Question Number 104606 by john santu last updated on 22/Jul/20 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\left\{\frac{{x}−\mathrm{1}}{\mid{x}−\mathrm{1}\mid}\:+\:\mid{x}\mid\right\}=? \\ $$ Answered by bobhans last updated on 22/Jul/20 $$\left(\mathrm{1}\right)\underset{{x}\rightarrow\mathrm{0}^{+} } {\mathrm{lim}}\left\{\frac{{x}−\mathrm{1}}{\mid{x}−\mathrm{1}\mid}\:+\:\mid{x}\mid\:\right\}\:=\:\underset{{x}\rightarrow\mathrm{0}^{+} }…
Question Number 104607 by ~blr237~ last updated on 22/Jul/20 $$\:{if}\:\:\:{a}_{\mathrm{0}} =\mathrm{1}\:\:\:,\:\forall\:{n}\geqslant\mathrm{1}\:\:\:\:\:\underset{{p}=\mathrm{0}} {\overset{{n}} {\sum}}\:\frac{{a}_{{n}−{p}} }{\left({p}+\mathrm{1}\right)!}=\mathrm{0}\: \\ $$$${explicit}\:\:{a}_{{n}} \:\:{in}\:{terms}\:{of}\:{n}\: \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 39067 by bshahid010@gmail.com last updated on 02/Jul/18 Commented by math khazana by abdo last updated on 03/Jul/18 $$={lim}_{{h}\rightarrow\mathrm{0}} \:\:\frac{\mathrm{2}{h}\:−{h}^{\mathrm{3}} \sqrt{\mathrm{8}+{h}}}{\mathrm{2}{h}^{\mathrm{4}} \sqrt{\mathrm{8}+{h}}} \\ $$$$={lim}_{{h}\rightarrow\mathrm{0}}…
Question Number 170129 by mathlove last updated on 17/May/22 $$\underset{{x}\rightarrow\mathrm{4}} {\mathrm{lim}}\:\frac{{e}\:!{x}−\mathrm{24}}{\:\sqrt{{x}}−\mathrm{2}}=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 104603 by john santu last updated on 22/Jul/20 $$\underset{{x}\rightarrow−\mathrm{2}} {\mathrm{lim}}\:{x}\mid{x}−\mathrm{2}\mid\: \\ $$ Answered by bobhans last updated on 22/Jul/20 $$\underset{{x}\rightarrow−\mathrm{2}^{−} } {\mathrm{lim}}{x}\mid{x}−\mathrm{2}\mid\:=\:\underset{{x}\rightarrow−\mathrm{2}^{−} }…
Question Number 170130 by sciencestudent last updated on 17/May/22 $${li}\underset{{x}\rightarrow\mathrm{0}} {{m}}\left(\frac{\mathrm{1}}{{sin}^{\mathrm{2}} {x}}−\frac{\mathrm{1}}{{x}^{\mathrm{2}} }\right)=? \\ $$ Commented by cortano1 last updated on 17/May/22 $$\:=\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\left({x}−\mathrm{sin}\:{x}\right)\left({x}+\mathrm{sin}\:{x}\right)}{{x}^{\mathrm{2}} \:\mathrm{sin}\:^{\mathrm{2}}…
Question Number 170057 by nimnim last updated on 15/May/22 $$\underset{{x}\rightarrow\mathrm{0}} {{lim}}\:\frac{{x}}{{a}}\lfloor\frac{{b}}{{x}}\rfloor\:\:{where}\:{a},{b}>\mathrm{0} \\ $$$${please}…. \\ $$ Answered by mahdipoor last updated on 15/May/22 $${get}\:\frac{{b}}{{x}}={t}\:\: \\ $$$$\underset{{x}\rightarrow\mathrm{0}}…
Question Number 170018 by cortano1 last updated on 14/May/22 $$\:\:\:\:\:\:\underset{{x}\rightarrow\frac{\pi}{\mathrm{2}}} {\mathrm{lim}}\left(\mathrm{1}+\mathrm{sin}\:\left(\pi−\mathrm{2}{x}\right)\right)^{\frac{\mathrm{5}}{\mathrm{sin}\:\left({x}−\frac{\pi}{\mathrm{2}}\right)}} .\mathrm{ln}\:\left(\mathrm{4}.\frac{\mathrm{cos}\:\left(\pi−\mathrm{2}{x}\right)−\mathrm{1}}{\left(\frac{\pi}{\mathrm{2}}−{x}\right)^{\mathrm{2}} }\right)=? \\ $$ Answered by Mathspace last updated on 14/May/22 $${u}\left({x}\right)=\left(\mathrm{1}+{sin}\left(\pi−\mathrm{2}{x}\right)\right)^{\frac{\mathrm{5}}{{sin}\left({x}−\frac{\pi}{\mathrm{2}}\right)}} \\ $$$${and}\:{v}\left({x}\right)={ln}\left(\mathrm{4}.\frac{{cos}\left(\pi−\mathrm{2}{x}\right)−\mathrm{1}}{\left(\frac{\pi}{\mathrm{2}}−{x}\right)^{\mathrm{2}}…
Question Number 38893 by gunawan last updated on 01/Jul/18 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{{x}\left({a}+{b}\:\mathrm{cos}\:{x}\right)−{c}\:\mathrm{sin}\:{x}}{{x}^{\mathrm{5}} }=\mathrm{1} \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:{a},{b},\:\mathrm{and}\:{c} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 01/Jul/18 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{{ax}+{bx}\left(\mathrm{1}−\frac{{x}^{\mathrm{2}}…
Question Number 38892 by gunawan last updated on 01/Jul/18 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{{x}\left(\mathrm{1}+\:{a}\:\mathrm{cos}\:{x}\right)−{b}\:\mathrm{sin}\:{x}}{{x}^{\mathrm{5}} }=\mathrm{1} \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:{a}\:\mathrm{and}\:{b} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 01/Jul/18 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{{x}+{ax}\left(\mathrm{1}−\frac{{x}^{\mathrm{2}}…