Question Number 197255 by sciencestudentW last updated on 11/Sep/23 $$\mathrm{log}\:\mathrm{2}={a} \\ $$$$\mathrm{log}\:\mathrm{3}={b} \\ $$$$\mathrm{log}\:\mathrm{72}=? \\ $$ Answered by AST last updated on 11/Sep/23 $${log}\left(\mathrm{9}×\mathrm{8}\right)=\mathrm{2}{log}\mathrm{3}+\mathrm{3}{log}\mathrm{2}=\mathrm{2}{b}+\mathrm{3}{a} \\…
Question Number 197250 by sciencestudentW last updated on 11/Sep/23 $$\mathrm{log}\:\mathrm{3}={a} \\ $$$$\mathrm{log}\:\mathrm{4}={b} \\ $$$$\mathrm{lo}\underset{\mathrm{5}} {\mathrm{g}36}=?\: \\ $$ Answered by AST last updated on 11/Sep/23 $$\frac{{log}\mathrm{3}}{{log}\mathrm{2}+{log}\mathrm{5}}={a}…
Question Number 197249 by sciencestudentW last updated on 11/Sep/23 $$\mathrm{lo}\underset{\mathrm{6}} {\mathrm{g}2}={a} \\ $$$$\mathrm{lo}\underset{\mathrm{6}} {\mathrm{g}9}=?\:\: \\ $$ Answered by AST last updated on 11/Sep/23 $$\frac{{log}\mathrm{2}}{{log}\mathrm{2}+{log}\mathrm{3}}={a}\Rightarrow{log}\mathrm{2}\left(\mathrm{1}−{a}\right)={alog}\mathrm{3} \\…
Question Number 197251 by sciencestudentW last updated on 11/Sep/23 $$\mathrm{log}\:\mathrm{2}=\mathrm{0}.\mathrm{30103} \\ $$$$\mathrm{log}\:\mathrm{125}=? \\ $$ Answered by mr W last updated on 26/Sep/23 $$\mathrm{log}\:\mathrm{2}={a} \\ $$$$\mathrm{log}\:\mathrm{125}=\mathrm{log}\:\mathrm{5}^{\mathrm{3}}…
Question Number 197242 by sonukgindia last updated on 10/Sep/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 197241 by sonukgindia last updated on 10/Sep/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 197238 by sonukgindia last updated on 10/Sep/23 Commented by Frix last updated on 12/Sep/23 $$\mathrm{No}\:\mathrm{useful}\:\mathrm{exact}\:\mathrm{solution}. \\ $$$$\mathrm{Set}\:\mathrm{the}\:\mathrm{radius}\:\mathrm{of}\:\mathrm{the}\:\mathrm{quarter}\:\mathrm{circle}\:=\mathrm{1} \\ $$$$\Rightarrow \\ $$$$\mathrm{Radius}\:\mathrm{of}\:\mathrm{the}\:\mathrm{semi}\:\mathrm{circle}\:\approx.\mathrm{717910784} \\ $$$${r}\approx.\mathrm{205269551}…
Question Number 197234 by sonukgindia last updated on 10/Sep/23 Answered by HeferH last updated on 10/Sep/23 Commented by HeferH last updated on 11/Sep/23 $$\:\left({m}+{n}\right)^{\mathrm{2}} +{n}^{\mathrm{2}}…
Question Number 197228 by sonukgindia last updated on 10/Sep/23 Answered by cherokeesay last updated on 10/Sep/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 197225 by sonukgindia last updated on 10/Sep/23 Answered by Frix last updated on 10/Sep/23 $${x}=\sqrt[{\mathrm{2}}]{\mathrm{1}+\frac{\mathrm{1}}{\mathrm{3}}\sqrt[{\mathrm{3}}]{\frac{\mathrm{1}}{\mathrm{3}}+\frac{\mathrm{10}}{\mathrm{9}}{x}}} \\ $$$${x}^{\mathrm{2}} =\mathrm{1}+\frac{\mathrm{1}}{\mathrm{3}}\sqrt[{\mathrm{3}}]{\frac{\mathrm{1}}{\mathrm{3}}+\frac{\mathrm{10}}{\mathrm{9}}{x}} \\ $$$$\mathrm{3}\left({x}^{\mathrm{2}} −\mathrm{1}\right)=\sqrt[{\mathrm{3}}]{\frac{\mathrm{1}}{\mathrm{3}}+\frac{\mathrm{10}}{\mathrm{9}}{x}} \\ $$$$\mathrm{27}\left({x}^{\mathrm{2}}…