Question Number 115551 by bemath last updated on 26/Sep/20 $$\underset{{x}\rightarrow\mathrm{2}} {\mathrm{lim}}\:\frac{\sqrt[{\mathrm{4}\:}]{{x}^{\mathrm{4}} −\mathrm{4}{x}^{\mathrm{3}} +\mathrm{5}{x}^{\mathrm{2}} −\mathrm{4}{x}+\mathrm{4}}}{\:\sqrt{{x}^{\mathrm{2}} −\mathrm{3}{x}+\mathrm{2}}}\:=\:? \\ $$ Answered by TANMAY PANACEA last updated on 26/Sep/20…
Question Number 115541 by bobhans last updated on 26/Sep/20 $$\:\underset{{x}\rightarrow{a}} {\mathrm{lim}}\:\left(\mathrm{2}−\frac{{x}}{{a}}\right)^{\mathrm{tan}\:\left(\frac{\pi{x}}{\mathrm{2}{a}}\right)} =? \\ $$ Answered by bemath last updated on 26/Sep/20 $${L}\:=\:\underset{{x}\rightarrow{a}} {\mathrm{lim}}\:\left(\mathrm{2}−\frac{{x}}{{a}}\right)^{\mathrm{tan}\:\left(\frac{\pi{x}}{\mathrm{2}{a}}\right)} \\ $$$$\mathrm{ln}\:{L}=\underset{{x}\rightarrow{a}}…
Question Number 49927 by Abdo msup. last updated on 12/Dec/18 $${find}\:{lim}_{{x}\rightarrow{a}^{+} } \:\:\:\:\left({x}−{a}\right)\left({a}^{{x}} −{x}^{{a}} \right)\:\:\:{with}\:{a}>\mathrm{0}\:. \\ $$ Commented by afachri last updated on 12/Dec/18 $$\mathrm{i}\:\mathrm{found}\:\mathrm{0}\:,\mathrm{Sir}.\:…
Question Number 49817 by Aditya789 last updated on 11/Dec/18 $$\mathrm{prove}\:\mathrm{that}.\:\frac{\mathrm{a}^{\mathrm{r}} −\mathrm{1}}{\mathrm{r}}=\mathrm{1} \\ $$ Commented by tanmay.chaudhury50@gmail.com last updated on 11/Dec/18 $${what}\:{is}\:{the}\:{relation}\:{between}\:{a}\:{and}\:{r}…{question} \\ $$$${not}\:{clear}… \\ $$…
Question Number 49803 by maxmathsup by imad last updated on 10/Dec/18 $${find}\:{lim}_{{x}\rightarrow\mathrm{0}^{+} } \:\:\:\:\frac{\left({sinx}\right)^{{x}} \:−\mathrm{1}}{{x}^{{sinx}} \:−\mathrm{1}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 49802 by maxmathsup by imad last updated on 10/Dec/18 $${find}\:{lim}_{{x}\rightarrow{e}} \:\:\:\frac{{e}^{{x}} \:−{e}^{{e}} }{{x}^{{e}} \:−{e}^{{e}} } \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on…
Question Number 49800 by maxmathsup by imad last updated on 10/Dec/18 $${find}\:{lim}_{{x}\rightarrow\mathrm{0}} \:\:\:\frac{\sqrt{\mathrm{1}+{x}+{x}^{\mathrm{2}} }−\sqrt{\mathrm{1}+\mathrm{2}{x}+{x}^{\mathrm{3}} }}{{x}^{\mathrm{2}} } \\ $$ Answered by afachri last updated on 12/Dec/18…
Question Number 115320 by john santu last updated on 25/Sep/20 $$\left(\mathrm{1}\right)\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{1}−\mathrm{cos}\:^{\mathrm{6}} \left(\mathrm{2}{x}\right)\mathrm{cos}\:^{\mathrm{3}} \left(\mathrm{3}{x}\right)}{\mathrm{3}{x}^{\mathrm{2}} }\:? \\ $$$$\left(\mathrm{2}\right)\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{1}−\mathrm{cos}\:\mathrm{4}{x}+\mathrm{2sin}\:^{\mathrm{2}} {x}.\mathrm{cos}\:\mathrm{4}{x}}{{x}^{\mathrm{2}} .\mathrm{cos}\:\mathrm{3}{x}}? \\ $$$$\left(\mathrm{3}\right)\:\underset{{x}\rightarrow\frac{\pi}{\mathrm{2}}} {\mathrm{lim}}\:\frac{\mathrm{sin}\:{x}−\mathrm{2cos}\:^{\mathrm{2}} {x}−\mathrm{1}}{\:\sqrt{\mathrm{sin}\:^{\mathrm{3}} {x}}−\sqrt{\mathrm{sin}\:{x}}}\:?\:…
Question Number 115318 by bemath last updated on 25/Sep/20 $$\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{{x}\mathrm{sin}\:{x}}{\mathrm{2sin}\:^{\mathrm{2}} \left(\mathrm{3}{x}\right)−{x}^{\mathrm{2}} \mathrm{cos}\:{x}} \\ $$ Answered by bobhans last updated on 25/Sep/20 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{{x}\:\mathrm{sin}\:{x}}{\mathrm{2}\:\mathrm{sin}\:^{\mathrm{2}} \left(\mathrm{3}{x}\right)−{x}^{\mathrm{2}}…
Question Number 180815 by mnjuly1970 last updated on 17/Nov/22 Terms of Service Privacy Policy Contact: info@tinkutara.com