Question Number 6703 by love math last updated on 15/Jul/16 $$\underset{\mathrm{x}\rightarrow\mathrm{0}} {\mathrm{l}im}\frac{{x}−\mathrm{sin}\:{x}}{{x}^{\mathrm{2}} \left({e}^{{x}} −\mathrm{1}\right)} \\ $$ Answered by FilupSmith last updated on 15/Jul/16 $${L}=\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{{x}−\mathrm{sin}\:{x}}{{x}^{\mathrm{2}}…
Question Number 6689 by Tawakalitu. last updated on 13/Jul/16 $${limit}\:\:\:\:\:\:\:\:\:\:\:\mathrm{1}\:+\:\frac{\mathrm{1}}{\mathrm{1}\:−\:{x}} \\ $$$${x}\:\dashrightarrow\:\infty \\ $$ Answered by FilupSmith last updated on 14/Jul/16 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\mathrm{1}+\frac{\mathrm{1}}{\mathrm{1}−{x}}\:=\:\mathrm{1}+\frac{\mathrm{1}}{\mathrm{1}−\infty} \\ $$$$=\mathrm{1}−\frac{\mathrm{1}}{\infty}…
Question Number 6692 by Tawakalitu. last updated on 14/Jul/16 $${limit}\:\:\:\:\:\:\:\:\mathrm{1}\:+\:\frac{\mathrm{1}}{{x}\:−\:\mathrm{1}} \\ $$$${x}\:\rightarrow\:\infty \\ $$ Answered by FilupSmith last updated on 14/Jul/16 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\mathrm{1}+\frac{\mathrm{1}}{{x}−\mathrm{1}}=\mathrm{1}+\frac{\mathrm{1}}{\infty−\mathrm{1}} \\ $$$$=\mathrm{1}+\frac{\mathrm{1}}{\infty}…
Question Number 72218 by aliesam last updated on 26/Oct/19 Commented by turbo msup by abdo last updated on 26/Oct/19 $${let}\:{A}\left({x}\right)=\left(\frac{{sinx}}{{x}}\right)^{\frac{\mathrm{1}}{{x}^{\mathrm{2}} }} \:\Rightarrow \\ $$$${A}\left({x}\right)={e}^{\frac{\mathrm{1}}{{x}^{\mathrm{2}} }{ln}\left(\frac{{sinx}}{{x}}\right)}…
Question Number 137737 by bemath last updated on 06/Apr/21 $$\underset{{x}\rightarrow−\infty} {\mathrm{lim}}\:\frac{\mathrm{3}^{{x}} −\mathrm{3}^{−{x}} }{\mathrm{3}^{{x}} +\mathrm{3}^{−{x}} }\:=? \\ $$$$ \\ $$ Answered by greg_ed last updated on…
Question Number 6668 by janzmir6996 last updated on 10/Jul/16 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}cos}\:\mathrm{2}{x}/\mathrm{sin}\:{x}\mathrm{2} \\ $$ Commented by Rasheed Soomro last updated on 10/Jul/16 $${Do}\:{you}\:{mean}\:\:\:\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\:\mathrm{cos}\:\mathrm{2}{x}/\mathrm{sin}\:{x}^{\mathrm{2}} \:\:\:? \\…
Question Number 72071 by aliesam last updated on 23/Oct/19 $$\left.{a}\right)\underset{{x}\rightarrow\mathrm{0}} {\:{lim}}\frac{\mathrm{3}{x}−{sin}\left(\mathrm{2}{x}\right)}{\mathrm{2}{x}−{sin}\left(\mathrm{3}{x}\right)} \\ $$$$ \\ $$$$ \\ $$ Commented by mathmax by abdo last updated on…
Question Number 71991 by ozodbek last updated on 23/Oct/19 Answered by mind is power last updated on 23/Oct/19 $$\mathrm{worcking}\:\mathrm{for}\:\mathrm{this}\:\mathrm{one} \\ $$$$ \\ $$ Terms of…
Question Number 137482 by Algoritm last updated on 03/Apr/21 Answered by MJS_new last updated on 03/Apr/21 $$\mathrm{0} \\ $$ Commented by Algoritm last updated on…
Question Number 6407 by FilupSmith last updated on 26/Jun/16 $$\mathrm{Can}\:\mathrm{you}\:\mathrm{evaluate}: \\ $$$$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\left(−\mathrm{1}\right)^{{x}} {x} \\ $$$$ \\ $$$$\mathrm{WolframAlpha}\:\mathrm{writes}\:\mathrm{the}\:\mathrm{answer}\:\mathrm{as} \\ $$$$={e}^{\mathrm{2}{i}\:\:\mathrm{to}\:\:\pi} \infty \\ $$ Commented by…