Question Number 201519 by vahid last updated on 08/Dec/23 Answered by cortano12 last updated on 08/Dec/23 $$\left(\mathrm{1}\right)\:\int\:\frac{\mathrm{sin}\:^{\mathrm{3}} \mathrm{x}}{\mathrm{cos}\:^{\mathrm{6}} \mathrm{x}}\:\mathrm{dx}\:=\:−\int\:\frac{\mathrm{1}−\mathrm{cos}\:^{\mathrm{2}} \mathrm{x}}{\mathrm{cos}\:^{\mathrm{6}} \mathrm{x}}\:\mathrm{d}\left(\mathrm{cos}\:\mathrm{x}\right) \\ $$ Answered by…
Question Number 201544 by sonukgindia last updated on 08/Dec/23 Answered by aleks041103 last updated on 09/Dec/23 $${J}=\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{\mathrm{4}{sin}^{\mathrm{2}} \left({ln}\left({x}\right)\right)}{{ln}\left(\mathrm{1}/{x}\right)}{dx}=−\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{\mathrm{4}{sin}^{\mathrm{2}} \left(\mathrm{1}.{ln}\left({x}\right)\right)}{{ln}\left({x}\right)}{dx} \\ $$$${I}\left({s}\right)=−\int_{\mathrm{0}}…
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Question Number 201515 by sonukgindia last updated on 08/Dec/23 Answered by Calculusboy last updated on 08/Dec/23 $$\boldsymbol{{Solution}}:\:\boldsymbol{{I}}=\int_{\mathrm{0}} ^{\frac{\boldsymbol{\pi}}{\mathrm{2}}} \:\frac{\mathrm{1}}{\mathrm{1}+\left(\frac{\mathrm{1}}{\boldsymbol{{tanx}}}\right)^{\sqrt{\mathrm{2}}} }\boldsymbol{{dx}}\:\:\Leftrightarrow\:\:\boldsymbol{{I}}=\int_{\mathrm{0}} ^{\frac{\boldsymbol{\pi}}{\mathrm{2}}} \:\frac{\mathrm{1}}{\frac{\left(\boldsymbol{{tanx}}\right)^{\sqrt{\mathrm{2}}} +\mathrm{1}}{\left(\boldsymbol{{tanx}}\right)^{\sqrt{\mathrm{2}}} }}\boldsymbol{{dx}} \\…
Question Number 201495 by Rodier97 last updated on 07/Dec/23 $$ \\ $$$$ \\ $$$$ \\ $$$$ \\ $$$$\:\:\left({Un}\right)_{{n}\geqslant\mathrm{1}\:;} \:\:\:\:\frac{\mathrm{1}}{{nC}_{\mathrm{2}{n}} ^{{n}} \:} \\ $$$$ \\ $$$$\:\:\:\:{study}\:\:{convergence}…
Question Number 201473 by MrGHK last updated on 06/Dec/23 $$\int_{\mathrm{0}} ^{\mathrm{1}} \frac{\boldsymbol{\mathrm{Li}}_{\mathrm{3}} \left(−\boldsymbol{\mathrm{x}}^{\mathrm{2}} \right)}{\mathrm{1}+\boldsymbol{\mathrm{x}}}\boldsymbol{\mathrm{dx}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 201443 by sonukgindia last updated on 06/Dec/23 Commented by mr W last updated on 06/Dec/23 $${i}\:{and}\:{many}\:{others}\:{do}\:{our}\:{best}\:{to} \\ $$$${answer}\:{your}\:{questions}.\:{but}\:{why}\: \\ $$$${don}'{t}\:{you}\:{answer}\:{any}\:{question}\:{of}\: \\ $$$${mine}\:{and}\:{others}? \\…
Question Number 201401 by MrGHK last updated on 05/Dec/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 201393 by mokys last updated on 05/Dec/23 $${by}\:{diffention}\:{find}\:{f}\:'\left({z}\right)\:{of}\:{f}\left({z}\right)\:=\:\sqrt[{\mathrm{3}}]{{z}} \\ $$ Commented by mokys last updated on 05/Dec/23 $${how}\:{can}\:{solve}\:{this} \\ $$ Answered by aleks041103…
Question Number 201373 by sonukgindia last updated on 05/Dec/23 Answered by aleks041103 last updated on 05/Dec/23 Commented by aleks041103 last updated on 05/Dec/23 $${AQ}.{BQ}={DQ}.{FQ} \\…