Question Number 71216 by TawaTawa last updated on 13/Oct/19 Answered by mind is power last updated on 13/Oct/19 $$\Sigma\frac{\mathrm{n}^{\mathrm{2}} +\mathrm{x}}{\mathrm{n}!}=\Sigma\frac{\mathrm{n}^{\mathrm{2}} }{\mathrm{n}!}+\mathrm{x}\Sigma\frac{\mathrm{1}}{\mathrm{n}!} \\ $$$$\underset{\mathrm{n}\geqslant\mathrm{0}} {\sum}\frac{\mathrm{n}^{\mathrm{2}} }{\mathrm{n}!}=\mathrm{1}+\sum_{\mathrm{n}\geqslant\mathrm{2}}…
Question Number 136758 by mathlove last updated on 25/Mar/21 $$\:\:\mathrm{1}==>\:\:\:\:\:\underset{{x}\rightarrow\infty} {\mathrm{lim}}\left(\frac{\mathrm{1}}{\pi}+\frac{\mathrm{1}}{\pi^{\mathrm{2}} }+\frac{\mathrm{1}}{\pi^{\mathrm{3}} }+\centerdot\centerdot\centerdot+\frac{\mathrm{1}}{\pi^{{n}} }\right)=? \\ $$$$ \\ $$$$\:\mathrm{2}=>\underset{{x}\rightarrow\infty} {\mathrm{lim}}\frac{\mathrm{1}+\mathrm{2}^{\mathrm{2}} +\mathrm{3}^{\mathrm{2}} +\centerdot\centerdot\centerdot\centerdot+{n}^{\mathrm{2}} }{\mathrm{1}−{n}^{\mathrm{3}} }=? \\ $$…
Question Number 5637 by sanusihammed last updated on 23/May/16 $${Limit}\:\:\:\left[\frac{\mathrm{3}^{{n}+\mathrm{1}} \:−\:\mathrm{5}^{{n}+\mathrm{1}} }{\mathrm{3}^{{n}} \:−\:\mathrm{5}^{{n}} }\right] \\ $$$${x}\rightarrow\infty \\ $$$$ \\ $$$$ \\ $$$${Please}\:{help}.\:{Thanks} \\ $$ Answered…
Question Number 136700 by mathlove last updated on 25/Mar/21 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\frac{{n}^{{n}} +\mathrm{3}^{{n}} }{\mathrm{10}^{{n}} +\mathrm{3}^{{n}} }=? \\ $$ Commented by mathlove last updated on 25/Mar/21 $${thanks}…
Question Number 136701 by mathlove last updated on 25/Mar/21 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\frac{\mathrm{3}^{{n}} −{n}!}{\mathrm{2}^{{n}} −{n}!}=? \\ $$ Commented by yutytfjh67ihd last updated on 25/Mar/21 Commented by mathlove…
Question Number 5616 by sanusihammed last updated on 22/May/16 $${Find}\: \\ $$$$ \\ $$$$\left[\mathrm{1}\:+\:\mathrm{3}{n}^{−\mathrm{1}} \right]^{{n}} \\ $$$$ \\ $$$${Limit}\:{as}\:{n}\:\rightarrow\infty \\ $$$$ \\ $$$$ \\ $$$${Please}\:{help}.…
Question Number 136670 by rexford last updated on 24/Mar/21 Answered by Dwaipayan Shikari last updated on 24/Mar/21 $$\mathrm{0} \\ $$ Answered by MJS_new last updated…
Question Number 5593 by sanusihammed last updated on 21/May/16 $${Find}\:{the}\:{limit} \\ $$$$ \\ $$$${limit}\:\:\:\:\:\:\:\left[\mathrm{1}\:+\:{mt}\right]^{\frac{\mathrm{2}}{{t}}} \\ $$$${t}\:\rightarrow\infty \\ $$ Answered by FilupSmith last updated on 21/May/16…
Question Number 71096 by Omer Alattas last updated on 11/Oct/19 Answered by $@ty@m123 last updated on 11/Oct/19 $${Let}\:{x}=\mathrm{1}+{y} \\ $$$$\underset{{y}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\:\:\:\frac{{y}}{\mathrm{ln}\:\left(\mathrm{1}+{y}\right)} \\ $$$$\:\:\frac{\mathrm{1}}{\underset{{y}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{ln}\:\left(\mathrm{1}+{y}\right)}{{y}}}=\mathrm{1} \\…
Question Number 136594 by slahadjb last updated on 23/Mar/21 $${li}\underset{\mathrm{0}^{+} } {{m}}\frac{{x}^{{x}^{{x}} } }{{x}^{{x}} −\mathrm{1}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com