Question Number 104159 by Ar Brandon last updated on 19/Jul/20 $$\mathrm{How}\:\mathrm{may}\:\mathrm{we}\:\mathrm{plot}\:\mathrm{the}\:\mathrm{graph}\:\mathrm{of} \\ $$$$\mathrm{f}\left(\mathrm{x}\right)=\mathrm{x}+\sqrt{\frac{\mathrm{x}\left(\mathrm{x}+\mathrm{2}\right)}{\mathrm{x}+\mathrm{1}}}\:,\:\mathrm{with} \\ $$$$\mathrm{the}\:\mathrm{help}\:\mathrm{of}\:\mathrm{a}\:\mathrm{variation}\:\mathrm{table}\:? \\ $$ Commented by Ar Brandon last updated on 19/Jul/20…
Question Number 169635 by cortano1 last updated on 05/May/22 $$\:\:\:\underset{{x}\rightarrow−\mathrm{3}} {\mathrm{lim}}\:\frac{\sqrt{{x}^{\mathrm{2}} +\mathrm{7}}+\sqrt{\mathrm{25}−{x}^{\mathrm{2}} }−\mathrm{8}}{\:\sqrt{−\mathrm{3}{x}}−\mathrm{6}+\sqrt{\mathrm{18}+\mathrm{3}{x}}}\:=? \\ $$ Commented by cortano1 last updated on 05/May/22 $$\:{by}\:{L}'{Hopital} \\ $$$$\:\underset{{x}\rightarrow−\mathrm{3}}…
Question Number 169565 by mathlove last updated on 03/May/22 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{{a}^{{sinx}} −{c}^{{sinx}} }{{m}^{{sinx}} −{n}^{{sinx}} }=? \\ $$$$\forall\left\{{a},{c},{m},{n}\right\}\in\left[\mathrm{0},\infty\right] \\ $$ Commented by infinityaction last updated on…
Question Number 169527 by Giantyusuf last updated on 01/May/22 $$\boldsymbol{{evaluate}}\:\boldsymbol{{the}}\:\boldsymbol{{limit}}\left(\boldsymbol{{if}}\:\boldsymbol{{it}}\:\boldsymbol{{exists}}\right) \\ $$$$\boldsymbol{{lim}}_{\boldsymbol{{n}}\rightarrow\infty} \left[\frac{\sqrt{\boldsymbol{{n}}^{\mathrm{4}} −\mathrm{2}\boldsymbol{{n}}^{\mathrm{3}} }−\boldsymbol{{n}}^{\mathrm{2}} }{\boldsymbol{{n}}+\mathrm{2}}\right]^{\mathrm{3}} \\ $$ Commented by infinityaction last updated on 02/May/22…
Question Number 103979 by Study last updated on 18/Jul/20 $$\:\:{show}\:{right}\:{and}\:{left}\:{sid}\:\:\:\:{limitation}\:\:\:\: \\ $$$${of}\:\:\:{li}\underset{{x}\rightarrow\mathrm{0}} {{m}}\frac{{ln}\left({b}−{x}\right)}{{ax}} \\ $$$$ \\ $$ Commented by Study last updated on 18/Jul/20 $${help}\:{me}…
Question Number 169514 by Giantyusuf last updated on 01/May/22 $$\boldsymbol{{evaluate}}\:\boldsymbol{{the}}\:\boldsymbol{{following}}\:\boldsymbol{{limit}} \\ $$$$\left(\boldsymbol{{if}}\:\boldsymbol{{it}}\:\boldsymbol{{exists}}\right) \\ $$$$\boldsymbol{{lim}}_{\boldsymbol{{n}}\rightarrow\infty} \frac{\boldsymbol{{ln}}^{\mathrm{2}} \left(\boldsymbol{{n}}+\mathrm{1}\right)}{\left(\boldsymbol{{n}}−\mathrm{1}\right)^{\mathrm{2}} } \\ $$ Commented by Giantyusuf last updated on…
Question Number 169508 by Giantyusuf last updated on 01/May/22 $${Evaluate}\:{if}\:{the}\:{limit}\:{exist} \\ $$$${lim}_{\boldsymbol{{n}}\rightarrow\infty} \left(\frac{\mathrm{3}^{\boldsymbol{{n}}} +\left(−\mathrm{2}\right)^{\boldsymbol{{n}}+\mathrm{1}} }{\mathrm{3}^{\boldsymbol{{n}}−\mathrm{2}} −\mathrm{2}^{\mathrm{2}\boldsymbol{{n}}−\mathrm{1}} }\right) \\ $$ Answered by qaz last updated on…
Question Number 169501 by Giantyusuf last updated on 01/May/22 Answered by qaz last updated on 01/May/22 $$\underset{\mathrm{n}\rightarrow\infty} {\mathrm{lim}n}\left(\frac{\pi}{\mathrm{2}}−\mathrm{arctan}\:\mathrm{n}\right)=\underset{\mathrm{n}\rightarrow\infty} {\mathrm{lim}narctan}\:\frac{\mathrm{1}}{\mathrm{n}}=\mathrm{1} \\ $$ Terms of Service Privacy…
Question Number 169498 by bagjagugum123 last updated on 01/May/22 Commented by infinityaction last updated on 01/May/22 $$\frac{\mathrm{8}}{\mathrm{3}} \\ $$ Commented by bagjagugum123 last updated on…
Question Number 169481 by TOTTI last updated on 01/May/22 Terms of Service Privacy Policy Contact: info@tinkutara.com