Question Number 160995 by bobhans last updated on 10/Dec/21 $$\:\:\:\:\:\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\left(\mathrm{sin}\:\mathrm{2x}−\mathrm{2tan}\:\mathrm{x}\right)^{\mathrm{2}} +\left(\mathrm{1}−\mathrm{cos}\:\mathrm{2x}\right)^{\mathrm{3}} }{\mathrm{tan}\:^{\mathrm{7}} \mathrm{6x}\:+\mathrm{sin}\:^{\mathrm{6}} \mathrm{x}}=? \\ $$ Commented by blackmamba last updated on 11/Dec/21 $$\:\:\left(\bullet\right)\left(\mathrm{sin}\:\mathrm{2}{x}−\mathrm{2tan}\:{x}\right)^{\mathrm{2}}…
Question Number 29875 by tawa tawa last updated on 13/Feb/18 $$\mathrm{Prove}\:\mathrm{the}\:\mathrm{convergence}\:\mathrm{or}\:\mathrm{divergent}\:\mathrm{of}\:\:\:\:\:\:\:\:\:\:\left(\frac{\mathrm{n}\:−\:\mathrm{1}}{\mathrm{n}}\right)_{\mathrm{n}\:=\:\mathrm{1}} ^{\infty} \\ $$$$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 160937 by blackmamba last updated on 09/Dec/21 $$\:\:\:\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\left(\:\mathrm{sin}\:\sqrt{{x}^{\mathrm{2}} +\mathrm{1}}−\mathrm{sin}\:\sqrt{{x}^{\mathrm{2}} −\mathrm{1}}\:\right)=? \\ $$ Answered by aleks041103 last updated on 14/Dec/21 $${sin}\left({a}\right)−{sin}\left({b}\right)= \\ $$$$={sin}\left(\frac{{a}+{b}}{\mathrm{2}}+\frac{{a}−{b}}{\mathrm{2}}\right)−{sin}\left(\frac{{a}+{b}}{\mathrm{2}}−\frac{{a}−{b}}{\mathrm{2}}\right)=…
Question Number 95401 by john santu last updated on 25/May/20 $$\underset{\mathrm{n}\rightarrow\infty} {\mathrm{lim}n}^{\frac{\mathrm{3}}{\mathrm{2}}} \left\{\sqrt{\mathrm{n}+\mathrm{1}}+\sqrt{\mathrm{n}−\mathrm{1}}−\mathrm{2}\sqrt{\mathrm{n}}\:\right\}\: \\ $$ Answered by john santu last updated on 25/May/20 Commented by…
Question Number 160938 by cortano last updated on 09/Dec/21 $$\underset{{x}\rightarrow\frac{\pi}{\mathrm{2}}} {\mathrm{lim}}\:\left(\frac{\pi}{\mathrm{cos}\:\mathrm{x}}\:−\mathrm{2x}\:\mathrm{tan}\:\mathrm{x}\:\right)=? \\ $$ Answered by blackmamba last updated on 09/Dec/21 Terms of Service Privacy Policy…
Question Number 29845 by abdo imad last updated on 12/Feb/18 $${find}\:\:{lim}_{{x}\rightarrow\mathrm{0}} \:\:\:\:\:\:\frac{{tanx}\:−{x}−\frac{\mathrm{1}}{\mathrm{3}}{x}^{\mathrm{3}} }{{x}^{\mathrm{5}} }\:\:. \\ $$ Commented by Cheyboy last updated on 13/Feb/18 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{sec}^{\mathrm{2}}…
Question Number 160912 by cortano last updated on 09/Dec/21 $$\:\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{tan}\:\left(\mathrm{x}+\mathrm{2}\right)\mathrm{tan}\:\left(\mathrm{2}−\mathrm{x}\right)−\mathrm{tan}\:^{\mathrm{2}} \left(\mathrm{2}\right)}{\mathrm{3x}\:\mathrm{tan}\:\mathrm{x}}\:=? \\ $$ Answered by blackmamba last updated on 09/Dec/21 $$\:\begin{cases}{\mathrm{tan}\:\left({x}+\mathrm{2}\right)=\frac{\mathrm{tan}\:\mathrm{2}+\mathrm{tan}\:{x}}{\mathrm{1}−\mathrm{tan}\:\mathrm{2}\:\mathrm{tan}\:{x}}}\\{\mathrm{tan}\:\left(\mathrm{2}−{x}\right)=\frac{\mathrm{tan}\:\mathrm{2}−\mathrm{tan}\:{x}}{\mathrm{1}+\mathrm{tan}\:\mathrm{2}\:\mathrm{tan}\:{x}}}\\{\mathrm{tan}\:\left({x}+\mathrm{2}\right)\mathrm{tan}\:\left(\mathrm{2}−{x}\right)=\frac{\mathrm{tan}\:^{\mathrm{2}} \left(\mathrm{2}\right)−\mathrm{tan}\:^{\mathrm{2}} \left({x}\right)}{\mathrm{1}−\mathrm{tan}\:^{\mathrm{2}} \left(\mathrm{2}\right)\mathrm{tan}\:^{\mathrm{2}}…
Question Number 29836 by abdo imad last updated on 12/Feb/18 $${let}\:{give}\:{u}_{{n}} =\:\sum_{{q}=\mathrm{1}} ^{{n}} \:\frac{\mathrm{1}}{{n}^{\mathrm{2}} +{q}}\:\:{find}\:{lim}_{{n}\rightarrow+\infty} \left(\mathrm{1}−{nu}_{{n}} \right){n}. \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 95363 by john santu last updated on 24/May/20 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\frac{\left(\mathrm{x}!\right)^{\mathrm{2}} }{\left(\mathrm{2x}\right)!}\:=\:? \\ $$ Commented by john santu last updated on 24/May/20 Answered by…
Question Number 160885 by qaz last updated on 08/Dec/21 $$\underset{\mathrm{n}\rightarrow\infty} {\mathrm{lim}}\underset{\mathrm{k}=\mathrm{1}} {\overset{\mathrm{n}} {\sum}}\frac{\mathrm{n}+\frac{\mathrm{1}}{\mathrm{k}}}{\:\sqrt{\mathrm{n}^{\mathrm{2}} +\mathrm{k}^{\mathrm{2}} }}\centerdot\mathrm{sin}\:\frac{\mathrm{1}}{\mathrm{n}}=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com