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Category: Mensuration

A-rectangular-picture-6cm-by-8cm-is-enclosed-by-a-frame-1-2-wide-calculate-the-area-of-the-frame-

Question Number 172269 by Mikenice last updated on 25/Jun/22 $${A}\:{rectangular}\:{picture}\:\mathrm{6}{cm}\:{by}\:\mathrm{8}{cm}\:{is} \\ $$$${enclosed}\:{by}\:{a}\:{frame}\:\left(\frac{\mathrm{1}}{\mathrm{2}}\right)\:{wide}.\: \\ $$$${calculate}\:{the}\left[{area}\:{of}\:{the}\:{frame}.\right. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question-105883

Question Number 105883 by bemath last updated on 01/Aug/20 Answered by mr W last updated on 01/Aug/20 $${AG}=\sqrt{\mathrm{3}^{\mathrm{2}} +\mathrm{6}^{\mathrm{2}} −\mathrm{2}×\mathrm{3}×\mathrm{6}×\mathrm{cos}\:\mathrm{120}°}=\mathrm{3}\sqrt{\mathrm{7}} \\ $$$$\frac{\mathrm{sin}\:\angle{AGF}}{\mathrm{3}}=\frac{\mathrm{sin}\:\mathrm{120}°}{\mathrm{3}\sqrt{\mathrm{7}}} \\ $$$$\mathrm{sin}\:\angle{AGF}=\frac{\sqrt{\mathrm{21}}}{\mathrm{14}} \\…

Cube-ABCD-EFGH-with-length-side-2-cm-Point-P-is-the-center-of-ABFE-plane-The-distance-of-HP-line-and-the-BG-line-is-

Question Number 105404 by bemath last updated on 28/Jul/20 $${Cube}\:{ABCD}.{EFGH}\:{with} \\ $$$${length}\:{side}\:\mathrm{2}\:{cm}.\:{Point}\:{P}\:{is}\:{the} \\ $$$${center}\:{of}\:{ABFE}\:{plane}.\:{The} \\ $$$${distance}\:{of}\:{HP}\:{line}\:{and}\:{the}\:{BG} \\ $$$${line}\:{is}\:\_\_\: \\ $$ Answered by john santu last…