Question Number 109863 by mathdave last updated on 26/Aug/20 Answered by mathdave last updated on 26/Aug/20 $${solution} \\ $$$${recall}\:{that}\:\: \\ $$$$\:_{{a}} {D}_{{x}} ^{−\alpha} {f}\left({t}\right)=_{{a}} {I}_{{x}}…
Question Number 109858 by aurpeyz last updated on 26/Aug/20 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{nth}\:\mathrm{term}\:\mathrm{for}\:\mathrm{the}\:\mathrm{sequence}\:\mathrm{3}.\:\mathrm{12}.\:\mathrm{27}.\:\mathrm{48}.\:\mathrm{75}… \\ $$ Answered by Her_Majesty last updated on 26/Aug/20 $$\mathrm{3}{n}^{\mathrm{2}} \\ $$ Answered by 1549442205PVT…
Question Number 109854 by bemath last updated on 26/Aug/20 $$\:\frac{\bigstar{be}\bigstar}{{math}} \\ $$$$\left(\mathrm{1}\right)\int\:\frac{\mathrm{3}+\mathrm{2cos}\:{x}}{\left(\mathrm{2}+\mathrm{3cos}\:{x}\right)^{\mathrm{3}} }\:{dx}\: \\ $$$$\left(\mathrm{2}\right)\left(\sqrt{\mathrm{2}+\sqrt{\mathrm{3}}}\:\right)^{{y}} −\left(\sqrt{\mathrm{2}−\sqrt{\mathrm{3}}}\:\right)^{{y}} \:=\:\mathrm{14} \\ $$$$\:\:\:\:\:{y}=? \\ $$ Commented by bemath last…
Question Number 109855 by aurpeyz last updated on 26/Aug/20 Answered by aurpeyz last updated on 26/Aug/20 $${Can}\:{anyone}\:{pls}\:{explain}\:{this}?\:{it}\:{is}\:{pertaining} \\ $$$${binomial}\:{expansion}\:{for}\:{negative}\:{powers} \\ $$ Commented by mathdave last…
Question Number 109852 by aurpeyz last updated on 26/Aug/20 $${pls}\:{is}\:{there}\:{anyone}\:{with}\:{any}\:{material}\:{that} \\ $$$${can}\:{help}\:{me}\:{for}\:{binomial}\:{expansion}\:{for} \\ $$$${negative}\:{powers} \\ $$ Commented by mathdave last updated on 26/Aug/20 $${drop}\:{the}\:{question}\:{nah}\:{from}\:{there}\:{when}\:{it}\:{solvr}\:{u} \\…
Question Number 109853 by aurpeyz last updated on 26/Aug/20 $${is}\:{there}\:{any}\:{diffrence}\:{between}\:{greatest} \\ $$$${coefficient}\:{and}\:{largest}\:{coefficient}? \\ $$ Commented by Her_Majesty last updated on 26/Aug/20 $${no} \\ $$ Commented…
Question Number 44301 by naka3546 last updated on 26/Sep/18 $${Prove}\:\:{that} \\ $$$$\mathrm{1}\:+\:\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{2}} }\:+\:\frac{\mathrm{1}}{\mathrm{3}^{\mathrm{2}} }\:+\:\frac{\mathrm{1}}{\mathrm{4}^{\mathrm{2}} }\:+\:…\:\:=\:\:\frac{\pi^{\mathrm{2}} }{\mathrm{6}} \\ $$ Commented by abdo.msup.com last updated on 26/Sep/18…
Question Number 109823 by mathdave last updated on 25/Aug/20 Commented by mathdave last updated on 25/Aug/20 $${pls}\:{solution}\:{wit}\:{enough}\:{explanation} \\ $$ Answered by 1549442205PVT last updated on…
Question Number 109817 by Algoritm last updated on 25/Aug/20 Commented by 1549442205PVT last updated on 26/Aug/20 $$\mathrm{This}\:\mathrm{question}\:\mathrm{is}\:\mathrm{repeated}\:\mathrm{question} \\ $$$$\mathrm{Q109721}.\mathrm{Here},\mathrm{you}\:\mathrm{wrote}\:\:\mathrm{the}\:\mathrm{question} \\ $$$$\mathrm{in}\:\mathrm{an}\:\mathrm{ambiguous}\:\mathrm{way} \\ $$$$\mathrm{I}\:\mathrm{solve}\:\mathrm{it}\:\mathrm{in}\:\mathrm{the}\:\mathrm{case}\:\mathrm{log}_{\mathrm{3}} \left[\left(\mathrm{6}−\mathrm{x}\right)\sqrt{\mathrm{x}^{\mathrm{2}} +\mathrm{2x}+\mathrm{6}}\right]=\mathrm{x}…
Question Number 109806 by floor(10²Eta[1]) last updated on 25/Aug/20 $$\mathrm{a}\:\mathrm{handy}\:\mathrm{little}\:\mathrm{formula}\:\mathrm{to}\:\mathrm{remember} \\ $$$$\left.\mathrm{in}\:\mathrm{case}\:\mathrm{you}\:\mathrm{forget}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{3}\::\right) \\ $$$$ \\ $$$$\:\:\:^{\frac{\mathrm{2}}{\left(\frac{\mathrm{log}_{\mathrm{2}} \left(\mathrm{3}\right)}{\mathrm{2}}\right)}} \sqrt{\mathrm{2}^{\mathrm{4}} }=\mathrm{3} \\ $$ Terms of Service Privacy…