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Category: Integration

cos3x-e-2x-dx-

Question Number 76462 by kaivan.ahmadi last updated on 27/Dec/19 $$\int{cos}\mathrm{3}{x}\:{e}^{−\mathrm{2}{x}} {dx} \\ $$ Commented by mathmax by abdo last updated on 27/Dec/19 $${let}\:{A}\:=\int\:{cos}\left(\mathrm{3}{x}\right){e}^{−\mathrm{2}{x}} {dx}\:\Rightarrow{A}\:={Re}\left(\int\:{e}^{\mathrm{3}{ix}} \:{e}^{−\mathrm{2}{x}}…

Question-76442

Question Number 76442 by aliesam last updated on 27/Dec/19 Answered by Tanmay chaudhury last updated on 28/Dec/19 $${x}={tana}\:\:\:\:{dx}={sec}^{\mathrm{2}} {ada} \\ $$$${sec}^{−\mathrm{1}} \left(\frac{\mathrm{1}+{tan}^{\mathrm{2}} {a}}{\mathrm{1}−{tan}^{\mathrm{2}} {a}}\right)\rightarrow{sec}^{−\mathrm{1}} \left({sec}\mathrm{2}{a}\right)=\mathrm{2}{a}…

0-1-x-x-x-y-5-dy-dx-

Question Number 10876 by Saham last updated on 28/Feb/17 $$\int_{\:\mathrm{0}} ^{\:\mathrm{1}} \int_{\:\mathrm{x}} ^{\:\sqrt{\mathrm{x}}} \:\left(\mathrm{x}\:+\:\mathrm{y}^{\mathrm{5}} \right)\:\mathrm{dy}\:\mathrm{dx} \\ $$ Answered by fariraihmudzengerere75@gmail.c last updated on 28/Feb/17 $${Answer}\:.\:\int_{\mathrm{0}}…

x-3-x-4-dx-

Question Number 10880 by Saham last updated on 28/Feb/17 $$\left.\int\:\left(\mathrm{x}\:+\:\mathrm{3}\right)\sqrt{\left(\mathrm{x}\:+\:\mathrm{4}\right.}\right)\:\mathrm{dx}\: \\ $$ Answered by geovane10math last updated on 28/Feb/17 $$\int\left({x}\:+\:\mathrm{3}\right)\sqrt{{x}\:+\:\mathrm{4}}\:\mathrm{dx}\:=\:\int{x}\sqrt{{x}\:+\:\mathrm{4}}\:\mathrm{dx}\:+\:\int\mathrm{3}\sqrt{{x}\:+\:\mathrm{4}}\:\mathrm{dx} \\ $$$$\mathrm{First}\:\mathrm{integral}: \\ $$$$\int{x}\sqrt{{x}\:+\:\mathrm{4}}\:\mathrm{dx}\:= \\…

dx-x-16-4x-2-

Question Number 141943 by cesarL last updated on 25/May/21 $$\int\frac{{dx}}{{x}\sqrt{\mathrm{16}−\mathrm{4}{x}^{\mathrm{2}} }} \\ $$ Answered by MJS_new last updated on 25/May/21 $$\int\frac{{dx}}{{x}\sqrt{\mathrm{16}−\mathrm{4}{x}^{\mathrm{2}} }}=\frac{\mathrm{1}}{\mathrm{2}}\int\frac{{dx}}{{x}\sqrt{\mathrm{4}−{x}^{\mathrm{2}} }}= \\ $$$$\:\:\:\:\:\left[{t}=\frac{\mathrm{2}+\sqrt{\mathrm{4}−{x}^{\mathrm{2}}…