Question Number 84087 by M±th+et£s last updated on 09/Mar/20 $$\int_{\mathrm{0}} ^{\mathrm{3}} \sqrt{\mathrm{1}+{sinh}^{\mathrm{2}} {t}}\:{dt} \\ $$ Commented by mathmax by abdo last updated on 09/Mar/20 $$\int_{\mathrm{0}}…
Question Number 149608 by puissant last updated on 06/Aug/21 $$…..\mathrm{K}=\int\frac{\mathrm{1}}{\mathrm{1}+\mathrm{sin}^{\mathrm{2}} \left(\mathrm{x}\right)}\mathrm{dx}…… \\ $$ Answered by ArielVyny last updated on 06/Aug/21 $${sin}^{\mathrm{2}} {x}=\frac{\mathrm{1}−{cos}\left(\mathrm{2}{x}\right)}{\mathrm{2}} \\ $$$${K}=\int\frac{\mathrm{1}}{\mathrm{1}+\frac{\mathrm{1}−{cos}\left(\mathrm{2}{x}\right)}{\mathrm{2}}}=\int\frac{\mathrm{1}}{\frac{\mathrm{2}+\mathrm{1}−{cos}\left(\mathrm{2}{x}\right)}{\mathrm{2}}}{dx} \\…
Question Number 84046 by TawaTawa1 last updated on 09/Mar/20 $$\mathrm{Please}\:\mathrm{any}\:\mathrm{short}\:\mathrm{cut}\:\mathrm{to}\:\mathrm{evaluate}:\:\:\:\:\:\int_{\:\mathrm{1}} ^{\:\mathrm{2}} \:\:\:\frac{\:\:\sqrt[{\mathrm{3}}]{\mathrm{x}\:\:−\:\:\mathrm{x}^{\mathrm{4}} }}{\mathrm{x}^{\mathrm{4}} } \\ $$ Commented by jagoll last updated on 09/Mar/20 $$\mathrm{i}\:\mathrm{don}'\mathrm{t}\:\mathrm{know}\:\mathrm{short}\:\mathrm{cut}\:\mathrm{method} \\…
Question Number 84036 by M±th+et£s last updated on 08/Mar/20 $$\int_{−\mathrm{1}} ^{\mathrm{10}} {sin}\left({x}−\mid{x}\mid\right)\:{dx} \\ $$ Answered by TANMAY PANACEA last updated on 09/Mar/20 $$\int_{−\mathrm{1}} ^{\mathrm{0}} {sin}\left({x}+{x}\right){dx}+\int_{\mathrm{0}}…
Question Number 84039 by M±th+et£s last updated on 08/Mar/20 $$\int\frac{{x}\:{cos}^{\mathrm{3}} \left({x}\right)}{{sin}^{\mathrm{5}} \left({x}\right)+{cos}^{\mathrm{5}} \left({x}\right)}\:{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 84035 by M±th+et£s last updated on 08/Mar/20 $$\int\frac{{x}−\mathrm{4}}{{x}^{\mathrm{4}} −\mathrm{1}}{dx} \\ $$ Commented by MJS last updated on 08/Mar/20 $$\frac{{x}−\mathrm{4}}{{x}^{\mathrm{4}} −\mathrm{1}}=−\frac{{x}}{\mathrm{2}\left({x}^{\mathrm{2}} +\mathrm{1}\right)}+\frac{\mathrm{2}}{{x}^{\mathrm{2}} +\mathrm{1}}+\frac{\mathrm{5}}{\mathrm{4}\left({x}+\mathrm{1}\right)}−\frac{\mathrm{3}}{\mathrm{4}\left({x}−\mathrm{1}\right)} \\…
Question Number 84030 by mathmax by abdo last updated on 08/Mar/20 $${find}\:\int\:\sqrt{\frac{{x}+\mathrm{2}}{{x}^{\mathrm{2}} −{x}−\mathrm{3}}}{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 83984 by M±th+et£s last updated on 08/Mar/20 $$\int{cos}^{\mathrm{7}} \left({x}\right)\:{dx} \\ $$ Answered by TANMAY PANACEA last updated on 08/Mar/20 $$\int{cos}^{\mathrm{6}} {x}×{cosxdx} \\ $$$$\int\left(\mathrm{1}−{sin}^{\mathrm{2}}…
Question Number 149498 by peter frank last updated on 05/Aug/21 $$ \\ $$$$\int\frac{{px}+{q}}{\:\sqrt{{x}^{\mathrm{2}} +{r}^{\mathrm{2}} }} \\ $$ Answered by MJS_new last updated on 05/Aug/21 $$\int\frac{{px}+{q}}{\:\sqrt{{x}^{\mathrm{2}}…
Question Number 83960 by john santu last updated on 08/Mar/20 $$\int\:\frac{\mathrm{x}−\mathrm{1}}{\:\sqrt{\mathrm{x}^{\mathrm{2}} −\mathrm{x}}}\:\mathrm{dx}\:?\: \\ $$ Commented by mathmax by abdo last updated on 08/Mar/20 $${I}\:=\int\:\frac{{x}−\mathrm{1}}{\:\sqrt{{x}^{\mathrm{2}} −{x}}}{dx}\:\Rightarrow\:{I}\:=\frac{\mathrm{1}}{\mathrm{2}}\int\:\frac{\mathrm{2}{x}−\mathrm{1}−\mathrm{1}}{\:\sqrt{{x}^{\mathrm{2}}…