Question Number 64253 by Jameel Ahmad last updated on 16/Jul/19 Commented by ajfour last updated on 16/Jul/19 $${Nobel}\:{laurettes},\:{i}\:{think}! \\ $$ Terms of Service Privacy Policy…
Question Number 129731 by Adel last updated on 18/Jan/21 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}cos}\:\frac{\mathrm{x}}{\mathrm{2}}×\mathrm{cos}\:\frac{\mathrm{x}}{\mathrm{4}}…….\mathrm{cos}\:\frac{\mathrm{x}}{\mathrm{2}^{\mathrm{n}} }=? \\ $$ Answered by Dwaipayan Shikari last updated on 18/Jan/21 $${cos}\frac{{x}}{\mathrm{2}}=\frac{{sinx}}{\mathrm{2}{sin}\frac{{x}}{\mathrm{2}}} \\ $$$$\underset{{n}=\mathrm{1}}…
Question Number 129723 by Adel last updated on 18/Jan/21 $$\underset{{x}\rightarrow\mathrm{100}} {\mathrm{lim}}\left[\left(\mathrm{x}^{\mathrm{100}} −\mathrm{100}^{\mathrm{x}} \right)\frac{\mathrm{1}}{\mathrm{100}−\mathrm{x}}\right]=? \\ $$$$\mathcal{DANISH} \\ $$ Answered by bramlexs22 last updated on 18/Jan/21 $$\:\underset{{x}\rightarrow\mathrm{100}}…
Question Number 129683 by Adel last updated on 17/Jan/21 Commented by Adel last updated on 17/Jan/21 $$ \\ $$When we use antigral in the limit…
Question Number 129655 by liberty last updated on 17/Jan/21 $$\:\:\underset{{x}\rightarrow\infty} {\mathrm{lim}}\left(\mathrm{log}\:_{{x}} \left(\mathrm{2021}{x}\right)\right)^{\mathrm{log}\:{x}} \:=? \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\lceil\ast\rceil\left(\sqrt{\pi^{\ell\mathrm{iberty}} }\:\right) \\ $$ Answered by bemath last updated on 17/Jan/21…
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Question Number 129584 by bemath last updated on 16/Jan/21 $$\:\:\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\left(\mathrm{sin}\:\mathrm{x}\right)\left(\mathrm{arctan}\:\mathrm{x}\right)−\mathrm{x}^{\mathrm{2}} }{\mathrm{1}−\mathrm{cos}\:\left(\mathrm{x}^{\mathrm{2}} \right)}=? \\ $$ Answered by liberty last updated on 16/Jan/21 $$\:\:\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\left(\mathrm{x}−\frac{\mathrm{x}^{\mathrm{3}} }{\mathrm{6}}+\frac{\mathrm{x}^{\mathrm{5}}…
Question Number 129587 by Adel last updated on 16/Jan/21 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\left(\mathrm{1}−\frac{\mathrm{1}}{\mathrm{x}}\right)^{\mathrm{x}} =? \\ $$ Answered by Dwaipayan Shikari last updated on 16/Jan/21 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\left(\mathrm{1}−\frac{\mathrm{1}}{{x}}\right)^{{x}} =\underset{{x}\rightarrow\infty}…
Question Number 64047 by aliesam last updated on 12/Jul/19 Commented by mathmax by abdo last updated on 12/Jul/19 $${we}\:{have}\:{x}_{\mathrm{0}} =\mathrm{1}\:{and}\:{x}_{{n}+\mathrm{1}} =\frac{\mathrm{3}+\mathrm{2}{x}_{{n}} }{\mathrm{3}+{x}_{{n}} }\:\Rightarrow{x}_{{n}+\mathrm{1}} ={f}\left({x}_{{n}} \right)\:{with}…
Question Number 129510 by Adel last updated on 16/Jan/21 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\left(\mathrm{cos}\:\mathrm{x}\right)^{\mathrm{log}\:\mathrm{x}} =? \\ $$ Commented by mr W last updated on 16/Jan/21 $$\Rightarrow{Q}\mathrm{129387} \\ $$…