Question Number 177132 by mokys last updated on 01/Oct/22 Commented by mr W last updated on 01/Oct/22 $${instead}\:{of}\:{posting}\:{these}\:?????,\:{you} \\ $$$${can}\:{easily}\:{try}\:{by}\:{yourself}: \\ $$$${A}=\left(−\frac{\mathrm{1}}{\cancel{\mathrm{3}}}\right)\left(−\frac{\cancel{\mathrm{3}}}{\cancel{\mathrm{5}}}\right)\left(−\frac{\cancel{\mathrm{5}}}{\cancel{\mathrm{7}}}\right)…\left(−\frac{\cancel{\mathrm{4}{k}−\mathrm{1}}}{\mathrm{4}{k}+\mathrm{1}}\right) \\ $$$$=\left(−\mathrm{1}\right)^{\mathrm{2}{k}} \frac{\mathrm{1}}{\mathrm{4}{k}+\mathrm{1}}…
Question Number 177131 by mokys last updated on 01/Oct/22 Commented by Frix last updated on 02/Oct/22 $$\frac{\frac{\mathrm{1}}{\mathrm{1}×\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{3}×\mathrm{4}}+…+\frac{\mathrm{1}}{\left(\mathrm{2}{n}−\mathrm{1}\right)×\mathrm{2}{n}}}{\frac{\mathrm{1}}{\left({n}+\mathrm{1}\right)×\mathrm{2}{n}}+\frac{\mathrm{1}}{\left({n}+\mathrm{2}\right)×\left(\mathrm{2}{n}−\mathrm{1}\right)}+…+\frac{\mathrm{1}}{\left({n}+{n}\right)×\left(\mathrm{2}{n}−\left({n}−\mathrm{1}\right)\right)}}=\frac{\mathrm{3}{n}+\mathrm{1}}{\mathrm{2}} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 111581 by mathdave last updated on 04/Sep/20 $${the}\:{age}\:{of}\:{a}\:{mother}\:{and}\:{daughter}\:{arein} \\ $$$${the}\:{ratio}\:{of}\:\mathrm{8}:\mathrm{5}.{if}\:{the}\:{age}\:{now}\:{is} \\ $$$$\mathrm{15},{what}\:{was}\:{the}\:{age}\:{of}\:{the}\:{mother} \\ $$$${six}\:{years}\:{ago}. \\ $$ Commented by Her_Majesty last updated on 04/Sep/20…
Question Number 46042 by naka3546 last updated on 20/Oct/18 Commented by Tawa1 last updated on 20/Oct/18 $$\mathrm{Sir},\:\mathrm{can}\:\mathrm{you}\:\mathrm{share}\:\mathrm{me}\:\mathrm{the}\:\mathrm{link}\:\mathrm{to}\:\mathrm{download}\:\mathrm{this}\:\mathrm{pdf}\:\mathrm{or}\:\mathrm{how}\:\mathrm{can}\:\mathrm{i}\:\mathrm{get}\:\mathrm{it}\:\mathrm{sir} \\ $$ Commented by Kunal12588 last updated on…
Question Number 177099 by mokys last updated on 30/Sep/22 Answered by TheHoneyCat last updated on 04/Oct/22 $$\mathrm{taking}\:\mathrm{the}\:\mathrm{log}\:\mathrm{of}\:\mathrm{your}\:\mathrm{product} \\ $$$$ \\ $$$$\mathrm{L}=\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}{x}^{{n}} \left(\mathrm{ln}\left(\mathrm{1}+{x}^{{n}+\mathrm{1}} \right)−\mathrm{ln}\left(\mathrm{1}+{x}^{{n}}…
Question Number 46025 by Sanjarbek last updated on 20/Oct/18 Answered by tanmay.chaudhury50@gmail.com last updated on 20/Oct/18 $${ln}_{{sinx}} {cosx}=\mathrm{4}−{x} \\ $$$$\left({sinx}\right)^{\mathrm{4}−{x}} ={cosx} \\ $$ Terms of…
Question Number 46020 by mondodotto@gmail.com last updated on 20/Oct/18 Answered by tanmay.chaudhury50@gmail.com last updated on 20/Oct/18 $$=\frac{\mathrm{1}}{\mathrm{2}}\int\frac{{x}^{\mathrm{2}} +{x}+\mathrm{1}}{{x}\sqrt{{x}^{\mathrm{2}} +{x}+\mathrm{1}}}{dx} \\ $$$$=\frac{\mathrm{1}}{\mathrm{2}}\int\frac{{x}}{\:\sqrt{{x}^{\mathrm{2}} +{x}+\mathrm{1}}}+\frac{\mathrm{1}}{\mathrm{2}}\int\frac{{dx}}{\:\sqrt{{x}^{\mathrm{2}} +{x}+\mathrm{1}}}+\frac{\mathrm{1}}{\mathrm{2}}\int\frac{{dx}}{{x}\sqrt{{x}^{\mathrm{2}} +{x}+\mathrm{1}}} \\…
Question Number 111548 by tkb last updated on 04/Sep/20 $$ \\ $$$$ \\ $$$$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{RESULT}\left(\mathrm{I}\boldsymbol{\mathrm{ntegration}}\right)\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{D}\boldsymbol{\mathrm{ate}}:\mathrm{04}.\mathrm{09}.\mathrm{2020} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{FULL}\:\mathrm{MARKS}\::\:\mathrm{40} \\ $$$$\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\mathrm{1}\:\:.\:\:\:\:.\boldsymbol{\mathrm{SR}}\mathrm{EET}\boldsymbol{\mathrm{OMA}}\::\mathrm{40} \\…
Question Number 111544 by tkb last updated on 04/Sep/20 $$ \\ $$$$ \\ $$$$ \\ $$$$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{RESULT}\left(\mathrm{INTEGRATION}\right) \\ $$$$ \\ $$ Terms…
Question Number 111458 by mohammad17 last updated on 03/Sep/20 Commented by kaivan.ahmadi last updated on 03/Sep/20 $${Q}_{\mathrm{1}} \\ $$$$\left({ab}\right)^{{n}} =\left({ab}\right)\left({ab}\right)…\left({ab}\right)\:;\:{n}\:{times} \\ $$$${a}\left({ba}\right)\left({ba}\right)….\left({ba}\right){b}={a}\left({ab}\right)\left({ab}\right)…\left({ab}\right){b}= \\ $$$${a}^{\mathrm{2}} \left({ba}\right)….\left({ba}\right){b}^{\mathrm{2}}…