Question Number 198421 by mr W last updated on 19/Oct/23 Commented by mr W last updated on 19/Oct/23 $${given}\:{that}\:{the}\:{midpoints}\:{of}\:{the}\:{sides} \\ $$$${of}\:{a}\:{convex}\:{quadrilaterial}\:{are} \\ $$$${concyclic}.\:{if}\:{the}\:{lengthes}\:{of}\:{three}\:{of} \\ $$$${its}\:{sides}\:{are}\:{a},\:{b},\:{c}\:{respectively},\:{find}…
Question Number 198391 by mr W last updated on 19/Oct/23 Commented by mr W last updated on 19/Oct/23 $${prove}\:{that}\:{BE}\:{is}\:{bisector}\:{of}\:\angle{CBD}. \\ $$$$\left({B},\:{E}\:{are}\:{touching}\:{points}\right) \\ $$ Answered by…
Question Number 198235 by MASANJAJJ last updated on 15/Oct/23 Answered by Rasheed.Sindhi last updated on 15/Oct/23 $${y}={m}\angle{B}\:\:\:\:\:\:\:\left[{Corresponding}\:{angles}\right] \\ $$$${x}={m}\angle{A}\:\:\:\:\:\:\left[{Alternative}\:{angles}\right] \\ $$$${z}={m}\angle{ACB}\:\:\:\left[{Same}\:{angles}\right] \\ $$$${x}+{y}+{z}={m}\angle{A}+{m}\angle{B}+{m}\angle{ACB}=\mathrm{180}°\:\left[{Angles}\:{of}\:{triangle}\right] \\ $$$$…
Question Number 198158 by mnjuly1970 last updated on 12/Oct/23 Answered by mr W last updated on 12/Oct/23 Commented by mr W last updated on 12/Oct/23…
Question Number 198054 by necx122 last updated on 09/Oct/23 $${In}\:\bigtriangleup{MNO},\:{MN}=\mathrm{6}{units},\:{MO}=\mathrm{4}\:{units} \\ $$$${and}\:{NO}=\mathrm{12}\:{units}.\:{If}\:{the}\:{bisector}\:{of}\:{the} \\ $$$${angle}\:{M}\:{meets}\:{NO}\:{at}\:{P},\:{calculate}\:{NP}. \\ $$ Commented by som(math1967) last updated on 09/Oct/23 $${But}\:{MN}+{MO}=\mathrm{10} \\…
Question Number 198025 by mr W last updated on 08/Oct/23 Commented by mr W last updated on 08/Oct/23 $${prove}\:{PQ}={RS} \\ $$ Answered by mahdipoor last…
Question Number 197989 by mr W last updated on 07/Oct/23 Commented by mr W last updated on 07/Oct/23 $$\left[\underline{{old}\:{question}\:{from}\:{ajfour}\:{sir}}\right] \\ $$$$\mathrm{3}\:{circles}\:{with}\:{radii}\:{p},\:{q},\:{r}\:{respectively} \\ $$$${touch}\:{each}\:{other}\:{as}\:{shown}.\:{find}\:{the}\: \\ $$$${maximum}\:{area}\:{of}\:\:{triangle}\:\Delta{ABC}…
Question Number 197970 by mr W last updated on 06/Oct/23 Answered by Frix last updated on 07/Oct/23 $${r}_{\mathrm{1}} =\mathrm{4} \\ $$$${r}_{\mathrm{2}} =\mathrm{2} \\ $$$${r}_{\mathrm{3}} =\mathrm{1}…
Question Number 197920 by cortano12 last updated on 04/Oct/23 Commented by cortano12 last updated on 04/Oct/23 $$\mathrm{if}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{shaded}\:\mathrm{is}\:\mathrm{320}\:\mathrm{cm}^{\mathrm{2}} \\ $$$$\mathrm{then}\:\mathrm{find}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{big}\:\mathrm{triangle}.\: \\ $$ Answered by Tokugami last…
Question Number 197680 by mr W last updated on 26/Sep/23 Commented by mr W last updated on 26/Sep/23 $${unsolved}\:{old}\:{question}\:{Q}#\mathrm{197245} \\ $$ Answered by mr W…