Category: Geometry

Question Number 202001 by necx122 last updated on 18/Dec/23 $${If}\:{a}\:{circle}\:{of}\:{radius}\:{r}\:{is}\:{inscribed}\:{in} \\ $$$${a}\:{triangl}\:{ABC}.\:{Express}\:{r}\:{in}\:{terms}\:{of} \\ $$$${a},{b}\:{and}\:{c}\:{only} \\ $$ Answered by AST last updated on 18/Dec/23 $${r}=\frac{\sqrt{{s}\left({s}−{a}\right)\left({s}−{b}\right)\left({s}−{c}\right)}}{{s}}\:{where}\:{s}=\frac{{a}+{b}+{c}}{\mathrm{2}} \\…

Question Number 201994 by Mingma last updated on 18/Dec/23 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 201914 by Anonim_X last updated on 15/Dec/23 Commented by mr W last updated on 16/Dec/23 $${see}\:{Q}\mathrm{198828} \\ $$ Terms of Service Privacy Policy…

Question Number 201907 by mnjuly1970 last updated on 15/Dec/23 Answered by Rasheed.Sindhi last updated on 15/Dec/23 $$\bullet{Radius}\:{of}\:{Semi}-{circle}\:{R}=\:\frac{\mathrm{10}}{\mathrm{2}}=\mathrm{5}\:{cm} \\ $$$$\bullet{let}\:{radous}\:{of}\:{greater}\:{quarter}-{circle}={r}_{\mathrm{1}} \\ $$$$\left({R}+{r}_{\mathrm{1}} \right)^{\mathrm{2}} =\mathrm{10}^{\mathrm{2}} +\mathrm{5}^{\mathrm{2}} =\mathrm{125}…

Question Number 201790 by ajfour last updated on 12/Dec/23 Commented by ajfour last updated on 12/Dec/23 $${Can}\:{we}\:{find}\:{sides}\:{of}\:\Box{PQRS}\:\:{in} \\ $$$${terms}\:{of}\:{a},{b},{c}\:? \\ $$ Answered by a.lgnaoui last…