Question Number 140977 by Mathspace last updated on 14/May/21 $${find}\:\int_{\mathrm{0}} ^{\infty} \:\frac{{e}^{−{t}\left(\mathrm{1}+{x}^{\mathrm{2}} \right)} }{\mathrm{1}+{x}^{\mathrm{2}} }{dx}\:\:{with}\:{t}\geqslant\mathrm{0} \\ $$ Answered by mathmax by abdo last updated on…
Question Number 140976 by Mathspace last updated on 14/May/21 $${find}\:\int_{\mathrm{0}} ^{\pi} \:\frac{{dx}}{\left(\mathrm{2}−{cosx}−{sinx}\right)^{\mathrm{2}} } \\ $$$$ \\ $$ Answered by Ar Brandon last updated on 14/May/21…
Question Number 140971 by bekzodjumayev last updated on 14/May/21 Commented by bekzodjumayev last updated on 14/May/21 $${Please}\:{help}? \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 140961 by iloveisrael last updated on 14/May/21 $$\:\underset{\mathrm{0}} {\overset{\:\mathrm{1}} {\int}}\:\:\frac{\mathrm{ln}\:\left({x}+\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }\right)}{{x}}\:{dx}\:=?\: \\ $$ Answered by qaz last updated on 14/May/21 $$\int_{\mathrm{0}} ^{\mathrm{1}} \frac{{ln}\left({x}+\sqrt{\mathrm{1}−{x}^{\mathrm{2}}…
Question Number 140966 by mnjuly1970 last updated on 14/May/21 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:…….{nice}……{calculus}….. \\ $$$$\:\:\:\:\:{if}\:\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\sqrt{{cos}\:\left({n}\pi\right)}\:}{\left(\mathrm{2}{n}\right)!!}\:=\:\omega \\ $$$$\:\:\:\:\:\:\:{then}\:\:\:{Re}\left(\omega\right):=?? \\ $$ Answered by Dwaipayan Shikari last updated on…
Question Number 140956 by mnjuly1970 last updated on 14/May/21 $$\:\:\:\:\:\:\:\:\:\:…..{advanced}……{calculus}….. \\ $$$$\:\:\:\:\:{prove}\:{that}: \\ $$$$\:\:\boldsymbol{\phi}:=\:\int_{−\infty} ^{\:\infty} \frac{{sin}^{\mathrm{4}} \left({x}\right).{cos}^{\mathrm{4}} \left({x}\right)}{{x}^{\mathrm{2}} }{dx}=\frac{\pi}{\mathrm{16}} \\ $$$$\:\:{m}.{n} \\ $$ Answered by…
Question Number 9863 by richard last updated on 10/Jan/17 $$\mathrm{the}\:\mathrm{value}\:\mathrm{of}: \\ $$$$\underset{\mathrm{0}} {\overset{\pi/\mathrm{2}} {\int}}\frac{\mathrm{1}}{\mathrm{1}+\mathrm{tan}^{\mathrm{3}} {x}}\:{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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