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Question Number 109264 by mathdave last updated on 22/Aug/20 Answered by Her_Majesty last updated on 22/Aug/20 $${x}−\mathrm{1}={a}\wedge{x}+\mathrm{1}={b} \\ $$$${ln}^{\mathrm{2}} {ab}−{ln}^{\mathrm{2}} \frac{{a}}{{b}}=\left({lna}+{lnb}\right)^{\mathrm{2}} +\left({lna}−{lnb}\right)^{\mathrm{2}} = \\ $$$$={ln}^{\mathrm{2}}…

Question Number 43713 by Junaid555 last updated on 14/Sep/18 Commented by Cheyboy last updated on 14/Sep/18 $$\sqrt{\frac{\left(\mathrm{6}^{\mathrm{3}} \right)^{\mathrm{2}/\mathrm{3}} \left(\mathrm{5}^{\mathrm{2}} \right)^{\mathrm{1}/\mathrm{2}} }{\left(\mathrm{5}^{−\mathrm{2}} \right)^{−\mathrm{3}/\mathrm{2}} }\:}=\sqrt{\frac{\left(\mathrm{6}^{\mathrm{2}} \right)\left(\mathrm{5}\right)}{\left(\mathrm{5}^{\mathrm{3}} \right)}}…

Question Number 174775 by Best1 last updated on 10/Aug/22 Answered by Ar Brandon last updated on 10/Aug/22 $${p}+{q}=\mathrm{8}\:…\left({i}\right) \\ $$$${p}\left(\mathrm{3}^{\mathrm{2}} \right)+{q}+\mathrm{2}\left(\mathrm{2}\right)=\mathrm{52}\:\Rightarrow\mathrm{9}{p}+{q}=\mathrm{48}\:…\left({ii}\right) \\ $$$$\left({ii}\right)−\left({i}\right)\Rightarrow\mathrm{8}{p}=\mathrm{40}\:\Rightarrow{p}=\mathrm{5},\:{q}=\mathrm{3} \\ $$$$\Rightarrow{G}_{{n}}…

Question Number 174767 by Best1 last updated on 10/Aug/22 Answered by Ar Brandon last updated on 10/Aug/22 $$\mathrm{60}+\frac{\mathrm{1}}{\mathrm{3}}\left(\mathrm{60}+\mathrm{60}\right)+\frac{\mathrm{1}}{\mathrm{9}}\left(\mathrm{60}+\mathrm{60}\right)+\frac{\mathrm{1}}{\mathrm{27}}\left(\mathrm{60}+\mathrm{60}\right)+\frac{\mathrm{1}}{\mathrm{81}}\left(\mathrm{60}+\mathrm{60}\right) \\ $$$$=\mathrm{60}+\frac{\mathrm{120}}{\mathrm{3}}+\frac{\mathrm{120}}{\mathrm{9}}+\frac{\mathrm{120}}{\mathrm{27}}+\frac{\mathrm{120}}{\mathrm{81}} \\ $$$$=\mathrm{119}.\mathrm{2592593}\:\mathrm{m} \\ $$ Terms…

Question Number 109178 by Algoritm last updated on 21/Aug/20 Commented by Algoritm last updated on 21/Aug/20 $$\mathrm{mr}\:\mathrm{W} \\ $$ Answered by Dwaipayan Shikari last updated…