Question Number 54616 by cesar.marval.larez@gmail.com last updated on 07/Feb/19 Answered by tanmay.chaudhury50@gmail.com last updated on 08/Feb/19 $${a}={tanx}\:\:{da}={sec}^{\mathrm{2}} {xdx} \\ $$$$\int\frac{{a}^{\mathrm{2}} {da}}{\:\sqrt{\mathrm{2}+\mathrm{1}+{a}^{\mathrm{2}} }} \\ $$$$\int\frac{{a}^{\mathrm{2}} +\mathrm{3}−\mathrm{3}}{\:\sqrt{{a}^{\mathrm{2}}…
Question Number 185677 by Mingma last updated on 25/Jan/23 Answered by Frix last updated on 25/Jan/23 $$\frac{{df}}{{dx}}=\mathrm{e}^{\mid{x}\mid} −\mathrm{e}^{\mid{x}−\mathrm{2}\mid} =\mathrm{0}\:\Rightarrow\:{x}=\mathrm{1} \\ $$$${f}\left(\mathrm{1}\right)=\underset{\mathrm{0}} {\overset{\mathrm{2}} {\int}}\mathrm{e}^{\mid\mathrm{1}−{t}\mid} {dt}=\mathrm{2}\underset{\mathrm{0}} {\overset{\mathrm{1}}…
Question Number 54586 by arvinddayama00@gmail.com last updated on 07/Feb/19 $$\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }\:+\:\sqrt{\mathrm{1}−{y}^{\mathrm{2}} }\:=\:{a}\left({x}−{y}\right) \\ $$$${prove}\:{that} \\ $$$$\frac{{dy}}{{dx}}=\sqrt{\frac{\mathrm{1}−{y}^{\mathrm{2}} }{\mathrm{1}−{x}^{\mathrm{2}} }} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated…
Question Number 54585 by peter frank last updated on 07/Feb/19 $${show}\:{that}\:\int_{\mathrm{0}} ^{\infty} \frac{{x}}{\mathrm{1}+{x}^{\mathrm{6}} }{dx}=\frac{\pi}{\mathrm{3}\sqrt{\mathrm{3}}} \\ $$$$ \\ $$ Commented by maxmathsup by imad last updated…
Question Number 54573 by Abdo msup. last updated on 07/Feb/19 $${calculate}\:\int_{\mathrm{0}} ^{\infty} \:\:\:\frac{{cos}\left({e}^{−{x}^{\mathrm{2}} } \right)}{\mathrm{1}+{x}^{\mathrm{2}} }{dx}\: \\ $$ Commented by maxmathsup by imad last updated…
Question Number 120109 by mnjuly1970 last updated on 29/Oct/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 120102 by benjo_mathlover last updated on 29/Oct/20 $$\:\Theta\:=\:\int\:\frac{\mathrm{4}{x}^{−\mathrm{1}} +\mathrm{8}{x}^{−\mathrm{3}} }{{x}^{\mathrm{2}} \sqrt{{x}^{\mathrm{4}} +\mathrm{2}{x}^{\mathrm{2}} +\mathrm{2}}}\:{dx}\: \\ $$ Answered by mathmax by abdo last updated on…
Question Number 54556 by gunawan last updated on 06/Feb/19 $$\int_{−\mathrm{2}\pi^{\mathrm{2}} } ^{\mathrm{2}\pi^{\mathrm{2}} } \frac{\mathrm{sin}\:\left({x}^{\mathrm{2}} \right)}{{x}^{\mathrm{2}} }\:{dx} \\ $$ Commented by tanmay.chaudhury50@gmail.com last updated on 06/Feb/19…
Question Number 120064 by bemath last updated on 29/Oct/20 $${I}\:=\:\int\underset{\mathrm{0}} {\overset{\frac{\pi}{\mathrm{2}}} {\:}}\left(\frac{\mathrm{1}}{\mathrm{ln}\:\left(\mathrm{tan}\:{r}\right)}\:+\:\frac{\mathrm{1}}{\mathrm{1}−\mathrm{tan}\:{r}}\:\right)\:{dr} \\ $$ Answered by mnjuly1970 last updated on 29/Oct/20 $$\mathrm{I}\overset{\int_{{a}} ^{\:{b}} {f}\left({x}\right){dx}=\int_{{a}} ^{\:{b}}…
Question Number 54529 by tarun kunar last updated on 05/Feb/19 $$\int\mathrm{5cos}\:{x}−\mathrm{4sin}\:{x}/\mathrm{2cos}\:{x}+\mathrm{sin}\:{x}\:{dx} \\ $$ Commented by maxmathsup by imad last updated on 05/Feb/19 $${let}\:{I}\:=\int\:\frac{\mathrm{5}{cosx}−\mathrm{4}{sinx}}{\mathrm{2}{cosx}\:+{sinx}}{dx}\:\:{let}\:{use}\:{the}\:{changement}\:{tan}\left(\frac{{x}}{\mathrm{2}}\right)={t}\:\Rightarrow \\ $$$${I}\:=\int\:\:\frac{\frac{\mathrm{5}\left(\mathrm{1}−{t}^{\mathrm{2}}…