Question Number 163960 by bobhans last updated on 12/Jan/22 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\sqrt{\mathrm{2}+\mathrm{7cot}\:^{\mathrm{2}} \mathrm{x}}−\sqrt{\mathrm{7}+\mathrm{7cot}\:^{\mathrm{2}} \mathrm{x}}}{\mathrm{tan}\:\mathrm{x}}\:=? \\ $$ Answered by cortano1 last updated on 12/Jan/22 Terms of Service…
Question Number 163959 by mathlove last updated on 12/Jan/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 163938 by cortano1 last updated on 12/Jan/22 $$\:\:\:\:\:\:\:\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{cos}\:\left(−\mathrm{3}{x}\right)−\mathrm{cos}\:\left(\mathrm{3}{x}\right)}{\mathrm{sin}\:^{\mathrm{2}} \left({x}\sqrt{\mathrm{5}}\:\right)}=? \\ $$ Answered by 770551415 last updated on 12/Jan/22 $$\boldsymbol{{Solution}}:\:{cos}\:{y}\:{is}\:{even}\: \\ $$$$\:\:{cos}\left(−\mathrm{3}{x}\right)={cos}\left(\mathrm{3}{x}\right)\: \\…
Question Number 163931 by mathlove last updated on 12/Jan/22 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{{x}^{{x}^{{x}} } }{{x}}=? \\ $$$${pleas}\:\:{help} \\ $$ Answered by mahdipoor last updated on 12/Jan/22 $$\underset{{x}\rightarrow\mathrm{0}}…
Question Number 98380 by Rio Michael last updated on 13/Jun/20 $$\mathrm{let}\:\left\{{u}_{{n}} \right\}\:\mathrm{and}\:\left\{{v}_{{n}} \right\}\:\mathrm{be}\:\mathrm{sequences}\:\mathrm{defined}\:\mathrm{by} \\ $$$$\:{u}_{\mathrm{0}} \:=\:\mathrm{9},\:{u}_{{n}+\mathrm{1}} \:=\:\frac{\mathrm{1}}{\mathrm{2}}{u}_{{n}} −\mathrm{3}. \\ $$$${v}_{{n}} \:=\:{u}_{{n}} \:+\:\mathrm{6}. \\ $$$$\mathrm{Calculate}\:{P}_{{n}} \:=\:\underset{{i}=\mathrm{0}}…
Question Number 163825 by cortano1 last updated on 11/Jan/22 $$\:\:\:\:\:\:\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{tan}\:\mathrm{2}{x}−\mathrm{2}{x}}{\mathrm{sin}\:\mathrm{3}{x}−\mathrm{3}{x}}\:=?\: \\ $$ Answered by Ar Brandon last updated on 11/Jan/22 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{tan2}{x}−\mathrm{2}{x}}{\mathrm{sin3}{x}−\mathrm{3}{x}}=\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\left(\mathrm{2}{x}+\frac{\left(\mathrm{2}{x}\right)^{\mathrm{3}} }{\mathrm{3}}−\mathrm{2}{x}\right)}{\mathrm{3}{x}−\frac{\left(\mathrm{3}{x}\right)^{\mathrm{3}}…
Question Number 163775 by mathlove last updated on 10/Jan/22 Commented by MJS_new last updated on 10/Jan/22 $$\mathrm{no} \\ $$ Answered by phanphuoc last updated on…
Question Number 163769 by mathlove last updated on 10/Jan/22 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\frac{{ln}\left(\mathrm{1}+\sqrt[{{n}}]{{n}!}\right)}{\:\sqrt[{{n}}]{\left(\mathrm{2}{n}−\mathrm{1}\right)!!}}=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 98166 by M±th+et+s last updated on 11/Jun/20 $$\underset{{x}\rightarrow\infty} {{lim}}\left[{cos}\left(\mathrm{2}\pi\left(\frac{{x}}{{x}+\mathrm{1}}\right)^{{a}} \right)\right]^{{x}^{\mathrm{2}} } \\ $$$${a}\in\mathbb{R} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 163690 by cortano1 last updated on 09/Jan/22 $$\:\:\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{cos}\:\mathrm{2}{x}\:\mathrm{cos}\:\mathrm{4}{x}\:\mathrm{cos}\:\mathrm{8}{x}\:−\:\mathrm{3}{x}\:\mathrm{csc}\:\mathrm{2}{x}}{\mathrm{2}{x}^{\mathrm{2}} }\:=? \\ $$ Answered by blackmamba last updated on 09/Jan/22 $$\:\:\mathcal{X}\:=\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{sin}\:\mathrm{2}{x}\:\mathrm{cos}\:\mathrm{2}{x}\:\mathrm{cos}\:\mathrm{4}{x}\:\mathrm{cos}\:\mathrm{8}{x}−\mathrm{3}{x}}{\mathrm{2}{x}^{\mathrm{2}} \:\mathrm{sin}\:\mathrm{2}{x}} \\…