Question Number 170211 by mathlove last updated on 18/May/22 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\left(\frac{{tan}^{−\mathrm{1}} \left(\frac{{x}−{x}\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }}{\:\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }+{x}^{\mathrm{2}} }\right)}{{x}^{\mathrm{3}} }\right)=? \\ $$$${pleas}\:{solve}\:{this} \\ $$ Answered by aleks041103 last updated…
Question Number 104667 by bobhans last updated on 23/Jul/20 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\left[\frac{\mathrm{3}^{\pi{x}} }{\mathrm{tan}\:{x}}\:−\:\frac{\mathrm{cos}\:^{\mathrm{2}} {x}}{\mathrm{sin}\:{x}}\right]\:? \\ $$ Answered by bramlex last updated on 23/Jul/20 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{3}^{\pi{x}} .\mathrm{cos}\:{x}}{\mathrm{sin}\:{x}}−\:\frac{\mathrm{cos}\:^{\mathrm{2}}…
Question Number 104664 by ~blr237~ last updated on 23/Jul/20 $$\:\:\left(\mathrm{1}−{lna}\right)\left(\mathrm{1}−{lnb}\right)…….\left(\mathrm{1}−{lnx}\right)\left(\mathrm{1}−{lny}\right)\left(\mathrm{1}−{lnz}\right)=\mathrm{0}\:\:???? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 170197 by mathlove last updated on 18/May/22 Answered by qaz last updated on 18/May/22 $$\mathrm{ln}\left(\mathrm{1}+\mathrm{x}^{\mathrm{2018}} \right)=\mathrm{x}^{\mathrm{2018}} −\frac{\mathrm{1}}{\mathrm{2}}\mathrm{x}^{\mathrm{4036}} +… \\ $$$$\left(\mathrm{ln}\left(\mathrm{1}+\mathrm{x}\right)\right)^{\mathrm{2018}} =\left(\mathrm{x}−\frac{\mathrm{1}}{\mathrm{2}}\mathrm{x}^{\mathrm{2}} +…\right)^{\mathrm{2018}} =\mathrm{x}^{\mathrm{2018}}…
Question Number 104655 by bobhans last updated on 23/Jul/20 $$\underset{{x}\rightarrow{a}} {\mathrm{lim}}\frac{\sqrt{\mathrm{2}{x}+{a}}−\sqrt{\mathrm{3}{x}}}{\:\sqrt{{x}+\mathrm{3}{a}}−\mathrm{2}\sqrt{{x}}}\:=?\:\:\:\:\left[{a}\neq\mathrm{0}\right]\: \\ $$ Answered by bramlex last updated on 23/Jul/20 $$\underset{{x}\rightarrow{a}} {\mathrm{lim}}\:\:\frac{\left[\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}{x}+{a}}}−\frac{\mathrm{3}}{\mathrm{2}\sqrt{\mathrm{3}{x}}}\right]}{\left[\frac{\mathrm{1}}{\mathrm{2}\sqrt{{x}+\mathrm{3}{a}}}−\frac{\mathrm{1}}{\:\sqrt{{x}}}\right]}\:=\:\frac{\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}{a}}}−\frac{\mathrm{3}}{\mathrm{2}\sqrt{\mathrm{3}{a}}}}{\frac{\mathrm{1}}{\mathrm{4}\sqrt{{a}}}−\frac{\mathrm{1}}{\mathrm{2}\sqrt{{a}}}} \\ $$$$=\:\left\{\frac{\mathrm{2}}{\mathrm{2}\sqrt{\mathrm{3}{a}}}−\frac{\mathrm{3}}{\mathrm{2}\sqrt{\mathrm{3}{a}}}\:\right\}×\:\left(−\mathrm{4}\sqrt{{a}}\:\right) \\…
Question Number 170182 by mathlove last updated on 18/May/22 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\left[{x}\centerdot{sin}\frac{\mathrm{1}}{{x}}\right]=? \\ $$ Commented by mr W last updated on 18/May/22 $${has}\:\left[\:\:\right]\:{special}\:{meaning}?\:{or}\:{you}\:{just}\:{mean} \\ $$$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\left({x}\centerdot{sin}\frac{\mathrm{1}}{{x}}\right)=?…
Question Number 170166 by sciencestudent last updated on 17/May/22 $${li}\underset{{x}\rightarrow\mathrm{0}} {{m}}\left(\frac{\mathrm{1}}{{sin}^{\mathrm{2}} {x}}−\frac{\mathrm{1}}{{x}^{\mathrm{2}} }\right)=? \\ $$$${please}\:{solve}\:{it}\:{describely}. \\ $$ Commented by mr W last updated on 17/May/22…
Question Number 170159 by mathlove last updated on 17/May/22 $$\underset{{x}\rightarrow\mathrm{4}} {\mathrm{lim}}\:\frac{{e}\:!{x}−\mathrm{24}}{\:\sqrt{{x}}−\mathrm{2}}=? \\ $$ Answered by Mathspace last updated on 18/May/22 $${hosital}\:\:{lim}={lim}_{{x}\rightarrow\mathrm{4}} \:\:\:\frac{{e}!}{\frac{\mathrm{1}}{\mathrm{2}\sqrt{{x}}}} \\ $$$$={lim}_{{x}\rightarrow\mathrm{4}} \:\mathrm{2}\left({e}\right)!\sqrt{{x}}…
Question Number 39078 by Cheyboy last updated on 02/Jul/18 $$\boldsymbol{{Without}}\:\boldsymbol{{using}}\:\boldsymbol{{l}}'\boldsymbol{{hopital}} \\ $$$$\boldsymbol{{find}}\:\:\:\:\underset{{x}\rightarrow\mathrm{3}} {\mathrm{lim}}\:\frac{\sqrt{\mathrm{9}−\boldsymbol{{x}}^{\mathrm{2}} }}{\boldsymbol{{x}}−\mathrm{3}} \\ $$$$ \\ $$ Commented by math khazana by abdo last…
Question Number 170141 by sciencestudent last updated on 17/May/22 $${li}\underset{{x}\rightarrow\mathrm{0}} {{m}}\left(\frac{\mathrm{1}}{{sin}^{\mathrm{2}} {x}}−\frac{\mathrm{1}}{{x}^{\mathrm{2}} }\right)=? \\ $$ Commented by mr W last updated on 17/May/22 $$=\left(\frac{\mathrm{1}}{\mathrm{sin}\:{x}}+\frac{\mathrm{1}}{{x}}\right)\left(\frac{\mathrm{1}}{\mathrm{sin}\:{x}}−\frac{\mathrm{1}}{{x}}\right) \\…