$\Rightarrow\:{C}_{\mathrm{1}} ,\:{C}_{\mathrm{2}} \:\mathrm{form}\:\mathrm{a}\:\mathrm{triangle}\:\mathrm{with}\:\mathrm{each}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{intersection}\:\mathrm{points}\:\mathrm{with}…
Question Number 223595 by ajfour last updated on 31/Jul/25 Commented by ajfour last updated on 31/Jul/25 $$\:\:\:\:\:\:\:\:\:\:{Given}\:\theta.\:{Find}\:\phi. \\ $$ Answered by mr W last updated…
Question Number 223544 by ajfour last updated on 29/Jul/25 Commented by ajfour last updated on 29/Jul/25 $${If}\:\mathrm{2}{R}\theta=\mathrm{2}\pi{r},\:{find}\:{R}/{r}\:{for}\:{h}=\mathrm{0}. \\ $$ Answered by mr W last updated…
Question Number 223523 by Nicholas666 last updated on 27/Jul/25 Commented by Nicholas666 last updated on 27/Jul/25 $$\:\:\boldsymbol{\mathrm{how}}\:\boldsymbol{\mathrm{to}}\:\boldsymbol{\mathrm{prove}}\:\boldsymbol{\mathrm{this}}\:\boldsymbol{\mathrm{problem}}\:?\: \\ $$$$ \\ $$ Terms of Service Privacy…