Question Number 157647 by wendjudi last updated on 26/Oct/21 $${bonjour}\:,{calculer}\:{la}\:{limite}\:{suivante}\:{en}\:{utilisant}\:{les}\:{developpements}\:{limites}: \\ $$$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\left(\frac{\mathrm{1}}{{x}^{\mathrm{2}} }\:−\:\frac{\mathrm{1}}{\mathrm{sin}^{\mathrm{2}} {x}}\right). \\ $$ Commented by cortano last updated on 26/Oct/21 $$\:\underset{{x}\rightarrow\mathrm{0}}…
Question Number 26572 by abdo imad last updated on 26/Dec/17 $${find}\:{the}\:{radius}\:{ofconvergence}\:{for}\:{the}\:{serie} \\ $$$$\sum_{{n}\geqslant\mathrm{0}} \left(\:{e}^{\sqrt{{n}+\mathrm{1}}} −{e}^{\sqrt{{n}}} \right){z}^{{n}} \:\:\:\:\:\:{with}\:{z}\:{from}\:\mathbb{C} \\ $$$$ \\ $$ Terms of Service Privacy…
Question Number 26573 by abdo imad last updated on 26/Dec/17 $${let}\:{put}\:\:{H}_{{n}} =\:\sum_{{k}=\mathrm{1}} ^{{k}={n}} \:\:\frac{\mathrm{1}}{{k}}\:\:\:\:\:\:{prove}\:{that}\:\:\:\sum_{{n}=\mathrm{1}} ^{\propto} \:\frac{{H}_{{n}} }{{n}^{\mathrm{2}} }\:\:=\:\:\mathrm{2}\xi\left(\mathrm{3}\right) \\ $$ Terms of Service Privacy Policy…
Question Number 26568 by abdo imad last updated on 26/Dec/17 $${let}\:{give}\:\xi\left({x}\right)=\:\sum_{{n}=\mathrm{1}} ^{\propto} \frac{\mathrm{1}}{{n}^{{x}} }\:\:{prove}\:{that}\:\xi\left({x}\right)−_{{x}−>\propto} \mathrm{1}\sim\mathrm{2}^{−{x}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 26567 by abdo imad last updated on 26/Dec/17 $${find}\:{the}\:{value}\:{of}\:\:\:\sum_{{n}\geqslant\mathrm{2}} \:\frac{\left(−\right)^{{n}} }{{n}\left({n}−\mathrm{1}\right)}\:{x}^{{n}} \\ $$ Commented by prakash jain last updated on 27/Dec/17 $${a}_{{n}} =\frac{\left(−\mathrm{1}\right)^{{n}+\mathrm{1}}…
Question Number 26565 by abdo imad last updated on 26/Dec/17 $${find}\:{the}\:{value}\:{of}\:\:\:\sum_{{n}=\mathrm{0}} ^{\propto} \:\:\frac{\left(−\mathrm{1}\right)^{{n}} }{\mathrm{3}{n}+\mathrm{1}} \\ $$ Commented by abdo imad last updated on 29/Dec/17 $${let}\:{put}\:\:{s}\left({x}\right)=\:\:\sum_{{n}=\mathrm{0}}…
Question Number 26534 by chernoaguero@gmail.com last updated on 26/Dec/17 $$\mathrm{Find}\:\:\mathrm{the} \\ $$$$\underset{\theta\rightarrow\mathrm{0}} {\mathrm{lim}}\:\:\frac{\mathrm{3}^{\mathrm{sin}\:\theta} −\mathrm{1}}{\theta} \\ $$ Commented by kaivan.ahmadi last updated on 26/Dec/17 $$\mathrm{hop} \\…
Question Number 92056 by john santu last updated on 04/May/20 $$\underset{{x}\rightarrow\mathrm{0}^{+} } {\mathrm{lim}}\:\frac{\mathrm{ln}\left({x}\right)}{\mathrm{cot}\:{x}} \\ $$ Commented by Prithwish Sen 1 last updated on 05/May/20 $$\underset{\mathrm{x}\rightarrow\mathrm{0}}…
Question Number 157591 by cortano last updated on 25/Oct/21 $$\:\underset{{x}\rightarrow\pi} {\mathrm{lim}}\:\left(\left({x}−\pi\right)^{\mathrm{2}} \mathrm{cos}\:\left(\frac{\mathrm{1}}{{x}−\pi}\right)+{x}^{\mathrm{4}} +\mathrm{sin}\:^{\mathrm{3}} {x}\right)=? \\ $$ Answered by Lordose last updated on 25/Oct/21 $$\boldsymbol{\pi}^{\mathrm{4}} \\…
Question Number 92032 by M±th+et+s last updated on 04/May/20 $$\underset{{x}\rightarrow\infty} {{lim}}\frac{\mathrm{2}^{\mathrm{4}{n}−\mathrm{1}} \ast\left({n}!\right)^{\mathrm{2}} }{\left(\mathrm{2}{n}+\mathrm{1}\right)\ast\left[\mathrm{2}{n}\:{p}\left({n}\right)\right]^{\mathrm{2}} } \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com