Category: Mensuration

Question Number 185851 by Mingma last updated on 28/Jan/23 Commented by Mingma last updated on 28/Jan/23 Diameter in relation to a,b,c ? Answered by mr W last updated on 28/Jan/23…

Question Number 185800 by Rupesh123 last updated on 27/Jan/23 Answered by ajfour last updated on 27/Jan/23 $${let}\:{center}\:{of}\:{small}\:{circle}\:\left(−{h},−{k}\right) \\ $$$${hence}\:{eq}.\:\:\:\left({x}+{h}\right)^{\mathrm{2}} +\left({y}+{k}\right)^{\mathrm{2}} ={r}^{\mathrm{2}} \\ $$$${side}\:{of}\:{eql}.\:\:{triangle}\:{a}={R}\sqrt{\mathrm{3}} \\ $$$${length}\:{of}\:{tangent}\:{from}\:{A}\left(\mathrm{0},{R}\right)…

Question Number 185705 by Mingma last updated on 26/Jan/23 Answered by mr W last updated on 26/Jan/23 $${s}=\frac{{n}−\mathrm{1}+{n}+{n}+\mathrm{1}}{\mathrm{2}}=\frac{\mathrm{3}{n}}{\mathrm{2}} \\ $$$$\overset{\_} {{r}}=\frac{{rs}}{{s}−{n}}=\frac{{r}}{\mathrm{1}−\frac{{n}}{{s}}}=\frac{{r}}{\mathrm{1}−\frac{\mathrm{2}{n}}{\mathrm{3}{n}}}=\mathrm{3}{r} \\ $$$$\frac{{r}}{\overset{\_} {{r}}}=\frac{\mathrm{1}}{\mathrm{3}}\:\checkmark \\…

Question Number 185494 by Mingma last updated on 22/Jan/23 Commented by mr W last updated on 23/Mar/24 $${see}\:{Q}\mathrm{205507} \\ $$ Terms of Service Privacy Policy…

Question Number 185387 by Rupesh123 last updated on 20/Jan/23 Answered by HeferH last updated on 21/Jan/23 Commented by HeferH last updated on 21/Jan/23 $${x}\:=\:\sqrt{\left(\mathrm{4}−{r}\right)^{\mathrm{2}} −{r}^{\mathrm{2}}…