Question Number 117299 by A8;15: last updated on 10/Oct/20 Commented by TANMAY PANACEA last updated on 10/Oct/20 $${question}\:{not}\:{clearly}\:{visible} \\ $$ Commented by mathmax by abdo…
Question Number 182829 by yaslm last updated on 14/Dec/22 Answered by cortano1 last updated on 15/Dec/22 $$\:{L}=\:\underset{{x}\rightarrow\frac{\pi}{\mathrm{6}}} {\mathrm{lim}}\:\frac{\mathrm{2sin}\:{x}−\mathrm{1}}{\:\sqrt{\mathrm{3}}\:\mathrm{sec}\:{x}−\mathrm{2}} \\ $$$$\:=\:\underset{{x}\rightarrow\frac{\pi}{\mathrm{6}}} {\mathrm{lim}}\:\frac{\mathrm{cos}\:{x}\left(\mathrm{2sin}\:{x}−\mathrm{1}\right)}{\:\sqrt{\mathrm{3}}−\mathrm{2cos}\:{x}} \\ $$$$\:=\:\frac{\mathrm{1}}{\mathrm{2}}\sqrt{\mathrm{3}}\:×\underset{{x}\rightarrow\frac{\pi}{\mathrm{6}}} {\mathrm{lim}}\:\frac{\mathrm{2sin}\:{x}−\mathrm{1}}{\:\sqrt{\mathrm{3}}−\mathrm{2cos}\:{x}} \\…
Question Number 182835 by SANOGO last updated on 15/Dec/22 $${s}\left({n}\right)=\underset{{n}=\mathrm{1}} {\overset{+{oo}} {\sum}}\:\frac{\left(−\mathrm{1}\right)^{{n}} \:+{n}^{\mathrm{2}} }{{n}!}{x}^{{n}} \:=? \\ $$ Answered by mr W last updated on 15/Dec/22…
Question Number 117295 by mohammad17 last updated on 10/Oct/20 Answered by mr W last updated on 10/Oct/20 $${y}={r}\:\mathrm{sin}\:\theta \\ $$$${x}={r}\:\mathrm{cos}\:\theta \\ $$$${r}=\mathrm{1}+\mathrm{cos}\:\theta \\ $$$$\frac{{dy}}{{d}\theta}=\frac{{dr}}{{d}\theta}\:\mathrm{sin}\:\theta+{r}\:\mathrm{cos}\:\theta=−\mathrm{sin}^{\mathrm{2}} \:\theta+\left(\mathrm{1}+\mathrm{cos}\:\theta\right)\mathrm{cos}\:\theta…
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Question Number 117263 by bemath last updated on 10/Oct/20 $$\mathrm{dear}\:\mathrm{admint}\:\mathrm{tinkutara} \\ $$ Commented by Tinku Tara last updated on 10/Oct/20 $$\mathrm{Yes}? \\ $$ Commented by…
Question Number 182791 by Matica last updated on 14/Dec/22 $$\:{We}\:{have}\:\mathrm{0}<{x}<{a}\:{and}\:{m},{n}\:\in\mathbb{N}. \\ $$$$\:{Prove}\:{x}^{{m}} \left({a}−{x}\right)^{{n}} \leqslant\:\frac{{m}^{{m}} {n}^{{n}} }{\left({m}+{n}\right)^{{m}+{n}} }\centerdot{a}^{{m}+{n}} \\ $$ Answered by mahdipoor last updated on…
Question Number 182786 by SANOGO last updated on 14/Dec/22 $${existant}\:{and}\:{value}\:{m}\geqslant\mathrm{1}\:{of} \\ $$$${S}_{{m}} =\underset{{n}=\mathrm{1}\:\overset{} {\:}} {\overset{+{oo}} {\sum}}\frac{\mathrm{1}}{{n}\left({n}+\mathrm{1}\right)…\left({n}+{m}\right)}\: \\ $$ Answered by dre23 last updated on 15/Dec/22…
Question Number 117243 by A8;15: last updated on 10/Oct/20 Commented by A8;15: last updated on 10/Oct/20 please help sir Answered by Olaf last updated on 10/Oct/20 $$…