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Question-194560

Question Number 194560 by Denis last updated on 09/Jul/23 Answered by MM42 last updated on 10/Jul/23 $$\Delta{XAB}\:\:{is}\:\:{equilatral}\:{triangle} \\ $$$$\angle\:{XAD}=\angle{XBC}=\mathrm{30}^{\mathrm{0}} \: \\ $$$${S}_{\mathrm{1}} ={S}_{\mathrm{2}} \Rightarrow{S}_{\mathrm{1}} +{S}_{\mathrm{2}}…

Gyanashram-classes-shivkund-Munger-by-Bittu-sir-12-th-physics-test-1-2-

Question Number 194506 by Biteshwar last updated on 08/Jul/23 $$\:\:\:\:\:\:\:\:\:\:\mathrm{Gyanashram}\:\mathrm{classes} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{shivkund}\left(\mathrm{Munger}\right)\:\:\:\:\mathrm{by}−\mathrm{Bittu}\:\mathrm{sir} \\ $$$$\:\:\:\mathrm{12}\:\:\mathrm{th}\:\mathrm{physics}\:\mathrm{test} \\ $$$$\:\:\:\:\:\:\:\:\mathrm{1}. \: \: \: \: \: \: \: \: \\…

Question-194436

Question Number 194436 by sonukgindia last updated on 06/Jul/23 Answered by Frix last updated on 06/Jul/23 $$\mathrm{3}\:?\:\sqrt{\mathrm{3}}+\sqrt[{\mathrm{3}}]{\mathrm{2}} \\ $$$$\mathrm{3}−\sqrt{\mathrm{3}}\:?\:\sqrt[{\mathrm{3}}]{\mathrm{2}} \\ $$$$\mathrm{54}−\mathrm{30}\sqrt{\mathrm{3}}\:?\:\mathrm{2} \\ $$$$\mathrm{52}\:?\:\mathrm{30}\sqrt{\mathrm{3}} \\ $$$$\frac{\mathrm{26}}{\mathrm{15}}\:?\:\sqrt{\mathrm{3}}…