Question Number 111770 by mathmax by abdo last updated on 04/Sep/20 $$\mathrm{f}\:\mathrm{function}\:\mathrm{continue}\:\mathrm{on}\:\left[\mathrm{0},\mathrm{1}\right]\:\mathrm{find}\:\mathrm{lim}_{\mathrm{n}\rightarrow+\infty} \:\frac{\mathrm{1}}{\mathrm{n}}\sum_{\mathrm{k}=\mathrm{0}} ^{\mathrm{n}} \left(\mathrm{n}−\mathrm{k}\right)\int_{\frac{\mathrm{k}}{\mathrm{n}}} ^{\frac{\mathrm{k}+\mathrm{1}}{\mathrm{n}}} \mathrm{f}\left(\mathrm{x}\right)\mathrm{dx} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 111768 by mathmax by abdo last updated on 04/Sep/20 $$\mathrm{explicite}\:\mathrm{f}\left(\mathrm{x}\right)\:=\int_{\mathrm{0}} ^{\mathrm{2}\pi} \mathrm{ln}\left(\mathrm{x}^{\mathrm{2}} −\mathrm{2xcos}\theta\:+\mathrm{1}\right)\mathrm{d}\theta\:\:\:\:\:\:\:\:\left(\mathrm{x}\neq\overset{−} {+}\mathrm{1}\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 111762 by mathmax by abdo last updated on 04/Sep/20 $$\mathrm{caoculate}\:\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{4}}} \mathrm{ln}\left(\mathrm{1}+\mathrm{2tanx}\right)\mathrm{dx} \\ $$ Answered by mathmax by abdo last updated on 12/Sep/20…
Question Number 111760 by mathmax by abdo last updated on 04/Sep/20 $$\mathrm{find}\:\mathrm{lim}_{\mathrm{x}\rightarrow\mathrm{1}^{+} } \:\:\:\int_{\mathrm{x}} ^{\mathrm{x}^{\mathrm{2}} } \:\:\frac{\mathrm{ln}\left(\mathrm{t}\right)}{\left(\mathrm{t}−\mathrm{1}\right)^{\mathrm{2}} }\mathrm{dx} \\ $$ Terms of Service Privacy Policy…
Question Number 177296 by peter frank last updated on 03/Oct/22 $$\:\:\mathrm{Evaluate}\: \\ $$$$\int_{\mathrm{0}} ^{\pi} \frac{\mathrm{x}}{\mathrm{a}^{\mathrm{2}} \mathrm{cos}\:^{\mathrm{2}} \mathrm{x}+\mathrm{b}^{\mathrm{2}} \mathrm{sin}\:^{\mathrm{2}} \mathrm{x}}\mathrm{dx} \\ $$$$ \\ $$ Commented by…
Question Number 177298 by peter frank last updated on 03/Oct/22 $$\mathrm{Prove}\:\mathrm{that} \\ $$$$\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \frac{\mathrm{sin}\:^{\mathrm{2}} \mathrm{x}}{\left(\mathrm{sin}\:\mathrm{x}+\mathrm{cos}\:\mathrm{x}\right)}\mathrm{dx}=\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\mathrm{log}\:\left(\sqrt{\mathrm{2}}+\mathrm{1}\right) \\ $$ Answered by Ar Brandon last updated on…
Question Number 46225 by rahul 19 last updated on 22/Oct/18 Answered by MrW3 last updated on 23/Oct/18 $${let}\:{f}\left({x}\right)={a}\left({x}−{b}\right)^{\mathrm{2}} +{c} \\ $$$$\left({b}\right)\Rightarrow{b}=\mathrm{1},\:{c}=\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\left({a}\right)\Rightarrow{a}\left(\mathrm{0}−\mathrm{1}\right)^{\mathrm{2}} +\frac{\mathrm{1}}{\mathrm{2}}=\mathrm{0}\Rightarrow{a}=−\frac{\mathrm{1}}{\mathrm{2}} \\…
Question Number 111756 by mathmax by abdo last updated on 04/Sep/20 $$\mathrm{find}\:\mathrm{I}_{\mathrm{n}} =\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{4}}} \:\frac{\mathrm{du}}{\mathrm{cos}^{\mathrm{n}} \mathrm{u}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 46221 by Meritguide1234 last updated on 22/Oct/18 Answered by MJS last updated on 22/Oct/18 $$\mathrm{I}\:\mathrm{solved}\:\mathrm{it}\:\mathrm{but}\:\mathrm{I}'\mathrm{m}\:\mathrm{too}\:\mathrm{tired}\:\mathrm{to}\:\mathrm{type}\:\mathrm{it} \\ $$ Commented by Meritguide1234 last updated on…
Question Number 46188 by rahul 19 last updated on 22/Oct/18 $${Using}\:{dimensional}\:{analysis}\:, \\ $$$${find}\:{out}\:{value}\:{of}\:{n}\:{in}\:{given}\:{expression}: \\ $$$$\:\:\int\frac{{dx}}{\:\sqrt{\mathrm{2}{ax}−{x}^{\mathrm{2}} }}\:=\:{a}^{{n}} \mathrm{sin}^{−\mathrm{1}} \left(\frac{{x}}{{a}}\:−\mathrm{1}\right). \\ $$ Commented by rahul 19 last…