Question Number 130809 by bemath last updated on 29/Jan/21 $$\:\int\:\mathrm{tan}\:\mathrm{x}\:\sqrt{\mathrm{sin}\:\mathrm{x}}\:\mathrm{dx}\:? \\ $$ Answered by EDWIN88 last updated on 29/Jan/21 $${let}\:\sqrt{\mathrm{sin}\:{x}}\:=\:{u}\:\Rightarrow\mathrm{sin}\:{x}\:=\:{u}^{\mathrm{2}} \\ $$$$\:\mathrm{tan}\:{x}\:=\:\frac{{u}^{\mathrm{2}} }{\:\sqrt{\mathrm{1}−{u}^{\mathrm{4}} }}\: \\…
Question Number 130778 by EDWIN88 last updated on 28/Jan/21 $$\int\:\frac{\mathrm{3}{x}^{\mathrm{2}} −\mathrm{1}}{{x}^{\mathrm{4}} −\mathrm{1}}\:{dx}\: \\ $$ Answered by bemath last updated on 29/Jan/21 $$\:\frac{\mathrm{3x}^{\mathrm{2}} −\mathrm{1}}{\left(\mathrm{x}^{\mathrm{2}} +\mathrm{1}\right)\left(\mathrm{x}^{\mathrm{2}} −\mathrm{1}\right)}\:=\:\frac{\mathrm{3}\left(\mathrm{x}^{\mathrm{2}}…
Question Number 130781 by EDWIN88 last updated on 28/Jan/21 $$\int_{\mathrm{0}} ^{\:\mathrm{1}} \:\frac{\mathrm{ln}\:\left(\mathrm{1}+{x}+{x}^{\mathrm{2}} +{x}^{\mathrm{3}} +…+{x}^{{n}} \right)}{{x}}\:{dx}? \\ $$ Answered by mathmax by abdo last updated on…
Question Number 130763 by Lordose last updated on 28/Jan/21 $$\mathrm{Q}.\mathrm{130626} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 130759 by mnjuly1970 last updated on 28/Jan/21 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:…{nice}\:\:{calculus}\:… \\ $$$$\:{find}\::\:\phi\:=\int_{\mathrm{0}} ^{\:\infty} \left({x}^{\mathrm{2}} {ln}\left(\mathrm{1}+{e}^{{x}} \right)−{x}^{\mathrm{3}} \right){dx} \\ $$$$ \\ $$ Answered by mnjuly1970 last…
Question Number 130738 by bemath last updated on 28/Jan/21 $$\int_{\:\mathrm{1}} ^{\:\mathrm{cosh}\:\mathrm{x}} \sqrt{\mathrm{t}^{\mathrm{2}} −\mathrm{1}}\:\mathrm{dt}\:=\:?\: \\ $$ Answered by MJS_new last updated on 28/Jan/21 $$\int\sqrt{{t}^{\mathrm{2}} −\mathrm{1}}{dt}= \\…
Question Number 65203 by arcana last updated on 26/Jul/19 $$\int_{\mathrm{0}} ^{\infty} \:\frac{{x}^{\mathrm{2}} }{{x}^{\mathrm{4}} +{x}^{\mathrm{2}} +\mathrm{1}}{dx} \\ $$ Commented by mathmax by abdo last updated on…
Question Number 65200 by rajesh4661kumar@gmail.com last updated on 26/Jul/19 Answered by ajfour last updated on 26/Jul/19 $${I}=\int\sqrt{\mathrm{tan}\:{x}}{dx} \\ $$$${let}\:\mathrm{tan}\:{x}={t}^{\mathrm{2}} \:\Rightarrow\:{dx}=\frac{\mathrm{2}{tdt}}{\mathrm{1}+{t}^{\mathrm{2}} } \\ $$$$\Rightarrow\:{I}=\int\frac{\mathrm{2}{t}^{\mathrm{2}} {dt}}{\mathrm{1}+{t}^{\mathrm{4}} }…
Question Number 65202 by arcana last updated on 26/Jul/19 $$\int_{\mathrm{0}} ^{\pi} \:\frac{\mathrm{cos}\:\mathrm{2}\theta}{\mathrm{1}−\mathrm{2}{a}\mathrm{cos}\:\theta+{a}^{\mathrm{2}} }{d}\theta,\:{a}^{\mathrm{2}} <\mathrm{1} \\ $$$$\mathrm{answer}? \\ $$ Answered by Tanmay chaudhury last updated on…
Question Number 65196 by mathmax by abdo last updated on 26/Jul/19 $$\:{find}\:\int_{\mathrm{0}} ^{\mathrm{1}} \left(\frac{\mathrm{1}}{\mathrm{1}−{x}}\:+\frac{\mathrm{1}}{{lnx}}\right){dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com