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Question Number 175023 by bubu last updated on 16/Aug/22 $$\underset{\boldsymbol{\mathrm{n}}=\mathrm{0}} {\overset{\infty} {\boldsymbol{\sum}}}\frac{\left(−\mathrm{1}\right)^{\boldsymbol{\mathrm{n}}} }{\mathrm{7}+\mathrm{6}\boldsymbol{\mathrm{n}}}\left[\boldsymbol{\psi}^{\left(\mathrm{0}\right)} \left(\frac{\mathrm{9}+\mathrm{6}\boldsymbol{\mathrm{n}}}{\mathrm{2}}\right)−\boldsymbol{\psi}^{\left(\mathrm{0}\right)} \left(\frac{\mathrm{7}+\mathrm{6}\boldsymbol{\mathrm{n}}}{\mathrm{2}}\right)\right] \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

A-large-lot-of-tires-contain-5-defectives-4-tires-are-to-be-chosen-for-a-car-Find-the-probability-that-you-find-a-2-defective-tires-before-4-good-ones-b-at-most-2-defective-tires-before-4-goo

Question Number 175011 by MathsFan last updated on 16/Aug/22 $$\mathrm{A}\:\mathrm{large}\:\mathrm{lot}\:\mathrm{of}\:\mathrm{tires}\:\mathrm{contain}\:\mathrm{5\%}\:\mathrm{defectives}. \\ $$$$\mathrm{4}\:\mathrm{tires}\:\mathrm{are}\:\mathrm{to}\:\mathrm{be}\:\mathrm{chosen}\:\mathrm{for}\:\mathrm{a}\:\mathrm{car}.\:\mathrm{Find} \\ $$$$\mathrm{the}\:\mathrm{probability}\:\mathrm{that}\:\mathrm{you}\:\mathrm{find} \\ $$$$\:\left(\mathrm{a}\right)\:\mathrm{2}\:\mathrm{defective}\:\mathrm{tires}\:\mathrm{before}\:\mathrm{4}\:\mathrm{good}\:\mathrm{ones} \\ $$$$\:\left(\mathrm{b}\right)\:\mathrm{at}\:\mathrm{most}\:\mathrm{2}\:\mathrm{defective}\:\mathrm{tires}\:\mathrm{before}\:\mathrm{4}\:\mathrm{good}\:\mathrm{ones}. \\ $$ Commented by mr W last…

Question-109469

Question Number 109469 by mathdave last updated on 24/Aug/20 Commented by Her_Majesty last updated on 24/Aug/20 $${why}\:{do}\:{you}\:{first}\:{post}\:{a}\:{question}\:{with}\:{its} \\ $$$${solution}\:{and}\:{next}\:{post}\:{the}\:{same}\:{question} \\ $$$${again}??? \\ $$ Commented by…

Question-109453

Question Number 109453 by mathdave last updated on 23/Aug/20 Answered by mathmax by abdo last updated on 23/Aug/20 $$\mathrm{I}\:=\int_{\mathrm{0}} ^{\mathrm{4}\pi} \mid\mathrm{cosx}\mid\:\mathrm{dx}\:\Rightarrow\:\mathrm{I}\:=_{\mathrm{x}\:=\mathrm{t}+\mathrm{2}\pi} \:\:\:\:\int_{−\mathrm{2}\pi} ^{\mathrm{2}\pi} \mid\mathrm{cost}\mid\:\mathrm{dt}\: \\…