Category: Mensuration

Question Number 224324 by fantastic last updated on 03/Sep/25 Answered by fantastic last updated on 03/Sep/25 Commented by fantastic last updated on 05/Sep/25 $${Area}\:{EFHJ}={AGHJE}−{AGHF}−{AEF} \\…

Question Number 224255 by fantastic last updated on 30/Aug/25 Commented by fantastic last updated on 30/Aug/25 $$\bigtriangleup{ABC}=? \\ $$ Commented by fantastic last updated on…

Question Number 224121 by fantastic last updated on 21/Aug/25 Answered by mr W last updated on 21/Aug/25 $${R}=\frac{\mathrm{1}}{\mathrm{2}\sqrt{\frac{\mathrm{1}}{\mathrm{10}×\mathrm{3}}+\frac{\mathrm{1}}{\mathrm{3}×\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{2}×\mathrm{10}}}−\frac{\mathrm{1}}{\mathrm{10}}−\frac{\mathrm{1}}{\mathrm{3}}−\frac{\mathrm{1}}{\mathrm{2}}}=\mathrm{15} \\ $$$$\pi{R}^{\mathrm{2}} =\mathrm{225}\pi\:\checkmark \\ $$ Commented by…

Question Number 224118 by fantastic last updated on 21/Aug/25 Answered by mr W last updated on 22/Aug/25 $${R}=\mathrm{12} \\ $$$$\mathrm{2}{b}={R}\:\Rightarrow{b}=\frac{{R}}{\mathrm{2}} \\ $$$$\left({a}+{b}\right)^{\mathrm{2}} ={b}^{\mathrm{2}} +\left({R}−{a}\right)^{\mathrm{2}} \\…

Question Number 223887 by fantastic last updated on 08/Aug/25 Commented by fantastic last updated on 08/Aug/25 $${can}\:{this}\:{be}\:{solved}\:{without}\:{any}\:{assumption}\left({s}\right)? \\ $$ Commented by Frix last updated on…