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Question Number 193448 by Mingma last updated on 14/Jun/23 Answered by cherokeesay last updated on 14/Jun/23 Commented by Mingma last updated on 14/Jun/23 Perfect �� Terms…
Question Number 193398 by Mingma last updated on 12/Jun/23 Answered by Subhi last updated on 13/Jun/23 $$ \\ $$$${put}\:\left({F}\hat {{C}E}\right)={y}=\left({C}\hat {{E}F}\right) \\ $$$$\left({F}\hat {{E}D}\right)=\left({F}\hat {{D}E}\right)=\left({E}\hat…
Question Number 193387 by Mingma last updated on 12/Jun/23 Commented by Frix last updated on 12/Jun/23 $$\mathrm{The}\:\mathrm{circle}\:\mathrm{is}\:\mathrm{the}\:\mathrm{circumcircle}\:\mathrm{of}\:\mathrm{a}\:\mathrm{triangle}: \\ $$$${a}=\mathrm{6} \\ $$$${b}=\mathrm{6}\sqrt{\mathrm{7}} \\ $$$${c}=\mathrm{18} \\ $$$$\Rightarrow…
Question Number 193199 by mnjuly1970 last updated on 07/Jun/23 $$ \\ $$$$\:\:\:{a}_{\mathrm{1}} \:,\:{a}_{\mathrm{2}} \:,…,{a}_{{n}} \:{are}\:\:{mutually}\:{distinct} \\ $$$$\:\:{and}\:{is}\:{a}\:\:\:\:{am}\:\:{sequence}\:. \\ $$$$\:\:\:{if}\:{a}_{\:\mathrm{1}} \:+{a}_{\:\mathrm{2}} \:+…+{a}_{{n}} \:={A} \\ $$$$\:\:\:{and}\:\: \\…
Question Number 193198 by Mingma last updated on 07/Jun/23 Answered by HeferH last updated on 07/Jun/23 Commented by HeferH last updated on 07/Jun/23 $${x}=\mathrm{60}°−\mathrm{30}°=\mathrm{30}° \\…
Question Number 193149 by Mingma last updated on 04/Jun/23 Answered by ajfour last updated on 05/Jun/23 $$\frac{\sqrt{\mathrm{3}}}{\mathrm{4}}{p}^{\mathrm{2}} ={A} \\ $$$${p}={k}\sqrt{{A}}\:\:\:\:{where}\:\:\:{k}^{\mathrm{2}} =\frac{\mathrm{4}}{\:\sqrt{\mathrm{3}}} \\ $$$${q}={k}\sqrt{{B}} \\ $$$${B}=\mathrm{9}{A}…
Question Number 193105 by Mingma last updated on 04/Jun/23 Commented by Mingma last updated on 04/Jun/23 Find x Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 193161 by Mingma last updated on 05/Jun/23 Answered by a.lgnaoui last updated on 05/Jun/23 $$\mathrm{Triangle}\:\mathrm{ABC}\:\:\mathrm{equilaterale}\: \\ $$$$\boldsymbol{\mathrm{MN}}=\boldsymbol{\mathrm{NP}}=\boldsymbol{\mathrm{MP}} \\ $$$$\measuredangle\mathrm{BAH}=\mathrm{60}=\measuredangle\mathrm{DAH} \\ $$$$\Rightarrow\:\measuredangle\mathrm{ADH}=\mathrm{30}°\:\:\:\measuredangle\mathrm{AMN}=\mathrm{90}−\mathrm{30}=\mathrm{60} \\ $$$$\mathrm{MNP}\:\:\:\mathrm{Triangle}\:\mathrm{equilaterale}…
Question Number 193153 by wizzy1 last updated on 04/Jun/23 Terms of Service Privacy Policy Contact: info@tinkutara.com