Question Number 86269 by M±th+et£s last updated on 27/Mar/20 $$\int\frac{{sec}^{\mathrm{2}} \left({x}\right)}{\left({tan}\left({x}\right)−\mathrm{1}\right)^{\mathrm{4}} \left({tan}\left({x}\right)−\mathrm{2}\right)}\:{dx} \\ $$ Commented by john santu last updated on 28/Mar/20 $${u}\:=\:\mathrm{tan}\:{x}−\mathrm{2}\: \\ $$$$\Rightarrow\:\int\:\frac{{du}}{\left({u}+\mathrm{1}\right)^{\mathrm{4}}…
Question Number 86258 by lémùst last updated on 27/Mar/20 $${calculate}\:{I}=\int_{\mathrm{1}} ^{+\infty} \frac{{x}^{\mathrm{2}} −\mathrm{1}}{{x}^{\mathrm{4}} −{x}^{\mathrm{2}} +\mathrm{1}}{dx} \\ $$ Commented by mathmax by abdo last updated on…
Question Number 86254 by sakeefhasan05@gmail.com last updated on 27/Mar/20 $$\int\:\sqrt{\mathrm{x}\sqrt{\mathrm{x}\sqrt{\mathrm{x}\sqrt{\mathrm{x}…….}}}}\:\:\:\mathrm{dx} \\ $$ Answered by TANMAY PANACEA. last updated on 27/Mar/20 $${y}=\sqrt{{x}\sqrt{{x}\sqrt{{x}\sqrt{{x}…\infty}\:\:\:}}} \\ $$$${y}=\sqrt{{xy}}\: \\ $$$${y}^{\mathrm{2}}…
Question Number 86246 by Rio Michael last updated on 27/Mar/20 $$\int\frac{{x}^{\mathrm{2}} −\mathrm{1}}{{x}^{\mathrm{2}} +\mathrm{1}}\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{1}\:+\:{x}^{\mathrm{4}} }}\:{dx}\:=\:? \\ $$ Answered by TANMAY PANACEA. last updated on 27/Mar/20 $$\int\frac{\mathrm{1}−\frac{\mathrm{1}}{{x}^{\mathrm{2}}…
Question Number 86247 by M±th+et£s last updated on 27/Mar/20 $$\int_{\mathrm{0}} ^{\mathrm{8}} \int_{\mathrm{0}} ^{{x}^{\frac{\mathrm{2}}{\mathrm{3}}} } \:\sqrt{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} +\mathrm{1}}\:{dy}\:{dx} \\ $$ Commented by mathmax by abdo last…
Question Number 151780 by Tawa11 last updated on 23/Aug/21 Answered by puissant last updated on 23/Aug/21 $${Q}=\int_{\mathrm{0}} ^{\mathrm{1}} \frac{{arctanx}}{{x}}{dx} \\ $$$${arctanx}=\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\left(−\mathrm{1}\right)^{{n}} \frac{{x}^{\mathrm{2}{n}+\mathrm{1}} }{\mathrm{2}{n}+\mathrm{1}}…
Question Number 151756 by Integrals last updated on 22/Aug/21 Commented by MJS_new last updated on 22/Aug/21 $$\int\left(\mathrm{cot}^{\mathrm{1}/\mathrm{4}} \:\beta\:+\mathrm{tan}^{\mathrm{1}/\mathrm{4}} \:\beta\right){d}\beta= \\ $$$$\:\:\:\:\:\left[{t}=\mathrm{tan}^{\mathrm{1}/\mathrm{4}} \:\beta\:\rightarrow\:{d}\beta=\frac{\mathrm{4}{t}^{\mathrm{3}} }{{t}^{\mathrm{8}} +\mathrm{1}}{dt}\right] \\…
Question Number 151761 by talminator2856791 last updated on 22/Aug/21 $$\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\int_{\mathrm{0}} ^{\:\infty} \:\frac{\mathrm{1}}{\:\sqrt{{e}^{{x}} +\mathrm{1}}}\:{dx}\: \\ $$$$\: \\ $$ Answered by mindispower last updated on…
Question Number 20686 by NECx last updated on 31/Aug/17 $$\int\left({tanx}\right)^{\mathrm{1}/\mathrm{3}} {dx} \\ $$ Commented by NECx last updated on 01/Sep/17 $${please}\:{help} \\ $$ Answered by…
Question Number 151754 by Integrals last updated on 22/Aug/21 Terms of Service Privacy Policy Contact: info@tinkutara.com