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Category: Geometry

Question-223449

Question Number 223449 by ajfour last updated on 25/Jul/25 Answered by ajfour last updated on 26/Jul/25 $$\:\:\:\sqrt{\mathrm{1}−\theta^{\mathrm{2}} }=\frac{\mathrm{sin}\:\left(\phi−\theta\right)}{\mathrm{sin}\:\phi} \\ $$$${Wow}!\:\:\:\:\:\:{arc}\:{CD}=\:{line}\:{AB} \\ $$$$ \\ $$$$\bullet\:{Find}\:{CT}/{AO}={t}/{R}\:\:{in}\:{terms}\:{of}\:\theta. \\…

Question-223301

Question Number 223301 by cemoosky last updated on 21/Jul/25 Answered by som(math1967) last updated on 21/Jul/25 $$\:\:\:{Ar}\:{of}\:{PQRK}=\mathrm{3}×\bigtriangleup{PSK} \\ $$$$\:{area}\:{of}\bigtriangleup{PSK}=\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{15sin}\:\mathrm{30}×\mathrm{15cos}\:\mathrm{30} \\ $$$$=\frac{\mathrm{1}}{\mathrm{2}}×\frac{\mathrm{225}\sqrt{\mathrm{3}}}{\mathrm{4}}{cm}^{\mathrm{2}} \\ $$$$\:{area}\:{of}\:{PQRK}=\mathrm{3}×\frac{\mathrm{1}}{\mathrm{2}}×\frac{\mathrm{225}\sqrt{\mathrm{3}}}{\mathrm{4}} \\ $$$$=\frac{\mathrm{675}\sqrt{\mathrm{3}}}{\mathrm{8}}{cm}^{\mathrm{2}}…

OC-4-5-amp-EF-2-amp-DE-EC-amp-AC-2AF-AB-

Question Number 223286 by mehdee7396 last updated on 20/Jul/25 $${OC}=\mathrm{4}.\mathrm{5}\:\:\:\&\:\:{EF}=\mathrm{2}\:\:\&\:\:{D}\overset{\frown} {{E}}={E}\overset{\frown} {{C}}\:\:\&\:\:{AC}=\mathrm{2}{AF}\Rightarrow{AB}=? \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\Downarrow\Downarrow\Downarrow \\ $$ Commented by fantastic last updated on 20/Jul/25 $$\mathrm{13}?? \\…

Question-223242

Question Number 223242 by mnjuly1970 last updated on 19/Jul/25 Answered by Tawa11 last updated on 19/Jul/25 $$\mathrm{Sir},\:\mathrm{did}\:\mathrm{you}\:\mathrm{hear}\:\mathrm{from}\:\:\:\:\:\mathrm{Mathdave}??? \\ $$$$\mathrm{Or}\:\mathrm{you}\:\mathrm{know}\:\mathrm{where}\:\mathrm{he}\:\mathrm{is}? \\ $$ Commented by mnjuly1970 last…