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Question Number 131465 by bramlexs22 last updated on 05/Feb/21 $${Let}\:{a},{b}\:{and}\:{c}\:{be}\:{three}\:{positive}\:{real}\:{numbers} \\ $$$$.\:{Prove}\:{that}\:{a}+{b}+{c}\:\leqslant\:\frac{{a}^{\mathrm{2}} +{bc}}{{b}+{c}}+\frac{{b}^{\mathrm{2}} +{ca}}{{c}+{a}}+\frac{{c}^{\mathrm{2}} +{ab}}{{a}+{b}} \\ $$ Answered by EDWIN88 last updated on 05/Feb/21 $${According}\:{to}\:{the}\:{identity}\:\frac{{a}^{\mathrm{2}}…
Question Number 99 by sagarwal last updated on 25/Jan/15 $$\mathrm{The}\:\mathrm{perimeter}\:\mathrm{of}\:\mathrm{an}\:\mathrm{isosceles}\:\mathrm{right}−\mathrm{angled} \\ $$$$\mathrm{triangle}\:\mathrm{is}\:\mathrm{2}{p}.\:\mathrm{Find}\:\mathrm{out}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{the}\:\mathrm{triangle}. \\ $$ Answered by 123456 last updated on 14/Dec/14 $$\mathrm{lets}\:\Delta\mathrm{A}{BC}\:\mathrm{be}\:\mathrm{a}\:\mathrm{triangle}\:\mathrm{with}\:\mathrm{lenght}\:{a},{b},{c} \\ $$$$\mathrm{by}\:\mathrm{it}\:\mathrm{isosceles}\:\mathrm{mean}\:\mathrm{that}\:\mathrm{two}\:\mathrm{or}\:\mathrm{more}\:\mathrm{angle}\:\mathrm{and}\:\mathrm{lenght}\:\mathrm{are}\:\mathrm{equal} \\…
Question Number 12933 by chux last updated on 07/May/17 Commented by ajfour last updated on 08/May/17 $${Touch}\:{and}\:{Draw} \\ $$ Commented by chux last updated on…
Question Number 12743 by tawa last updated on 30/Apr/17 $$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{eqilateral}\:\mathrm{triangle}\:\mathrm{whose}\:\mathrm{inscribed}\:\mathrm{circle}\:\mathrm{has}\:\mathrm{a}\:\mathrm{radius}\:\mathrm{2} \\ $$ Answered by mrW1 last updated on 30/Apr/17 $${OC}=\mathrm{2} \\ $$$${OB}=\mathrm{4}={DO} \\ $$$${CB}=\mathrm{2}\sqrt{\mathrm{3}} \\…
Question Number 12329 by tawa last updated on 19/Apr/17 Commented by mrW1 last updated on 19/Apr/17 $${if}\:{the}\:{rope}\:{is}\:{only}\:\mathrm{15}{m}\:{long},\:{the} \\ $$$${distance}\:{between}\:{the}\:{towers}\:{must} \\ $$$${be}\:{zero}! \\ $$ Commented by…
Question Number 143332 by bramlexs22 last updated on 13/Jun/21 Commented by soumyasaha last updated on 13/Jun/21 $$\:\mathrm{x}\:=\:\sqrt{\frac{\mathrm{3}+\sqrt{\mathrm{5}}}{\mathrm{2}}} \\ $$ Commented by mr W last updated…
Question Number 77272 by jagoll last updated on 05/Jan/20 $$\mathrm{given}\:\mathrm{T}.\mathrm{ABCD}\:\mathrm{is}\:\mathrm{pyramid}\: \\ $$$$\mathrm{with}\:\mathrm{AB}\:=\:\mathrm{BC}\:=\:\mathrm{8}\:\mathrm{and}\:\mathrm{AT}\:=\:\mathrm{6} \\ $$$$\:.\:\mathrm{P}\:\mathrm{is}\:\mathrm{midpoint}\:\mathrm{BC},\:\mathrm{Q}\:\mathrm{is}\:\mathrm{midpoint}\:\mathrm{AT}. \\ $$$$\mathrm{If}\:\alpha\:\mathrm{is}\:\mathrm{the}\:\mathrm{angle}\:\mathrm{between}\:\mathrm{TP}\:\mathrm{and} \\ $$$$\mathrm{PQ}\:\mathrm{then}\:\mathrm{cos}\:\alpha\:\mathrm{is}\:… \\ $$ Commented by john santu last…
Question Number 76964 by peter frank last updated on 01/Jan/20 $${solve}\:{Differential}\:\:{equation} \\ $$$${x}^{\mathrm{2}} \frac{{d}^{\mathrm{2}} {y}}{{dx}^{\mathrm{2}} }−\mathrm{4}{x}\frac{{dy}}{{dx}}+\mathrm{3}{y}={x}^{\mathrm{3}} +\mathrm{2}{x}+\mathrm{5} \\ $$ Answered by mind is power last…
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