Question Number 28770 by Rasheed.Sindhi last updated on 30/Jan/18 $$\underset{{x}\rightarrow+\infty} {{lim}}\:\frac{\mathrm{5}{x}^{\mathrm{4}} −\mathrm{10}{x}^{\mathrm{2}} +\mathrm{1}}{−\mathrm{3}{x}^{\mathrm{3}} +\mathrm{10}{x}^{\mathrm{2}} +\mathrm{50}} \\ $$ Commented by Cheyboy last updated on 30/Jan/18 $$\underset{{x}\rightarrow+\infty\:}…
Question Number 159837 by tounghoungko last updated on 21/Nov/21 $$\:\:\underset{{x}\rightarrow−\infty} {\mathrm{lim}}\:\sqrt{\mathrm{2021}{x}^{\mathrm{2}} −\mathrm{6}{x}}\:+\sqrt[{\mathrm{3}}]{\mathrm{1021}{x}^{\mathrm{3}} −\mathrm{5}{x}}\:=? \\ $$ Answered by kaivan.ahmadi last updated on 24/Nov/21 $$\sim{lim}\sqrt{\mathrm{2021}}\mid{x}−\frac{−\mathrm{6}}{\mathrm{2}×\mathrm{2021}}\mid+\sqrt[{\mathrm{3}}]{\mathrm{1021}}\mid{x}\mid= \\ $$$${lim}\sqrt{\mathrm{2021}}\left(−{x}−\frac{\mathrm{3}}{\mathrm{2021}}\right)−\sqrt[{\mathrm{3}}]{\mathrm{1021}}{x}=+\infty…
Question Number 159796 by Ar Brandon last updated on 21/Nov/21 $$\mathrm{Montrer}\:\mathrm{que}\:\mathrm{la}\:\mathrm{suite}\:\mathrm{d}\acute {\mathrm{e}finie}\:\mathrm{par}\: \\ $$$${u}_{{n}} =\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\frac{{x}^{{k}} }{{k}}\:\mathrm{est}\:\mathrm{une}\:\mathrm{suite}\:\mathrm{de}\:\mathrm{Cauchy}. \\ $$ Answered by alcohol last updated…
Question Number 94273 by Cheyboy last updated on 17/May/20 Commented by Cheyboy last updated on 17/May/20 $$\boldsymbol{{PLEASE}}\:\boldsymbol{{HELP}}\:\:!! \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 28698 by Rasheed.Sindhi last updated on 29/Jan/18 $$\frac{\infty}{\mathrm{negative}\:\mathrm{number}}=? \\ $$$$\:\infty\:\:\:\:\:\:\:\:\:\:\mathrm{or}\:\:\:\:\:\:\:\:\:−\infty\:\:? \\ $$ Commented by prakash jain last updated on 29/Jan/18 $$−\infty \\ $$$$\underset{{x}\rightarrow\mathrm{0}^{−}…
Question Number 28684 by abdo imad last updated on 28/Jan/18 $${find}\:\:{sum}\:{of}\:{S}\left({x}\right)=\:\sum_{{n}=\mathrm{1}} ^{\infty} \:\left(−\mathrm{1}\right)^{{n}−\mathrm{1}} \:\:\frac{{x}^{\mathrm{2}{n}+\mathrm{1}} }{\mathrm{4}{n}^{\mathrm{2}} −\mathrm{1}}\:. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 28681 by abdo imad last updated on 28/Jan/18 $${give}\:{a}\:{equivalent}\:{of}\:\:{w}_{{n}} =\:\:\:\sum_{{k}={n}+\mathrm{1}} ^{\infty} \:\:\frac{\mathrm{1}}{{k}!}\:\:. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 28682 by abdo imad last updated on 28/Jan/18 $${nature}\:{of}\:{the}\:{serie}\:\:\sum_{{n}=\mathrm{0}} ^{\infty} \:{tan}\left(\frac{\mathrm{2}{n}+\mathrm{1}}{{n}^{\mathrm{3}} }\right)\:. \\ $$ Commented by abdo imad last updated on 30/Jan/18 $${let}\:{put}\:{u}_{{n}}…
Question Number 159754 by cortano last updated on 20/Nov/21 $$\:\:\:\:\:\underset{{x}\rightarrow\mathrm{0}^{+} } {\mathrm{lim}}\:\frac{\sqrt{\mathrm{tan}\:{x}}\:+\:\sqrt{\mathrm{sin}\:{x}}\:−\mathrm{2}\sqrt{{x}}}{\:\sqrt{\mathrm{sin}\:{x}}\:−\:\sqrt{\mathrm{tan}\:{x}}\:}\:=\:? \\ $$ Answered by bobhans last updated on 21/Nov/21 $$\:\:\:\:\underset{{x}\rightarrow\mathrm{0}^{+} } {\mathrm{lim}}\:\frac{\sqrt{\mathrm{tan}\:\mathrm{x}}\:+\sqrt{\mathrm{sin}\:\mathrm{x}}−\mathrm{2}\sqrt{\mathrm{x}}}{\:\sqrt{\mathrm{sin}\:\mathrm{x}}−\sqrt{\mathrm{tan}\:\mathrm{x}}}\: \\…
Question Number 159740 by mathlove last updated on 20/Nov/21 Terms of Service Privacy Policy Contact: info@tinkutara.com