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Question Number 106661 by deep last updated on 06/Aug/20 $$\mathrm{sin}\:{x}\frac{\mathrm{1}}{\mathrm{cos}\:{x}}=\:\frac{\mathrm{sin}\:{x}}{\mathrm{cos}\:{x}}=\mathrm{tan}\:{x} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 172178 by Mikenice last updated on 23/Jun/22 Answered by mr W last updated on 24/Jun/22 $$=\int_{\mathrm{0}} ^{\mathrm{1}} {x}\left[\frac{{xy}^{\mathrm{2}} }{\mathrm{2}}+\frac{{y}^{\mathrm{3}} }{\mathrm{3}}\right]_{\mathrm{0}} ^{{x}} {dx} \\…
Question Number 106633 by bemath last updated on 06/Aug/20 $$\:\:\:\:\:\:\:\overset{@\mathrm{bemath}@} {\:} \\ $$$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\sqrt{\mathrm{1}+\mathrm{2sin}\:\mathrm{x}}\:−\sqrt{\mathrm{1}−\mathrm{4sin}\:\mathrm{4x}}}{\mathrm{4x}} \\ $$ Answered by john santu last updated on 06/Aug/20 $$\:\:\:\:\:\:\underset{@\mathrm{JS}@}…
Question Number 106614 by bemath last updated on 06/Aug/20 $$\:\:\:\:\:\underset{@\mathrm{bemath}@} {\:} \\ $$$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\sqrt[{\mathrm{3}}]{\mathrm{1}+\mathrm{3sin}\:\mathrm{x}\:}\:−\sqrt[{\mathrm{3}}]{\mathrm{1}+\mathrm{sin}\:\mathrm{3x}}}{\mathrm{2x}}\:=?\: \\ $$ Answered by Dwaipayan Shikari last updated on 06/Aug/20 $$\underset{{x}\rightarrow\mathrm{0}}…
Question Number 41016 by Tawa1 last updated on 31/Jul/18 Commented by Tawa1 last updated on 31/Jul/18 $$\mathrm{For}\:\mathrm{what}\:\mathrm{value}\:\mathrm{of}\:\mathrm{x}\:\mathrm{is}\:\mathrm{the}\:\mathrm{function}\:\mathrm{h}\left(\mathrm{x}\right)\:\mathrm{discontinuous}\:\mathrm{and}\:\mathrm{do}\:\mathrm{we} \\ $$$$\mathrm{call}\:\mathrm{functions}\:\mathrm{like}\:\mathrm{the}\:\mathrm{question}\:\mathrm{above}. \\ $$ Answered by tanmay.chaudhury50@gmail.com last…
Question Number 172064 by qaz last updated on 23/Jun/22 $${Calculate}\:\:::\:\:\underset{{x}\rightarrow\mathrm{0}^{+} } {{lim}}\frac{\int_{\mathrm{1}} ^{{x}} \frac{{lnt}}{\mathrm{1}+{t}}{dt}}{\left({x}−\mathrm{1}\right)^{\mathrm{2}} }=? \\ $$ Answered by puissant last updated on 23/Jun/22 $$=\:\int_{\mathrm{1}}…