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Question-112050

Question Number 112050 by naka3546 last updated on 05/Sep/20 Answered by ajfour last updated on 05/Sep/20 $$\frac{{x}}{{y}}={t} \\ $$$$\frac{{t}^{\mathrm{2}} −\mathrm{7}{t}−\mathrm{9}}{{t}^{\mathrm{2}} +\mathrm{5}{t}+\mathrm{11}}=\frac{\mathrm{9}}{\mathrm{5}} \\ $$$${t}^{\mathrm{2}} +\mathrm{20}{t}+\mathrm{36}=\mathrm{0} \\…

Question-177540

Question Number 177540 by yaslm last updated on 06/Oct/22 Answered by aleks041103 last updated on 07/Oct/22 $${its}\:{either}\:{circle}\:{inscribed}\:{in}\:{an}\:{ellipse}\:{or} \\ $$$${the}\:{other}\:{way}\:{around}. \\ $$$$\Rightarrow{Ans}.\:=\:\mid\pi{ab}−\pi{a}^{\mathrm{2}} \mid \\ $$$$\Rightarrow{Ans}.\:=\:\pi{a}\mid{b}−{a}\mid \\…

To-this-formula-find-the-value-of-S-when-t-1-u-2-a-3-b-4-c-5-S-tu-a-b-c-Answer-S-0-1666666666666-0-17-Solution-S-tu-

Question Number 46464 by Zahir Ussene Mamede last updated on 26/Oct/18 $${To}\:{this}\:{formula}\:{find}\:{the}\:{value}\:{of}\:{S}\:{when}\:{t}=\mathrm{1}\:{u}=\mathrm{2}\:{a}=\mathrm{3}\:{b}=\mathrm{4}\:{c}=\mathrm{5} \\ $$$${S}=\frac{{tu}}{\left({a}+{b}+{c}\right)} \\ $$$$\left[{Answer}\right]========================= \\ $$$$ \\ $$$$\:\:\:\:{S}=\mathrm{0}.\mathrm{1666666666666}… \\ $$$$\:\:\:\:\:\:\:\approx\mathrm{0}.\mathrm{17} \\ $$$$ \\…

Question-111974

Question Number 111974 by mohammad17 last updated on 05/Sep/20 Answered by mathmax by abdo last updated on 05/Sep/20 $$\left.\mathrm{1}\right)\mathrm{f}\left(\mathrm{x},\mathrm{y}\right)=\mathrm{x}^{\mathrm{2}} \:\mathrm{arctan}\left(\frac{\mathrm{y}}{\mathrm{x}}\right)\:\Rightarrow\frac{\partial\mathrm{f}}{\partial\mathrm{x}}\left(\mathrm{x},\mathrm{y}\right)=\mathrm{2x}\:\mathrm{arctan}\left(\frac{\mathrm{y}}{\mathrm{x}}\right)+\mathrm{x}^{\mathrm{2}} ×\left(\frac{−\mathrm{y}}{\mathrm{x}^{\mathrm{2}} \left(\mathrm{1}+\frac{\mathrm{y}^{\mathrm{2}} }{\mathrm{x}^{\mathrm{2}} }\right)}\right) \\…