Question Number 48982 by peter frank last updated on 30/Nov/18 Answered by tanmay.chaudhury50@gmail.com last updated on 01/Dec/18 $$\left.\mathrm{2}\right)\frac{\sqrt{\mathrm{3}}}{\mathrm{2}}={sin}\left(\frac{\pi}{\mathrm{6}}\right)\:\:\:\frac{\mathrm{1}}{\mathrm{2}}={cos}\left(\frac{\pi}{\mathrm{6}}\right) \\ $$$${e}^{{i}\theta} ={cos}\theta+{isin}\theta\:\leftarrow{demoivers}\:{theorem} \\ $$$${e}^{−{i}\theta} ={cos}\theta−{isin}\theta \\…
Question Number 48920 by peter frank last updated on 30/Nov/18 Answered by tanmay.chaudhury50@gmail.com last updated on 30/Nov/18 $${y}={e}^{−\mathrm{2}{mx}} {sin}\mathrm{4}{mx} \\ $$$$\frac{{dy}}{{dx}}={e}^{−\mathrm{2}{mx}} ×\mathrm{4}{mcos}\mathrm{4}{mx}−\mathrm{2}{me}^{−\mathrm{2}{mx}} {sin}\mathrm{4}{mx} \\ $$$$\frac{{dy}}{{dx}}=\mathrm{4}{me}^{−\mathrm{2}{mx}}…
Question Number 114447 by bemath last updated on 19/Sep/20 Commented by bemath last updated on 19/Sep/20 $${gave}\:{kudos}\:{all}\:{master}\: \\ $$ Answered by abdullahquwatan last updated on…
Question Number 114071 by bobhans last updated on 17/Sep/20 $${Find}\:{the}\:{solution}\:{set}\: \\ $$$$\sqrt{{x}^{\mathrm{2}} −\mathrm{4}{x}−\mathrm{5}}\:\geqslant\:{x} \\ $$ Commented by prakash jain last updated on 17/Sep/20 $$ \\…
Question Number 48517 by ajfour last updated on 24/Nov/18 Commented by ajfour last updated on 25/Nov/18 $${Find}\:{ratio}\:{of}\:{maximum}\:{triangle} \\ $$$${area}\:\left({with}\:{A}\:{and}\:{B}\:{fixed}\right)\:{to} \\ $$$${ellipse}\:{area}. \\ $$ Answered by…
Question Number 48501 by peter frank last updated on 24/Nov/18 Answered by Abdulhafeez Abu qatada last updated on 25/Nov/18 $$ \\ $$$$\left(\frac{{df}}{{dx}}\right)_{{y}} \:=\:\mathrm{sin}{x}\left(\mathrm{sin}\left({x}+{y}\right)\mathrm{cos}{y}\:+\:\mathrm{cos}\left({x}+{y}\right)\mathrm{sin}{y}\right) \\ $$$$\left(\frac{{df}}{{dx}}\right)_{{y}}…
Question Number 48338 by ajfour last updated on 22/Nov/18 Commented by mr W last updated on 23/Nov/18 $${nice}\:{working}! \\ $$ Commented by ajfour last updated…
Question Number 179088 by cortano1 last updated on 24/Oct/22 Answered by mr W last updated on 24/Oct/22 $$\boldsymbol{{Method}}\:\mathrm{1} \\ $$$$\mathrm{cos}\:\alpha=\frac{\mathrm{7}}{{R}} \\ $$$${R}^{\mathrm{2}} −\mathrm{7}^{\mathrm{2}} =\mathrm{58}^{\mathrm{2}} +\mathrm{92}^{\mathrm{2}}…
Question Number 178940 by ARUNG_Brandon_MBU last updated on 22/Oct/22 Answered by mr W last updated on 23/Oct/22 Commented by mr W last updated on 23/Oct/22…
Question Number 178941 by ARUNG_Brandon_MBU last updated on 23/Oct/22 Commented by HeferH last updated on 23/Oct/22 $${is}\:{AC}={DE}? \\ $$ Commented by Ar Brandon last updated…