Question Number 194434 by SANOGO last updated on 06/Jul/23 $${calcul} \\ $$$${e}^{\mathrm{2}{ln}\left(\mathrm{1}+{u}\right)\:} −{e}^{−\mathrm{2}{ln}\left(\mathrm{1}+{u}\right)} \:=? \\ $$ Answered by aba last updated on 06/Jul/23 $$\mathrm{e}^{\mathrm{2ln}\left(\mathrm{1}+\mathrm{u}\right)} −\mathrm{e}^{−\mathrm{2ln}\left(\mathrm{1}+\mathrm{u}\right)}…
Question Number 194363 by sonukgindia last updated on 05/Jul/23 Commented by Frix last updated on 05/Jul/23 $$\mathrm{There}'\mathrm{s}\:\mathrm{no}\:\mathrm{solution}. \\ $$$$\sqrt{{z}_{\mathrm{1}} +\sqrt{{z}_{\mathrm{2}} }}+\sqrt{{z}_{\mathrm{1}} −\sqrt{{z}_{\mathrm{2}} }}={r} \\ $$$$\mathrm{Solving}\:\mathrm{by}\:\mathrm{2}\:\mathrm{times}\:\left[\mathrm{squaring}\:\left(\mathrm{introduces}\right.\right.…
Question Number 194359 by Tinku Tara last updated on 05/Jul/23 $${v}\mathrm{2}.\mathrm{282}\:\mathrm{has}\:\mathrm{been}\:\mathrm{published}.\:\mathrm{This} \\ $$$$\mathrm{update}\:\mathrm{fixes}\:\mathrm{issues}\:\mathrm{with}\:\mathrm{missed} \\ $$$$\mathrm{notifications}\:\mathrm{and}\:\mathrm{adds}\:\mathrm{an} \\ $$$$\mathrm{arbitarary}\:\mathrm{precision}\: \\ $$$$\mathrm{scientific}\:\mathrm{calculator}. \\ $$ Commented by som(math1967) last…
Question Number 194386 by SANOGO last updated on 05/Jul/23 $${calcul}\:{the}\:{the}\:{derive}\:{of} \\ $$$${cos}^{\mathrm{3}} \left(\frac{\theta}{\mathrm{3}}\right)' \\ $$ Answered by Frix last updated on 05/Jul/23 $${f}\left({t}\right)={t}^{\mathrm{3}} \\ $$$${g}\left({t}\right)=\mathrm{cos}\:{t}…
Question Number 194401 by Tinku Tara last updated on 05/Jul/23 $$\mathrm{Hi} \\ $$$$\mathrm{Please}\:\mathrm{do}\:\mathrm{not}\:\mathrm{post}\:\mathrm{junk}\:\mathrm{content}\:\mathrm{in} \\ $$$$\mathrm{this}\:\mathrm{forum}.\:\mathrm{It}\:\mathrm{does}\:\mathrm{not}\:\mathrm{help}\:\mathrm{you}\:\mathrm{in} \\ $$$$\mathrm{anyway}\:\mathrm{and}\:\mathrm{it}\:\mathrm{increases}\:\mathrm{our}\:\mathrm{effort}\: \\ $$$$\mathrm{in}\:\mathrm{cleaning}\:\mathrm{up}. \\ $$ Terms of Service Privacy…
Question Number 194350 by SaRahAli last updated on 04/Jul/23 Answered by MM42 last updated on 04/Jul/23 $$\mathrm{1}+\sqrt{−\mathrm{1}}=\mathrm{1}+{i}=\sqrt{\mathrm{2}}×{e}^{\frac{\pi}{\mathrm{4}}{i}} \\ $$$$\Rightarrow\left(\mathrm{1}+{t}\right)^{\mathrm{20}} =\mathrm{2}^{\mathrm{10}} ×{e}^{\mathrm{5}\pi{i}} =−\mathrm{1024}\:\checkmark \\ $$$$ \\…
Question Number 194331 by 073 last updated on 03/Jul/23 Answered by Frix last updated on 03/Jul/23 $$\mathrm{cos}\:{x}\:={C} \\ $$$${A}+{B}=\mathrm{1}\:\Leftrightarrow\:{B}=\mathrm{1}−{A} \\ $$$${S}_{{n}} ={C}^{\mathrm{4}} {A}^{{n}} +\left({C}^{\mathrm{2}} −\mathrm{1}\right)^{\mathrm{2}}…
Question Number 194286 by mokys last updated on 02/Jul/23 $$ \\ $$$$\:\:\boldsymbol{{find}}\:\underset{\boldsymbol{{x}}\rightarrow\mathrm{0}} {\boldsymbol{{lim}}}\:\lfloor\:\frac{\boldsymbol{{tan}}\left(\boldsymbol{{x}}\right)}{\boldsymbol{{x}}}\rfloor \\ $$ Answered by tri26112004 last updated on 02/Jul/23 $$=\:\mathrm{1} \\ $$…
Question Number 194172 by sonukgindia last updated on 29/Jun/23 Commented by Frix last updated on 29/Jun/23 $$\begin{cases}{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} =\mathrm{5}}\\{{x}^{\mathrm{4}} +{y}^{\mathrm{4}} =\mathrm{55}}\end{cases} \\ $$$${x}=\pm\sqrt{{a}−\sqrt{{b}}}\wedge{y}=\pm\sqrt{{a}+\sqrt{{b}}} \\ $$$$\begin{cases}{\mathrm{2}{a}=\mathrm{5}}\\{\mathrm{2}{a}^{\mathrm{2}}…
Question Number 194174 by tri26112004 last updated on 29/Jun/23 $${Know}\:{f}\left({x}^{−\mathrm{1}} \right)={f}^{−\mathrm{1}} \left({x}\right)\:\left({f}^{−\mathrm{1}} \left({x}\right)=\frac{\mathrm{1}}{{f}\left({x}\right)}\right) \\ $$$${Find}\:{f}\left({x}\right)¿ \\ $$ Answered by mr W last updated on 29/Jun/23…