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Question-110722

Question Number 110722 by ZiYangLee last updated on 30/Aug/20 Answered by ajfour last updated on 30/Aug/20 $$\left({a}−{b}\right){x}+\left({b}−{a}\right)=\mathrm{0} \\ $$$$\Rightarrow\:\:{x}=\mathrm{1} \\ $$$$\Rightarrow\:\:{a}+{b}=−\mathrm{1}\:. \\ $$ Answered by…

Question-45173

Question Number 45173 by Cheyboy last updated on 10/Oct/18 Commented by Cheyboy last updated on 10/Oct/18 $$\mathrm{Plzz}\:\mathrm{help}\:\mathrm{me}\:\mathrm{with}\:\mathrm{the}\:\mathrm{pattern} \\ $$$$\mathrm{It}\:\mathrm{was}\:\mathrm{giving}\:\mathrm{to}\:\mathrm{me}\:\mathrm{by}\:\mathrm{my}\:\mathrm{little} \\ $$$$\mathrm{bro}\:\mathrm{but}\:\mathrm{i}\:\mathrm{cant}\:\mathrm{figure}\:\mathrm{out}\:\mathrm{d}\:\mathrm{pattern} \\ $$ Commented by…

A-solid-rigth-triangular-prism-of-length-12cm-and-a-cross-section-which-is-an-equilateral-triangle-of-6cm-Find-the-total-surface-area-

Question Number 176212 by otchereabdullai@gmail.com last updated on 15/Sep/22 $$\:\:\mathrm{A}\:\mathrm{solid}\:\mathrm{rigth}\:\mathrm{triangular}\:\mathrm{prism}\:\mathrm{of}\: \\ $$$$\:\:\mathrm{length}\:\mathrm{12cm}\:\mathrm{and}\:\mathrm{a}\:\mathrm{cross}\:\mathrm{section}\: \\ $$$$\:\:\mathrm{which}\:\mathrm{is}\:\mathrm{an}\:\mathrm{equilateral}\:\mathrm{triangle}\:\mathrm{of} \\ $$$$\:\:\mathrm{6cm}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{total}\:\mathrm{surface}\:\mathrm{area}. \\ $$ Commented by adhigenz last updated on 15/Sep/22…

In-a-school-election-for-the-positon-of-SRC-president-one-candidate-obtained-87-5-of-the-vote-cast-others-obtained-275-votes-a-How-many-votes-did-the-winner-obtain-b-If-

Question Number 176205 by otchereabdullai@gmail.com last updated on 15/Sep/22 $$\:\mathrm{In}\:\mathrm{a}\:\mathrm{school}\:\mathrm{election}\:\mathrm{for}\:\mathrm{the}\:\mathrm{positon}\: \\ $$$$\:\:\mathrm{of}\:\mathrm{SRC}\:\mathrm{president},\:\mathrm{one}\:\mathrm{candidate} \\ $$$$\:\:\mathrm{obtained}\:\mathrm{87}.\mathrm{5\%}\:\mathrm{of}\:\mathrm{the}\:\mathrm{vote}\:\mathrm{cast}\: \\ $$$$\:\:\mathrm{others}\:\mathrm{obtained}\:\mathrm{275}\:\mathrm{votes} \\ $$$$\:\:\left(\mathrm{a}\right)\:\mathrm{How}\:\mathrm{many}\:\mathrm{votes}\:\mathrm{did}\:\mathrm{the}\:\mathrm{winner} \\ $$$$\:\:\:\:\:\:\:\:\:\mathrm{obtain}. \\ $$$$\:\:\:\:\left(\mathrm{b}\right)\:\mathrm{If}\:\mathrm{the}\:\mathrm{voter}\:\mathrm{turnout}\:\mathrm{was}\:\mathrm{55\%}\: \\ $$$$\:\:\:\:\:\:\:\:\mathrm{find}\:\mathrm{the}\:\mathrm{total}\:\mathrm{number}\:\mathrm{of}\:\:\mathrm{eligible} \\…

1-lim-x-0-sin-1-x-2-lim-x-0-cos-1-x-

Question Number 110647 by Khalmohmmad last updated on 29/Aug/20 $$\left.\:\mathrm{1}\right)\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}sin}\left(\frac{\mathrm{1}}{\mathrm{x}}\right)=? \\ $$$$\left.\mathrm{2}\right)\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}cos}\:\left(\frac{\mathrm{1}}{\mathrm{x}}\right)=? \\ $$$$ \\ $$ Answered by mathmax by abdo last updated…

a-b-c-R-and-abc-1-Prove-c-a-3-b-3-a-2-b-2-b-a-3-c-3-a-2-c-2-a-b-3-c-3-b-2-c-2-3-2-

Question Number 176174 by Matica last updated on 14/Sep/22 $$ \\ $$$$\:\mathrm{a},{b},{c}\:\in\mathbb{R}_{+\:} ^{\ast} \:\:\mathrm{and}\:{abc}=\mathrm{1}.\:\mathrm{Prove} \\ $$$$\:\:\:\frac{{c}\:\sqrt{{a}^{\mathrm{3}} +{b}^{\mathrm{3}} }}{{a}^{\mathrm{2}} +{b}^{\mathrm{2}} }\:+\:\frac{{b}\:\sqrt{{a}^{\mathrm{3}} +{c}^{\mathrm{3}} }}{{a}^{\mathrm{2}} +{c}^{\mathrm{2}} }\:+\:\frac{{a}\sqrt{{b}^{\mathrm{3}} +{c}^{\mathrm{3}}…

someone-posted-this-problem-and-my-solution-followed-solve-0-1-ln-x-1-x-2-1-x-2-dx-solution-y-ln-x-1-x-2-and-dy-1-1-x-2-dx-at-x-0-y-0-and-at-x-1-y-ln-1-2-hen

Question Number 110619 by mathdave last updated on 29/Aug/20 $${someone}\:{posted}\:{this}\:{problem}\:{and}\:{my} \\ $$$${solution}\:{followed} \\ $$$${solve} \\ $$$$\int_{\mathrm{0}} ^{\mathrm{1}} \frac{\mathrm{ln}\left({x}+\sqrt{\mathrm{1}+{x}^{\mathrm{2}} }\right)}{\:\sqrt{\mathrm{1}+{x}^{\mathrm{2}} }}{dx} \\ $$$${solution} \\ $$$${y}=\mathrm{ln}\left({x}+\sqrt{\mathrm{1}+{x}^{\mathrm{2}} }\right)\:\:\:{and}\:\:{dy}=\frac{\mathrm{1}}{\:\sqrt{\mathrm{1}+{x}^{\mathrm{2}}…