Question Number 171247 by ilhamQ last updated on 11/Jun/22 $$\underset{{x}\rightarrow\mathrm{2}} {\mathrm{lim}}\:\frac{{x}^{\mathrm{2}} −\mathrm{4}}{{x}−\mathrm{2}}=… \\ $$ Answered by Rasheed.Sindhi last updated on 11/Jun/22 $$\underset{{x}\rightarrow\mathrm{2}} {\mathrm{lim}}\:\frac{{x}^{\mathrm{2}} −\mathrm{4}}{{x}−\mathrm{2}}=? \\…
Question Number 105661 by bobhans last updated on 30/Jul/20 $$\underset{{x}\rightarrow\pi/\mathrm{2}} {\mathrm{lim}}\:\mathrm{tan}\:^{\mathrm{2}} {x}\:\sqrt{\left({x}−\frac{\pi}{\mathrm{2}}\right)−\mathrm{cos}\:\:^{\mathrm{2}} {x}}\:? \\ $$ Commented by Dwaipayan Shikari last updated on 30/Jul/20 $${limit}\:{doesn}'{t}\:{exist} \\…
Question Number 40120 by maxmathsup by imad last updated on 15/Jul/18 $${find}\:{the}\:{value}\:{of}\:\:{lim}_{{x}\rightarrow\mathrm{0}} \:\:\:\frac{\left(\mathrm{1}+{sinx}\right)^{\frac{\mathrm{1}}{{x}}} \:−{e}^{\mathrm{1}−\frac{{x}}{\mathrm{2}}} }{\left(\mathrm{1}+{tanx}\right)^{\frac{\mathrm{1}}{{x}}} \:−{e}^{\mathrm{1}−\frac{{x}}{\mathrm{2}}} } \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 40119 by maxmathsup by imad last updated on 15/Jul/18 $${find}\:{lim}_{{x}\rightarrow+\infty} \:\left({chx}\right)^{{sh}\left({x}\right)} \:\:−\left({shx}\right)^{{ch}\left({x}\right)} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 40117 by maxmathsup by imad last updated on 15/Jul/18 $${calculate}\:{lim}_{{x}\rightarrow\mathrm{0}} \:\:\:\:\frac{\mathrm{1}}{{sin}^{\mathrm{4}} {x}}\left\{\:{sin}\left(\frac{{x}}{\mathrm{1}−{x}}\right)−\frac{{sinx}}{\mathrm{1}−{sinx}}\right\} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 40112 by maxmathsup by imad last updated on 15/Jul/18 $${calculate}\:\:{lim}_{{x}\rightarrow\mathrm{0}^{+} } \:\:\:\:\:\left\{\:{tan}\left(\frac{\pi}{\mathrm{2}+{x}}\right)\right\}^{{x}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 40110 by maxmathsup by imad last updated on 15/Jul/18 $${find}\:\:{lim}_{{x}\rightarrow+\infty} {x}\left\{\left(\mathrm{1}+{a}\right)^{\frac{\mathrm{1}}{{x}}} \:−{a}^{\frac{\mathrm{1}}{{x}}} \right\}\:\:\:\:\:\left({a}>\mathrm{0}\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 40111 by maxmathsup by imad last updated on 15/Jul/18 $${find}\:\:{lim}\:_{{x}\rightarrow\mathrm{0}} \:\:\:\frac{{a}^{{x}} \:−{b}^{{x}} }{{e}^{{ax}} \:−{e}^{{bx}} }\:\:\:{with}\:{a}>\mathrm{0}\:\:\:\:{b}>\mathrm{0}\:\:{and}\:{a}\neq{b} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 40108 by maxmathsup by imad last updated on 15/Jul/18 $${calculate}\:\:{lim}_{{x}\rightarrow\frac{\pi}{\mathrm{2}}} \:\:\:\:\:\left({sinx}\right)^{{ln}\mid{x}−\frac{\pi}{\mathrm{2}}\mid} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 40109 by maxmathsup by imad last updated on 15/Jul/18 $${find}\:\:{lim}_{{x}\rightarrow+\infty} {x}\left\{\left(\mathrm{1}+{a}\right)^{\frac{\mathrm{1}}{{x}}} \:−{a}^{\frac{\mathrm{1}}{{x}}} \right\}\:\:\:\:\:\left({a}>\mathrm{0}\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com