Question Number 94679 by i jagooll last updated on 20/May/20 Commented by i jagooll last updated on 20/May/20 $$\mathrm{dear}\:\mathrm{tinkutara}\:\mathrm{sir}\:\mathrm{how}\:\mathrm{my}\:\mathrm{image}\:\mathrm{post}? \\ $$ Commented by i jagooll…
Question Number 160178 by cortano last updated on 25/Nov/21 $$\:\:\:\:\underset{{x}\rightarrow\pi} {\mathrm{lim}}\:\frac{\mathrm{sin}\:\frac{{x}}{\mathrm{2}}−\mathrm{1}}{\mathrm{cos}\:\left(\mathrm{sin}\:{x}\right)−\mathrm{1}}\:=? \\ $$ Commented by blackmamba last updated on 25/Nov/21 $$\:\:\:\:\:\:\:\:\underset{{x}\rightarrow\pi} {\mathrm{lim}}\:\frac{\mathrm{sin}\:\frac{{x}}{\mathrm{2}}−\mathrm{1}}{\mathrm{cos}\:\left(\mathrm{sin}\:{x}\right)−\mathrm{1}}\: \\ $$$$\:\:\:\:\:\:\:=\:\underset{{x}\rightarrow\pi} {\mathrm{lim}}\:\frac{\mathrm{sin}\:\frac{{x}}{\mathrm{2}}−\mathrm{1}}{−\mathrm{2sin}\:^{\mathrm{2}}…
Question Number 160142 by cortano last updated on 25/Nov/21 Answered by puissant last updated on 25/Nov/21 $$\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\frac{{x}^{\mathrm{1111}} +\mathrm{2}{x}^{\mathrm{2222}} −\mathrm{3}{x}^{\mathrm{3333}} }{{x}^{\mathrm{4444}} −\mathrm{1}}\: \\ $$$$=\:\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\frac{\frac{{d}}{{dx}}\left\{{x}^{\mathrm{1111}}…
Question Number 160080 by qaz last updated on 24/Nov/21 $$\underset{\mathrm{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{x}−\int_{\mathrm{0}} ^{\mathrm{x}} \mathrm{e}^{\mathrm{t}^{\mathrm{2}} } \mathrm{dt}}{\mathrm{x}\left(\mathrm{1}−\mathrm{cos}\:\mathrm{x}\right)}=? \\ $$ Answered by mr W last updated on 25/Nov/21…
Question Number 160077 by qaz last updated on 24/Nov/21 $$\underset{\mathrm{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\left(\frac{\mathrm{654}}{\mathrm{1}−\mathrm{x}^{\mathrm{654}} }−\frac{\mathrm{678}}{\mathrm{1}−\mathrm{x}^{\mathrm{678}} }\right)=? \\ $$ Commented by cortano last updated on 25/Nov/21 $$\:\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\:\left(\frac{\mathrm{654}}{\mathrm{1}−{x}^{\mathrm{654}} }\:−\:\frac{\mathrm{678}}{\mathrm{1}−{x}^{\mathrm{678}}…
Question Number 94528 by i jagooll last updated on 19/May/20 Commented by i jagooll last updated on 19/May/20 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\frac{{x}^{\mathrm{2}} \:\left\{\sqrt[{\mathrm{4}\:\:}]{\mathrm{1}−\frac{\mathrm{2}}{{x}}}−\mathrm{1}+\frac{\mathrm{2}}{{x}^{\mathrm{2}} }\right\}}{{x}^{\mathrm{2}} \left\{\mathrm{1}+\frac{\mathrm{1}}{{x}^{\mathrm{2}} }−\sqrt[{\mathrm{4}\:\:}]{\mathrm{16}+\frac{\mathrm{7}}{{x}^{\mathrm{7}} }}\right\}}\:=\:\mathrm{0}…
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Question Number 28982 by abdo imad last updated on 02/Feb/18 $${fnd}\:{the}\:{value}\:{of}\:\prod_{{n}=\mathrm{1}} ^{\infty} \:\:\:\frac{{n}^{\mathrm{2}} +\mathrm{1}}{{n}^{\mathrm{2}} }\:\:. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 28980 by abdo imad last updated on 02/Feb/18 $${prove}\:{that}\:{sin}\left(\pi{z}\right)=\pi{z}\:\prod_{{k}=\mathrm{1}} ^{\infty} \left(\mathrm{1}−\frac{{z}^{\mathrm{2}} }{{k}^{\mathrm{2}} }\right)\:\:{zfromC}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 28892 by abdo imad last updated on 31/Jan/18 $${find}\:{lim}_{{x}\rightarrow\mathrm{0}} \:\:\frac{\mathrm{1}}{{x}}{ln}\left(\frac{{e}^{{x}} −\mathrm{1}}{{x}}\right)\:. \\ $$ Answered by ajfour last updated on 01/Feb/18 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{1}}{{x}}\mathrm{ln}\:\left(\frac{{x}+\frac{{x}^{\mathrm{2}} }{\mathrm{2}}+\frac{{x}^{\mathrm{3}}…