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Question-199899

Question Number 199899 by sonukgindia last updated on 11/Nov/23 Answered by Rajpurohith last updated on 11/Nov/23 $${cos}\left({z}\right)+{sin}\left({z}\right)={k}\: \\ $$$$\Rightarrow\left(\frac{{e}^{{iz}} +{e}^{−{iz}} }{\mathrm{2}}\right)+\left(\frac{{e}^{{iz}} −{e}^{−{iz}} }{\mathrm{2}{i}}\right)={k} \\ $$$$\Rightarrow{e}^{{iz}}…

how-do-I-calculate-for-7-86-without-calculator-

Question Number 199959 by Yakubu last updated on 11/Nov/23 $$\:\boldsymbol{{how}}\:\boldsymbol{{do}}\:\boldsymbol{{I}}\:\boldsymbol{{calculate}}\:\boldsymbol{{for}} \\ $$$$\:\mathrm{7}.\mathrm{86}!\:\boldsymbol{{without}}\:\boldsymbol{{calculator}}? \\ $$ Commented by mr W last updated on 11/Nov/23 $$\mathrm{7}.\mathrm{86}!=\Gamma\left(\mathrm{8}.\mathrm{86}\right) \\ $$$${i}\:{think}\:{you}\:{can}'{t}\:{calculate}\:{it}\:{even}\:{with}…

Question-199854

Question Number 199854 by sonukgindia last updated on 10/Nov/23 Answered by aleks041103 last updated on 10/Nov/23 $${every}\:{fold}\:{is}\:{done}\:{at}\:{the}\:{angle}\:{bisector} \\ $$$$\Rightarrow{final}\:{accute}\:{angle}=\mathrm{90}°/\mathrm{4}=\mathrm{22}.\mathrm{5}° \\ $$$${S}=\mathrm{8}×\mathrm{6}−\mathrm{2}×\frac{\mathrm{3}×\left(\frac{\mathrm{3}}{{tan}\left(\mathrm{22}.\mathrm{5}°\right)}\right)}{\mathrm{2}}= \\ $$$$=\mathrm{48}−\mathrm{9}{cot}\left(\frac{\mathrm{45}°}{\mathrm{2}}\right)=\mathrm{48}−\mathrm{9}{cot}\left({x}\right)=\mathrm{48}−\mathrm{9}{z} \\ $$$$…

S-F-dS-F-yze-1-xze-2-xye-3-S-x-y-z-2-v-sin-u-sin-2piv-v-cos-u-2-v-sin-u-cos-2piv-2v-2-

Question Number 199736 by MathedUp last updated on 08/Nov/23 $$\int\int_{\:\boldsymbol{\mathcal{S}}} \:\hat {\boldsymbol{\mathrm{F}}}\centerdot\mathrm{d}\hat {\boldsymbol{\mathrm{S}}} \\ $$$$\hat {\boldsymbol{\mathrm{F}}}=−{yz}\hat {\boldsymbol{\mathrm{e}}}_{\mathrm{1}} −{xz}\hat {\boldsymbol{\mathrm{e}}}_{\mathrm{2}} −{xy}\boldsymbol{\mathrm{e}}_{\mathrm{3}} \: \\ $$$$\hat {\boldsymbol{\mathrm{S}}};\:\begin{pmatrix}{\hat {{x}}}\\{\hat…

Question-199738

Question Number 199738 by sonukgindia last updated on 08/Nov/23 Answered by AST last updated on 08/Nov/23 $$\frac{{sin}\left({x}\right)}{{DB}}=\frac{{sin}\left(\alpha\right)}{{BC}};\frac{{sin}\left(\mathrm{2}{x}\right)}{{BE}={DB}}=\frac{{sinCEB}={sin}\left(\mathrm{90}+{x}\right)}{{BC}} \\ $$$$\Rightarrow\frac{{DB}}{{BC}}=\frac{{sin}\left({x}\right)}{{sin}\left(\alpha\right)}=\frac{{sin}\left(\mathrm{2}{x}\right)}{{sin}\left(\mathrm{90}+{x}\right)} \\ $$$$\Rightarrow{sin}\left(\alpha\right)=\frac{{sin}\left({x}\right)\left[{sin}\mathrm{90}{cosx}\right]}{\mathrm{2}{sinxcosx}}=\frac{\mathrm{1}}{\mathrm{2}}\Rightarrow\alpha=\mathrm{30}° \\ $$ Commented by…

Question-199753

Question Number 199753 by sonukgindia last updated on 08/Nov/23 Answered by MM42 last updated on 09/Nov/23 $${let}\:\::\:\:{f}={xsinx}+{cosx}\:\:\&\:\:{g}={xcosx}+{sinx} \\ $$$${f}={g}\:\:\overset{\mathrm{0}\leqslant{x}\leqslant\mathrm{1}} {\Rightarrow}\:{x}=\mathrm{1}\:,\frac{\pi}{\mathrm{4}} \\ $$$$\Rightarrow{s}=\mid\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{4}}} \left({f}−{g}\right){dx}\mid+\mid\int_{\frac{\pi}{\mathrm{4}}} ^{\mathrm{1}}…