Question Number 61069 by aanur last updated on 28/May/19 Commented by aanur last updated on 28/May/19 $${Find}\:{S}\mathrm{20}^{} \\ $$$${Could}\:{you}\:{help}\:{me}\:{sir} \\ $$ Commented by kaivan.ahmadi last…
Question Number 61061 by Gulay last updated on 28/May/19 Commented by Gulay last updated on 28/May/19 $$\mathrm{AB}=\mathrm{6}\:\:\mathrm{AC}=\mathrm{12}\:\mathrm{and}\:\mathrm{BC}=\mathrm{15}\:\:\mathrm{Find} \\ $$$$\frac{\mathrm{Saec}}{\mathrm{Sedc}} \\ $$ Answered by ajfour last…
Question Number 126588 by MathSh last updated on 22/Dec/20 $$\Sigma\:\frac{\mathrm{1}}{\:\sqrt{{n}}}\:{ln}\:\frac{\mathrm{2}{n}+\mathrm{1}}{{n}}\:{x}^{{n}} \:=\:? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 61048 by Gulay last updated on 28/May/19 Commented by Gulay last updated on 28/May/19 $$\mathrm{AB}=\mathrm{30}\:\:\:\:\mathrm{BD}=\mathrm{24}\:\:\:\mathrm{Find}\:\mathrm{DC}\:\:\:<\mathrm{B}=\mathrm{90} \\ $$$$\mathrm{sir}\:\mathrm{plz}\:\mathrm{help}\:\mathrm{me} \\ $$ Answered by mr W…
Question Number 61042 by aliesam last updated on 28/May/19 Answered by ajfour last updated on 28/May/19 $${let}\:\:{N}\bigtriangleup{x}=\mathrm{5}−\mathrm{2}=\mathrm{3} \\ $$$$\:\:\:\:\:\:\:\:{x}=\mathrm{2}+{n}\bigtriangleup{x}\:=\:\mathrm{2}+\frac{\mathrm{3}{n}}{{N}} \\ $$$$\int_{\mathrm{2}} ^{\:\mathrm{5}} \left({x}^{\mathrm{3}} −\mathrm{1}\right){dx}=\underset{{N}\rightarrow\infty} {\mathrm{lim}}\:\frac{\mathrm{3}}{{N}}\underset{{n}=\mathrm{1}}…
Question Number 126575 by amns last updated on 22/Dec/20 $$\boldsymbol{{Solve}}:\:{sin}\theta\:+\:{cos}\theta\:=\:\mathrm{1},\:\boldsymbol{{when}}\:\mathrm{0}°\:\leqslant\:\theta\:\leqslant\:\mathrm{90}° \\ $$ Commented by amns last updated on 22/Dec/20 $${I}\:{need}\:{a}\:{help}\:{to}\:{solve}\:{it},\:\boldsymbol{{Help}}\:\boldsymbol{{me}}. \\ $$ Commented by benjo_mathlover…
Question Number 61030 by aanur last updated on 28/May/19 Commented by prakash jain last updated on 28/May/19 $${x}^{\mathrm{2}} =\mathrm{3}\sqrt{\mathrm{3}} \\ $$$${x}^{\mathrm{4}} =\mathrm{9}×\mathrm{3}=\mathrm{27}=\mathrm{3}^{\mathrm{3}} \Rightarrow{x}=\mathrm{3}^{\mathrm{3}/\mathrm{4}} \\ $$$${y}^{\mathrm{2}}…
Question Number 61027 by Gulay last updated on 28/May/19 Commented by Gulay last updated on 28/May/19 $$\mathrm{sir}\:\mathrm{could}\:\mathrm{you}\:\mathrm{help}\:\mathrm{me} \\ $$ Commented by mathsolverby Abdo last updated…
Question Number 126552 by mathocean1 last updated on 21/Dec/20 $${u}\:;\:{v}\in\:\mathbb{C}\:{such}\:{that}\:\mid{u}\mid=\mid{v}\mid=\mathrm{1} \\ $$$${and}\:{uv}\neq−\mathrm{1}. \\ $$$${show}\:{that}\:\frac{{u}+{v}}{\mathrm{1}+{uv}}\:\in\:\mathbb{R}. \\ $$ Answered by Olaf last updated on 21/Dec/20 $${u}\:=\:{e}^{{i}\alpha} ,\:{v}\:=\:{e}^{{i}\beta}…
Question Number 126553 by mathocean1 last updated on 21/Dec/20 $${show}\:{thatfor}\:{z}\in\mathbb{C}\: \\ $$$$\mid{z}+\mathrm{1}\mid^{\mathrm{2}} =\mathrm{2}\mid{z}\mid^{\mathrm{2}\:} \Leftrightarrow\mid{z}−\mathrm{1}\mid^{\mathrm{2}} =\mathrm{2}. \\ $$$${This}\:{formula}\:{can}\:{be}\:{used}: \\ $$$$\mid{z}\mid^{\mathrm{2}} ={z}×\overset{−} {{z}} \\ $$ Answered by…