Question Number 197834 by ajfour last updated on 30/Sep/23 Answered by mr W last updated on 01/Oct/23 Commented by mr W last updated on 03/Oct/23…
Question Number 197569 by Amidip last updated on 22/Sep/23 Commented by a.lgnaoui last updated on 23/Sep/23 $$\boldsymbol{\mathrm{I}}\:\:\mathrm{think}\:\mathrm{the}\:\mathrm{question}\:\mathrm{is}\:\mathrm{to}\:\mathrm{find}\:\boldsymbol{\mathrm{DG}}\:? \\ $$ Commented by mr W last updated…
Question Number 197128 by Mingma last updated on 08/Sep/23 Commented by Frix last updated on 09/Sep/23 $$\mathrm{I}\:\mathrm{get}\:\rho\approx.\mathrm{213841779235} \\ $$ Answered by sniper237 last updated on…
Question Number 196571 by cortano12 last updated on 27/Aug/23 Answered by som(math1967) last updated on 27/Aug/23 $$\:{x}=\sqrt{\mathrm{6}^{\mathrm{2}} +\mathrm{7}^{\mathrm{2}} +\mathrm{6}^{\mathrm{2}} }=\sqrt{\mathrm{121}}=\mathrm{11}{cm} \\ $$ Answered by hafeez…
Question Number 196320 by sniper237 last updated on 22/Aug/23 $$\:\:{If}\:\:{a}\:\:{regular}\:{n}−{polygon}\:{can} \\ $$$$\:{be}\:{divided}\:{into}\:\:{n}\:\:{identical}\:\: \\ $$$${equilateral}\:{triangles}\:{then}\:\:{n}=\mathrm{6} \\ $$ Answered by Rasheed.Sindhi last updated on 23/Aug/23 $${n}−{polygon}\:{consists}\:{n}\:\boldsymbol{{equilateral}}\:\boldsymbol{{triangles}} \\…
Question Number 196084 by Mingma last updated on 17/Aug/23 Answered by mr W last updated on 17/Aug/23 Commented by mr W last updated on 17/Aug/23…
Question Number 195790 by justenspi last updated on 10/Aug/23 $${a},{b},{c}\:{are}\:{positive}\:{real}\:{numbers}\:{and}\:{abc}\:=\mathrm{1} \\ $$$${prove}\:{that} \\ $$$$\left({a}−\mathrm{1}+\frac{\mathrm{1}}{{b}}\right)\left({b}−\mathrm{1}+\frac{\mathrm{1}}{{c}}\right)\left({c}−\mathrm{1}+\frac{\mathrm{1}}{{a}}\right)\leqslant\mathrm{1} \\ $$ Commented by justenspi last updated on 10/Aug/23 $${Case}\left({I}\right)\left({a}−\mathrm{1}+\frac{\mathrm{1}}{{b}}\right),\left({b}−\mathrm{1}+\frac{\mathrm{1}}{{c}}\right),\left({c}−\mathrm{1}+\frac{\mathrm{1}}{{a}}\right)>\mathrm{0} \\…
Question Number 195611 by Mingma last updated on 05/Aug/23 Answered by mr W last updated on 06/Aug/23 $${a}={side}\:{length}\:{of}\:{small}\:{pentagon} \\ $$$${b}={side}\:{length}\:{of}\:{big}\:{pentagon} \\ $$$${b}=\mathrm{2}{a}\:\mathrm{sin}\:\mathrm{54}° \\ $$$${a}=\mathrm{2}{r}\:\mathrm{sin}\:\mathrm{36}°\:\Rightarrow{r}=\frac{{a}}{\mathrm{2}\:\mathrm{sin}\:\mathrm{36}°} \\…
Question Number 195570 by York12 last updated on 05/Aug/23 $$\mathrm{Given}\:\mathrm{three}\:\mathrm{Real}\:\mathrm{numbers}\:\left({x},{y},{z}\right),{such}\:{that} \\ $$$${x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{z}^{\mathrm{2}} =\mathrm{1} \\ $$$${maximize} \\ $$$${x}^{\mathrm{4}} +{y}^{\mathrm{4}} −\mathrm{2}{z}^{\mathrm{4}} −\mathrm{3}\sqrt{\mathrm{2}}{xyz} \\ $$ Commented…
Question Number 195590 by Mingma last updated on 05/Aug/23 Answered by mr W last updated on 05/Aug/23 Commented by mr W last updated on 05/Aug/23…